Problem 78
Question
Consider the following reaction: $$ \mathrm{A}_{2}+\mathrm{B}_{2} \longrightarrow 2 \mathrm{AB} \quad \Delta E=-285 \mathrm{kJ} $$ The bond energy for \(A_{2}\) is one-half the amount of the AB bond energy. The bond energy of \(\mathbf{B}_{2}=432 \mathrm{kJ} / \mathrm{mol} .\) What is the bond energy of \(\mathrm{A}_{2} ?\)
Step-by-Step Solution
Verified Answer
The bond energy of A₂ is 49 kJ/mol.
1Step 1: Write down the given information
Here are the information given in the problem:
- A₂ + B₂ ⟶ 2AB, ∆E = -285 kJ
- Bond energy of B₂ = 432 kJ/mol
- Bond energy of A₂ = (1/2) × Bond energy of AB
2Step 2: Calculate the total bond energy of the products
Assuming that the bond energy of AB is x kJ/mol, the total bond energy of products, considering the stoichiometric coefficients, will be 2x kJ.
3Step 3: Calculate the total bond energy of the reactants
The bond energy of A₂ is (1/2) x, and the bond energy of B₂ is 432 kJ/mol. Therefore, the total bond energy of reactants is (1/2)x + 432 kJ.
4Step 4: Apply Hess's Law
Hess's law states that the energy change for the reaction (∆E) is equal to the total bond energy of products minus the total bond energy of reactants. In this case, we have:
-285 kJ = (2x kJ) - [(1/2)x + 432 kJ]
5Step 5: Solve for x (bond energy of AB)
Rearrange the equation to solve for x:
-285 kJ + 432 kJ = (2x kJ) - (1/2)x
147 kJ = (3/2)x
x = 98 kJ/mol
The bond energy of the AB molecule is 98 kJ/mol.
6Step 6: Find the bond energy of A₂
Using the relationship given, we can now find the bond energy of A₂:
Bond energy of A₂ = (1/2) × Bond energy of AB
Bond energy of A₂ = (1/2) × 98 kJ/mol
Bond energy of A₂ = 49 kJ/mol
So, the bond energy of A₂ is 49 kJ/mol.
Key Concepts
Hess's LawEnthalpy ChangeChemical Reaction Energetics
Hess's Law
Hess's Law is a fundamental principle in chemistry that helps us understand energy changes in chemical reactions. It states that the total enthalpy change for a reaction is the same, regardless of the pathway taken. In simpler terms, it doesn't matter how you get from reactants to products; the energy change is constant.
In the context of our reaction, Hess's Law allows us to simplify the calculation of bond energies. We can separate the reaction into the breaking and forming of bonds, which lets us calculate the overall reaction energy. This approach is very helpful because direct measurement of bond energies isn't always feasible.
By applying Hess's Law, we can compute the required bond energies by using known bond energies and reacting substances. This helps us unravel the total energy exchanges involved in the process, providing insight into reaction energetics.
In the context of our reaction, Hess's Law allows us to simplify the calculation of bond energies. We can separate the reaction into the breaking and forming of bonds, which lets us calculate the overall reaction energy. This approach is very helpful because direct measurement of bond energies isn't always feasible.
By applying Hess's Law, we can compute the required bond energies by using known bond energies and reacting substances. This helps us unravel the total energy exchanges involved in the process, providing insight into reaction energetics.
Enthalpy Change
Enthalpy change, often represented as \( \Delta H \), is the amount of heat absorbed or released during a chemical reaction. It indicates whether a reaction is endothermic or exothermic.
By carefully analyzing the enthalpy change, we can understand the energy dynamics at play and predict how the reaction's energetics progress. This concept serves as a cornerstone for understanding not only this particular reaction but many others in energetics studies.
- If \( \Delta H \) is negative, the reaction releases heat (exothermic).
- If \( \Delta H \) is positive, the reaction absorbs heat (endothermic).
By carefully analyzing the enthalpy change, we can understand the energy dynamics at play and predict how the reaction's energetics progress. This concept serves as a cornerstone for understanding not only this particular reaction but many others in energetics studies.
Chemical Reaction Energetics
Chemical reaction energetics focuses on understanding the energy changes that occur during a chemical reaction. Energetics involves examining how energy is conserved, transferred, and transformed in the course of a reaction.
The key to comprehending reaction energetics starts with the bonds themselves. Energy is needed to break chemical bonds (endothermic) and is released when new bonds form (exothermic). Knowing the bond energies enables us to calculate the net energy change in a reaction.
Understanding these energetic principles is essential for predicting reaction viability, selecting suitable reaction conditions, and designing effective industrial processes.
The key to comprehending reaction energetics starts with the bonds themselves. Energy is needed to break chemical bonds (endothermic) and is released when new bonds form (exothermic). Knowing the bond energies enables us to calculate the net energy change in a reaction.
- Calculate individual bond energies.
- Assess how much energy is absorbed/released.
- Determine whether the overall reaction is endothermic or exothermic.
Understanding these energetic principles is essential for predicting reaction viability, selecting suitable reaction conditions, and designing effective industrial processes.
Other exercises in this chapter
Problem 68
The lattice energies of \(\mathrm{FeCl}_{3}, \mathrm{FeCl}_{2},\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) are (in no particular order) \(-2631,-5359,\) and -14,7
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The major industrial source of hydrogen gas is by the following reaction: $$ \mathrm{CH}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}(g)+3 \m
View solution Problem 79
Write Lewis structures that obey the octet rule (duet rule for H) for each of the following molecules. Carbon is the central atom in \(\mathrm{CH}_{4}\), nitrog
View solution Problem 80
Write Lewis structures that obey the octet rule (duet rule for H) for each of the following molecules. a. \(\mathrm{H}_{2} \mathrm{CO}\) b. \(\mathrm{CO}_{2}\)
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