Problem 77
Question
Use the properties of logarithms to rewrite each expression as a single logarithm with coefficient 1. Assume that all variables represent positive real numbers. $$\log _{a} x+\log _{a} y-\log _{a} m$$
Step-by-Step Solution
Verified Answer
\( \log_a \left( \frac{xy}{m} \right) \)
1Step 1: Apply the Product Rule for Logarithms
The product rule of logarithms states that \( \log_b (mn) = \log_b m + \log_b n \). Apply this to combine the first two terms: \( \log_a x + \log_a y = \log_a (xy) \).
2Step 2: Apply the Quotient Rule for Logarithms
The quotient rule for logarithms states that \( \log_b \left( \frac{m}{n} \right) = \log_b m - \log_b n \). Use this to combine the result from Step 1 with the third term: \( \log_a (xy) - \log_a m = \log_a \left( \frac{xy}{m} \right) \).
3Step 3: Express as a Single Logarithm
The final expression is \( \log_a \left( \frac{xy}{m} \right) \). This is a single logarithm with a coefficient of 1.
Key Concepts
Product RuleQuotient RuleProperties of Logarithms
Product Rule
The product rule for logarithms is a very handy tool when you need to add logarithms together. If you have the expression \( \log_b m + \log_b n \), you can combine these into a single term: \( \log_b (mn) \). This means multiplying the arguments of the logs inside one log because logarithms are essentially exponents, and this rule reflects the property of exponents where adding them means multiplying the base numbers.
This rule comes into play when you're dealing with problems that require you to simplify or solve logarithmic expressions, much like in our example where \( \log_a x + \log_a y \) becomes \( \log_a (xy) \).
This rule comes into play when you're dealing with problems that require you to simplify or solve logarithmic expressions, much like in our example where \( \log_a x + \log_a y \) becomes \( \log_a (xy) \).
- Remember to use the same base for the logs you're adding.
- This rule primarily helps in reducing the complexity of the expression by combining terms.
Quotient Rule
The quotient rule for logarithms is another useful tool, especially when you deal with subtraction of logarithm expressions. This rule states that if you subtract logarithms with the same base, like \( \log_b m - \log_b n \), you can rewrite this as \( \log_b \left( \frac{m}{n} \right) \).
Just as dividing exponents translates into subtracting them, the quotient rule reflects this in logarithmic terms. When you have an expression like \( \log_a (xy) - \log_a m \), you're subtracting a log and can simplify it as \( \log_a \left( \frac{xy}{m} \right) \).
Just as dividing exponents translates into subtracting them, the quotient rule reflects this in logarithmic terms. When you have an expression like \( \log_a (xy) - \log_a m \), you're subtracting a log and can simplify it as \( \log_a \left( \frac{xy}{m} \right) \).
- Ensure the logarithms have the same base before applying this rule.
- This method helps condense multiple logs into a single log expression.
Properties of Logarithms
Understanding the properties of logarithms is key to simplifying complex expressions involving logs. The product and quotient rules are just two of these properties. They greatly assist in combining and reducing expressions, making calculations manageable and straightforward. Here are a few broad properties:
- The power rule, which states \( \log_b (m^n) = n\log_b m \), helps when a term is raised to a power.
- Change of base property, allowing the change of bases for ease: \( \log_b m = \frac{\log_k m}{\log_k b} \).
- The log of a base to itself is always one, \( \log_b b = 1 \), providing a useful simplification.
Other exercises in this chapter
Problem 76
$$\text { Solve each formula for the indicated variable.}$$ $$m=6-2.5 \log \left(\frac{M}{M_{0}}\right), \text { for } M$$
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Solve each problem. Atmospheric Pressure The atmospheric pressure (in millibars) at a given altitude (in meters) is shown in the table. $$\begin{array}{c|c|c|c}
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The given function \(f\) is one-to-one. Find \(f^{-1}(x)\). $$f(x)=\frac{3-x}{2 x+1}$$
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$$\text { Solve each formula for the indicated variable.}$$ $$\log A=\log B-C \log x, \text { for } A$$
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