Problem 77
Question
Solution of \(2^{x}+2^{|x|} \geq 2 \sqrt{2}\) is (A) \(\left(-\infty, \log _{2}(\sqrt{2}+1)\right.\) (B) \((0,8)\) (C) \(\left(\frac{1}{2}, \log _{2}(\sqrt{2}-1)\right)\) (D) \(\left(-\infty, \log _{2}(\sqrt{2}-1)\right] \cup\left[\frac{1}{2}, \infty\right)\)
Step-by-Step Solution
Verified Answer
The correct solution is (D): \((-\infty, \log_2(\sqrt{2} - 1)] \cup [1/2, \infty)\).
1Step 1: Understand the Problem
We need to find the values of \(x\) that satisfy the inequality \(2^{x} + 2^{|x|} \geq 2\sqrt{2}\). This involves understanding how both terms vary with \(x\) by evaluating the expression in different cases based on the value of \(x\).
2Step 2: Consider Case 1: \(x \geq 0\)
When \(x \geq 0\), \(|x| = x\), so the inequality becomes \(2^x + 2^x \geq 2\sqrt{2}\), or \(2 \cdot 2^x \geq 2\sqrt{2}\). Simplifying, we get \(2^{x} \geq \sqrt{2}\) which implies \(2^{x} \geq 2^{1/2}\). Therefore, \(x \geq 1/2\).
3Step 3: Consider Case 2: \(x < 0\)
When \(x < 0\), \(|x| = -x\). Thus, the inequality becomes \(2^{x} + 2^{-x} \geq 2\sqrt{2}\). To solve it, set \(y = 2^x\), then the inequality is \(y + \frac{1}{y} \geq 2\sqrt{2}\). Testing with critical points around symmetric geometrical points derived from AM-GM inequality and specific values such as \(y = 1\), we find that the inequality holds for \( y \leq \sqrt{2} - 1 \), which translates back to \(x \leq \log_2(\sqrt{2} - 1)\).
4Step 4: Combine Results
From Case 1, we have \(x \geq 1/2\). From Case 2, we determined \(x \leq \log_2(\sqrt{2} - 1)\). Combine these solutions to find the intervals where the original inequality holds.
5Step 5: Conclusion
The combined solution is \(x \leq \log_2(\sqrt{2} - 1)\) or \(x \geq 1/2\), which corresponds to choice (D): \((-\infty, \log_2(\sqrt{2} - 1)] \cup [1/2, \infty)\).
Key Concepts
Inequality SolvingExponential FunctionsAbsolute Value
Inequality Solving
Inequalities are mathematical expressions involving symbols like ">", "<", ">=", or "<=" that describe a range of values rather than a single value. Understanding inequalities is crucial in solving problems where multiple solutions can exist. Let's break down how to solve an inequality step by step.
First, always start by simplifying both sides of the inequality if possible. Look for like terms or common factors. This is similar to simplifying equations.
After simplifying, determine the conditions under which the inequality holds true. It may help to split the problem into different cases. In the given example, the problem involves splitting into separate cases where the absolute value term changes behavior based on whether the variable inside is negative or non-negative.
First, always start by simplifying both sides of the inequality if possible. Look for like terms or common factors. This is similar to simplifying equations.
After simplifying, determine the conditions under which the inequality holds true. It may help to split the problem into different cases. In the given example, the problem involves splitting into separate cases where the absolute value term changes behavior based on whether the variable inside is negative or non-negative.
- Case Analysis: Consider scenarios such as when the variable is positive or negative.
- Comparison to Constants: Rearrange the inequality to directly compare your expression to known numbers or constant expressions.
Exponential Functions
Exponential functions are a type of mathematical function where a constant base is raised to a variable exponent. These functions can grow very quickly and are represented by expressions such as \(2^x\). Understanding exponential functions is crucial when working with inequalities involving terms like \(2^x\).
Here are some key properties of exponential functions that are helpful while solving inequalities:
In our exercise, solving \(2^x \geq \, \sqrt{2}\) turned into assessing when\(2^x\) meets or exceeds a particular value, here \(2^{1/2}\), using knowledge of exponential growth.
Here are some key properties of exponential functions that are helpful while solving inequalities:
- Base Greater Than 1: If the base of the exponential is greater than 1, the function will increase as the exponent increases.
- Equality and Inequality: Use the property that if \(a^b = a^c\), then \(b = c\), provided \(a > 0\) and \(a eq 1\). This helps in transforming inequalities.
In our exercise, solving \(2^x \geq \, \sqrt{2}\) turned into assessing when\(2^x\) meets or exceeds a particular value, here \(2^{1/2}\), using knowledge of exponential growth.
Absolute Value
Absolute value gives the non-negative magnitude of a number, effectively ignoring its sign. In inequalities, absolute value impacts how you interpret and solve for variables. The notation \(|x|\) implies a piecewise function: \(x\) when \(x \geq 0\) and \(-x\) when \(x < 0\).
To solve inequalities with absolute values, consider separating them into different cases:
As seen in the original exercise, different scenarios based on \(x\) values—positive or negative—were analyzed separately. This piecewise approach simplifies understanding how \(|x|\) affects the rest of the equation.
To solve inequalities with absolute values, consider separating them into different cases:
- Non-negative Values: Consider the direct form where the absolute value can be removed without altering the sign.
- Negative Values: Formulate the inequality assuming the value inside the absolute sign is negative, necessitating a change in the sign.
As seen in the original exercise, different scenarios based on \(x\) values—positive or negative—were analyzed separately. This piecewise approach simplifies understanding how \(|x|\) affects the rest of the equation.
Other exercises in this chapter
Problem 75
The solution set of \((x)^{2}+(x+1)^{2}=25\), where \((x)\) is the least integer greater than or equal to \(x\), is (A) \((2,4)\) (B) \((-5,4] \cup(2,3]\) (C) \
View solution Problem 76
Let \(S\) denote the set of all values of \(S\) for which the equation \(2 x^{2}-2(2 a+1) x+a(a+1)=0\) has one root less than \(a\) and other root greater than
View solution Problem 78
If \(f(x)=x^{2}+2 b x+2 c^{2}\) and \(g(x)=-x^{2}-2 c x+b^{2}\) such that min. \(f(x)>\max . g(x)\), then the relation between \(b\) and \(c\) is (A) \(|c||b| \
View solution Problem 79
If the roots of the equation \(x^{2}-2 a x+a^{2}+a-3=0\) are real less than 3 , then: (A) \(a4\)
View solution