Problem 77
Question
Solve each equation. $$x+\sqrt{x}-2=0$$
Step-by-Step Solution
Verified Answer
The solution is \(x = 1\).
1Step 1: Isolate the square root
Start by moving the constant term over to the other side of the equation to isolate the square root term: \( x + \sqrt{x} = 2 \). Subtract \(x\) from both sides to get \( \sqrt{x} = 2 - x \).
2Step 2: Square both sides of the equation
Square both sides of the equation to eliminate the square root: \( (\sqrt{x})^2 = (2 - x)^2 \). This simplifies to \( x = 4 - 4x + x^2 \).
3Step 3: Rearrange the equation
Rearrange the equation to form a quadratic equation: \( x^2 - 5x + 4 = 0 \).
4Step 4: Factor the quadratic equation
Find two numbers that multiply to 4 and add to -5. These numbers are -1 and -4. So, factor the quadratic equation: \( (x-1)(x-4) = 0 \).
5Step 5: Solve for x
Set each factor equal to zero and solve for \( x \): \( x - 1 = 0 \) gives \( x = 1 \), and \( x - 4 = 0 \) gives \( x = 4 \).
6Step 6: Verify solutions
Substitute \( x = 1 \) and \( x = 4 \) back into the original equation. For \( x = 1 \), \( 1 + \sqrt{1} - 2 = 0 \) holds true. For \( x = 4 \), \( 4 + \sqrt{4} - 2 = 4 eq 0 \). Only \( x = 1 \) satisfies the original equation.
Key Concepts
Solving EquationsSquare RootsFactoringVerification of Solutions
Solving Equations
In mathematics, solving equations involves finding the value of the unknown variable that makes the equation true. For the equation \(x + \sqrt{x} - 2 = 0\), our goal is to determine the value of \(x\) such that the left-hand side equals zero. To do this, we start by isolating terms that contain the square root.
- Initially, rearrange terms to get \(x + \sqrt{x} = 2\).
- Further, subtract \(x\) to isolate \(\sqrt{x}\): \(\sqrt{x} = 2 - x\).
Square Roots
Understanding square roots is crucial when solving equations that include them. A square root is a number which, when multiplied by itself, gives the original number. For instance, \(\sqrt{x}\) represents a number that squares to \(x\). In our equation, the square root appears as \(\sqrt{x}\).
To eliminate the square root from the equation \(\sqrt{x} = 2 - x\), we square both sides:
To eliminate the square root from the equation \(\sqrt{x} = 2 - x\), we square both sides:
- Squaring the left side, \( (\sqrt{x})^2 = x\).
- Squaring the right side, \((2 - x)^2 = 4 - 4x + x^2\).
Factoring
Factoring is a key technique for solving quadratic equations. Once an equation is in the form \(ax^2 + bx + c = 0\), we can factor it to find the roots. In our example, the quadratic equation is \(x^2 - 5x + 4 = 0\). The goal is to express it as a product of two binomials.
- Look for two numbers whose product is the constant term (4) and whose sum is the linear coefficient (-5).
- In this case, the numbers -1 and -4 fit these conditions.
Verification of Solutions
Verification is an essential step in solving equations as it confirms the validity of the solutions. After finding possible solutions from the factored form \((x - 1)(x - 4) = 0\), we have \(x = 1\) and \(x = 4\).
To verify, substitute each back into the original equation and check if they satisfy it:
To verify, substitute each back into the original equation and check if they satisfy it:
- For \(x = 1\): Substitute in the equation \(1 + \sqrt{1} - 2 = 0\), which holds true.
- For \(x = 4\): Substitute in the equation \(4 + \sqrt{4} - 2 = 4eq 0\), which does not satisfy the equation.
Other exercises in this chapter
Problem 76
\(a\) and \(b\) represent the lengths of the legs of a right triangle, and \(c\) represents the length of the hypotenuse. Express answers in simplest radical fo
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Find each of the products and express the answers in the standard form of a complex number. $$(4+5 i)^{2}$$
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Solve each equation. $$x^{\frac{2}{3}}+x^{\frac{1}{3}}-6=0$$
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