Problem 77
Question
Write a quadratic equation that has two solutions, 6 and -1 . Leave the polynomial in the equation in factored form.
Step-by-Step Solution
Verified Answer
The equation is
(x - 6)(x + 1) = 0
.
1Step 1: Understand Roots of the Equation
The roots of the quadratic equation are given as 6 and -1. Knowing that the solutions are the values for which the equation equals zero (
x = 6
and
x = -1
), we will construct the equation from these solutions.
2Step 2: Express Roots Using Factors
The factored form of a quadratic equation with roots 6 and -1 can be expressed as
(x - 6)
and
(x + 1)
. These factors represent the points where the equation equals zero.
3Step 3: Write the Equation in Factored Form
Write the quadratic equation using the factors from Step 2:
(x - 6)(x + 1) = 0
. This is the quadratic equation in its factored form.
Key Concepts
Quadratic EquationsRoots of EquationsFactored Form of Quadratics
Quadratic Equations
Quadratic equations are fundamental in algebra and are characterized by their polynomial form:
They are essential when dealing with areas, projectile motions, and optimizing specific conditions in real-world problems. Studying their general and nature specific forms helps solve numerous equations in mathematical representations.
In this section, we are especially interested in expressing them in factored form so as to easily identify the roots, which are the solutions to these equations.
- General form: \( ax^2 + bx + c = 0 \)
- Degree: A quadratic equation has a degree of 2, which means the highest power of the variable \( x \) is 2.
They are essential when dealing with areas, projectile motions, and optimizing specific conditions in real-world problems. Studying their general and nature specific forms helps solve numerous equations in mathematical representations.
In this section, we are especially interested in expressing them in factored form so as to easily identify the roots, which are the solutions to these equations.
Roots of Equations
The roots of an equation, often referred to as solutions or zeros, are values of \( x \) that satisfy the equation \( ax^2 + bx + c = 0 \).
These solutions are the values where the quadratic equation equals zero.
Understanding roots is crucial for factoring and solving quadratic equations because they directly determine the form of the equation.
These solutions are the values where the quadratic equation equals zero.
- For a quadratic equation, there can be a maximum of two roots.
- Root terms come into play with this equation form as these determine the direction and position where the parabola intersects the x-axis in its graphical representation.
- \( x = 6 \)
- \( x = -1 \)
Understanding roots is crucial for factoring and solving quadratic equations because they directly determine the form of the equation.
Factored Form of Quadratics
The factored form of a quadratic equation is a powerful way to express such equations because it directly facilitates finding the roots.
This allows us to write the factored form as \((x - 6)(x + 1) = 0\).
enabling easier analysis and understanding of the equation's behavior.
- Factored form: \((x - p)(x - q) = 0\), where \(p\) and \(q\) are the roots of the equation.
- This reveals immediate x-values where the graph of the quadratic will cross the x-axis.
This allows us to write the factored form as \((x - 6)(x + 1) = 0\).
- This expression clearly tells us that replacing \(x\) with 6 or -1 will result in zero.
- Each factor goes to zero at its respective root, simplifying the process of solving the quadratic equation.
enabling easier analysis and understanding of the equation's behavior.
Other exercises in this chapter
Problem 77
Factor out the GCF from each polynomial. Then factor by grouping. $$ 12 x^{2} y-42 x^{2}-4 y+14 $$
View solution Problem 77
Write a polynomial that factors as \((x-3)(x+8)\).
View solution Problem 78
Factor. $$ x^{2} y^{9}+x^{2} y^{3} $$
View solution Problem 78
Factor out the GCF from each polynomial. Then factor by grouping. $$ 90+15 y^{2}-18 x-3 x y^{2} $$
View solution