Problem 78
Question
Assume that all variables represent positive real numbers. $$ \sqrt{\frac{y^{10}}{9 x^{6}}} $$
Step-by-Step Solution
Verified Answer
\( \frac{y^{5}}{3x^{3}} \)
1Step 1: Understanding the Square Root
The expression inside the square root is \( \frac{y^{10}}{9x^{6}} \). This means you need to find the square root of both the numerator \( y^{10} \) and the denominator \( 9x^{6} \).
2Step 2: Simplifying the Numerator
Take the square root of the numerator \( y^{10} \). As per the properties of exponents, the square root is equivalent to raising the exponent to \( \frac{1}{2} \). So, \( \sqrt{y^{10}} = y^{10 \times \frac{1}{2}} = y^{5} \).
3Step 3: Simplifying the Denominator
Take the square root of the denominator \( 9x^{6} \). The square root of 9 is 3, and for \( x^{6} \), it is \( x^{6 \times \frac{1}{2}} = x^{3} \). Therefore, \( \sqrt{9x^{6}} = 3x^{3} \).
4Step 4: Combining Results
Now combine the results from the numerator and the denominator: \( \frac{y^{5}}{3x^{3}} \). Thus, the expression becomes \( \frac{y^{5}}{3x^{3}} \).
Key Concepts
Square RootProperties of ExponentsSimplifying Expressions
Square Root
The square root is a concept that refers to finding a number which, when multiplied by itself, gives the original number. In mathematical terms, for any non-negative number \( a \), the square root of \( a \) is denoted as \( \sqrt{a} \). The square root operation is pivotal in simplifying expressions, especially when dealing with exponential terms.
When you see a square root symbol like \( \sqrt{\frac{y^{10}}{9x^{6}}} \), your goal is to simplify both the numerator \( y^{10} \) and the denominator \( 9x^{6} \) separately to make the expression less complex.
When you see a square root symbol like \( \sqrt{\frac{y^{10}}{9x^{6}}} \), your goal is to simplify both the numerator \( y^{10} \) and the denominator \( 9x^{6} \) separately to make the expression less complex.
- For any expression \( \sqrt{a^{b}} \), it can also be expressed with exponents as \( a^{b/2} \).
- If \( a = b \times b \), then the square root of \( a \) is \( b \).
Properties of Exponents
Exponents are shorthand for repeated multiplication, and they have several key properties that help simplify expressions, especially when they are part of square roots. Knowing these properties can make it much easier to handle algebraic problems:
- Product of Powers: \( a^{m} \times a^{n} = a^{m+n} \) - When multiplying with the same base, add the exponents.
- Power to a Power: \( (a^{m})^{n} = a^{m \times n} \) - Multiply the exponents when raising a power to another power.
- Quotient of Powers: \( \frac{a^{m}}{a^{n}} = a^{m-n} \) - When dividing with the same base, subtract the exponents.
Simplifying Expressions
Simplifying expressions is the process of reducing an algebraic expression to its simplest form. This typically involves removing any unnecessary components, such as constants or like terms, to make the expression as straightforward as possible.
In our exercise, the expression \( \sqrt{\frac{y^{10}}{9x^{6}}} \) was simplified to \( \frac{y^{5}}{3x^{3}} \) by:
In our exercise, the expression \( \sqrt{\frac{y^{10}}{9x^{6}}} \) was simplified to \( \frac{y^{5}}{3x^{3}} \) by:
- Applying the square root to each part separately—both to the numerator and denominator.
- Using properties of exponents to rewrite \( y^{10} \) as \( y^{5} \) and \( x^{6} \) as \( x^{3} \) after taking their square roots.
- Recognizing that \( \sqrt{9} \) is 3, a basic fact about numbers.
Other exercises in this chapter
Problem 78
Solve each equation. \(x^{3}=x\)
View solution Problem 78
In your own words, explain why you think \(s\) in Heron's formula is called the semiperimeter.
View solution Problem 78
Use rational expressions to write as a single radical expression. $$ \sqrt[6]{y} \cdot \sqrt[3]{y} \cdot \sqrt[5]{y^{2}} $$
View solution Problem 78
Find the distance between each pair of points. Give an exact distance and a three-decimal-place approximation. (2,3) and (14,8)
View solution