Problem 78
Question
Find the inverse of each function. Is the inverse a function? \(f(x)=\frac{2}{3} x-3\)
Step-by-Step Solution
Verified Answer
The inverse of the function \(f(x)=\frac{2}{3}x-3\) is \(f^{-1}(x)=\frac{3x+9}{2}\), and this is indeed a function.
1Step 1: Find the Inverse Function
To find the inverse of the function \(f(x)=\frac{2}{3} x-3\), a procedure can be followed:1. Replace the \(f(x)\) with \(y\) to get \(y=\frac{2}{3} x-3\).2. Swap \(x\) and \(y\) to get \(x=\frac{2}{3} y-3\).3. Solve for \(y\) to find the inverse function.
2Step 2: Solve for y
The equation from the first step is now solved for \(y\).1. Get rid of any fractions first: \(3x=2y-9\).2. Isolate \(y\), by adding 9 to both sides and then dividing by 2: \(y= \frac{3x+9}{2}\).
3Step 3: Check if Inverse is a function
Now, we check whether this inverse is a function using the horizontal line test. In this case, any horizontal line would only cross the inverse function once, confirming that it is indeed a function. So, the inverse of the function f, denoted by \(f^{-1}(x)\), is indeed a function.
Key Concepts
Function InversesHorizontal Line TestAlgebraic Manipulation
Function Inverses
Understanding function inverses is crucial in mathematics. The concept involves swapping the input and output of a function. For a function \(f(x)\), its inverse \(f^{-1}(x)\) is found by reversing the process of \(f(x)\). In other words:
- The input of the original function becomes the output of the inverse function.
- The output of the original function becomes the input of the inverse function.
Horizontal Line Test
The horizontal line test is a simple way to determine if a function's inverse is also a function. A function is one-to-one (bijective) if it passes this test, meaning it has an inverse that is also a function. Here’s how it works:Imagine drawing horizontal lines across the graph of the function. If any horizontal line intersects the graph more than once, the function fails the test and does not have an inverse that is a function.In our example, the function \(f(x)=\frac{2}{3} x-3\) is a linear function, which always passes the horizontal line test. Any horizontal line drawn would intersect this linear graph only once, confirming that its inverse is indeed a function.This method ensures that the inverse relationship properly swaps the input and output, maintaining a one-to-one relationship.
Algebraic Manipulation
Algebraic manipulation involves rearranging equations to solve for a specific variable. To find an inverse function, this skill is essential. Let's break down the process using the problem \(f(x)=\frac{2}{3} x-3\):
- Begin by expressing the function in terms of \(y\): \(y=\frac{2}{3}x-3\).
- Swap variables: \(x=\frac{2}{3}y-3\).
- Clear the fraction by multiplying through by 3: \(3x=2y-9\).
- Isolate \(y\): Add 9 to both sides, giving \(3x+9=2y\).
- Divide by 2 to solve for \(y\): \(y=\frac{3x+9}{2}\).
Other exercises in this chapter
Problem 77
Expand each binomial. $$ (3 x-5)^{6} $$
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Writing Explain why \((-64)^{\frac{1}{3}}=-64^{\frac{1}{3}}\) and \((-64)^{\frac{1}{2}} \neq-64^{\frac{1}{2}}\).
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Let \(f(x)=4 x, g(x)=\frac{1}{2} x+7,\) and \(h(x)=|-2 x+4| .\) Simplify each function. $$ (h \circ(g \circ f))(x) $$
View solution Problem 78
Evaluate each expression. \(_{8} P_{4}\)
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