Problem 78
Question
Add or subtract terms whenever possible. $$ 3 \sqrt[3]{24}+\sqrt[3]{81} $$
Step-by-Step Solution
Verified Answer
The simplified form of \(3\sqrt[3]{24}+\sqrt[3]{81}\) is \(9\sqrt[3]{3}\)
1Step 1: Simplify 3 \sqrt[3]{24}
First, let's simplify \(3 \sqrt[3]{24}\). We recognize that 24 can be factored into \(2^3\) and 3. Therefore, we rewrite the term as \(3 \sqrt[3]{2^3 \cdot 3}\). The cube root of \(2^3\) is 2, so the term simplifies to \(6\sqrt[3]{3}\).
2Step 2: Simplify \(\sqrt[3]{81}\)
Next, let's simplify \(\sqrt[3]{81}\). By observing, we find that 81 can be factored into \(3^4\). Therefore, we rewrite the term as \(\sqrt[3]{(3^3) \cdot 3}\). The cube root of \(3^3\) is 3, so the term simplifies to \(3\sqrt[3]{3}\).
3Step 3: Add Simplified Terms
Now that both terms are simplified, they can be added together because they have the same radical. Therefore, the expression is simplified to \((6\sqrt[3]{3}) + (3\sqrt[3]{3}) = 9\sqrt[3]{3}\).
Key Concepts
Simplifying radicalsFactoringAdding like termsCube root simplification
Simplifying radicals
When dealing with the expression \(3 \sqrt[3]{24} + \sqrt[3]{81}\), one must simplify the cube roots. This process involves breaking down numbers under the radical sign into their prime factors.
Particularly for cube roots, we need to identify factors that are perfect cubes. For example, in the number 24, which can be expressed as \(2^3 \times 3\), the \(2^3\) is a perfect cube that can be taken out of the radical, simplifying \(\sqrt[3]{24}\) to \(2\sqrt[3]{3}\).
Simplifying radicals helps in handling the terms easily, especially when they need to be added or subtracted.
Particularly for cube roots, we need to identify factors that are perfect cubes. For example, in the number 24, which can be expressed as \(2^3 \times 3\), the \(2^3\) is a perfect cube that can be taken out of the radical, simplifying \(\sqrt[3]{24}\) to \(2\sqrt[3]{3}\).
Simplifying radicals helps in handling the terms easily, especially when they need to be added or subtracted.
Factoring
Factoring involves breaking down a number into its prime factors. This is a vital step in simplifying cube roots.
For example, to factor 24, we identify it as \(2^3 \times 3\). This allows us to pull \(2^3\) out of the cube root.
Similarly, when factoring 81, we find it to be \(3^4\), which can be expressed as \(3^3 \times 3\), helping in simplifying \(\sqrt[3]{81}\). Factoring helps reveal hidden perfect cubes and is a key step in simplifying cube root expressions.
For example, to factor 24, we identify it as \(2^3 \times 3\). This allows us to pull \(2^3\) out of the cube root.
Similarly, when factoring 81, we find it to be \(3^4\), which can be expressed as \(3^3 \times 3\), helping in simplifying \(\sqrt[3]{81}\). Factoring helps reveal hidden perfect cubes and is a key step in simplifying cube root expressions.
Adding like terms
Once cube roots are simplified, like terms can be added together. Terms are considered 'like' if they have the same radical component.
In our example, both simplified terms are \(6\sqrt[3]{3}\) and \(3\sqrt[3]{3}\), sharing \(\sqrt[3]{3}\) under the cube root symbol.
Simply combine the coefficients by addition: \(6 + 3\), leading to the simplification \(9\sqrt[3]{3}\).
Adding like terms allows expressions to be condensed into simpler forms for easier handling.
In our example, both simplified terms are \(6\sqrt[3]{3}\) and \(3\sqrt[3]{3}\), sharing \(\sqrt[3]{3}\) under the cube root symbol.
Simply combine the coefficients by addition: \(6 + 3\), leading to the simplification \(9\sqrt[3]{3}\).
Adding like terms allows expressions to be condensed into simpler forms for easier handling.
Cube root simplification
Cube root simplification involves reducing numbers under the cube root sign by extracting any perfect cubes.
For \(\sqrt[3]{24}\), recognize \(2^3\) as a perfect cube, which simplifies \(\sqrt[3]{24}\) to \(2\sqrt[3]{3}\). Similarly, for \(\sqrt[3]{81}\), we take \(3^3\) outside the radical, resulting in \(3\sqrt[3]{3}\).
Simplification helps in performing operations like addition or subtraction, providing a clearer, simpler result.
For \(\sqrt[3]{24}\), recognize \(2^3\) as a perfect cube, which simplifies \(\sqrt[3]{24}\) to \(2\sqrt[3]{3}\). Similarly, for \(\sqrt[3]{81}\), we take \(3^3\) outside the radical, resulting in \(3\sqrt[3]{3}\).
Simplification helps in performing operations like addition or subtraction, providing a clearer, simpler result.
Other exercises in this chapter
Problem 78
perform the indicated operations. Simplify the result, if possible. $$ \frac{y^{-1}-(y+2)^{-1}}{2} $$
View solution Problem 78
In Exercises 67–82, find each product. $$ (x+y)\left(x^{2}-x y+y^{2}\right) $$
View solution Problem 78
Write each number in scientific notation. $$ 64,000 $$
View solution Problem 78
State the name of the property illustrated. $$6 \cdot(2 \cdot 3)=6 \cdot(3 \cdot 2)$$
View solution