Problem 77
Question
Simplify each expression. \(\frac{k+3}{5 k \ell} \cdot \frac{10 k \ell}{k+3}\)
Step-by-Step Solution
Verified Answer
The simplified expression is 2.
1Step 1: Identify the expressions to multiply
We have two fractions: \( \frac{k+3}{5k\ell} \) and \( \frac{10k\ell}{k+3} \). We need to multiply these fractions together.
2Step 2: Multiply the numerators
The numerators of the fractions are \( (k+3) \) and \( 10k\ell \). Multiply these together: \((k+3) \times 10k\ell = 10k\ell(k+3)\).
3Step 3: Multiply the denominators
The denominators of the fractions are \( 5k\ell \) and \( (k+3) \). Multiply these: \(5k\ell \times (k+3) = 5k\ell(k+3)\).
4Step 4: Simplify the expression
The product of the fractions is \( \frac{10k\ell(k+3)}{5k\ell(k+3)} \). Notice that \((k+3)\) is a common factor in both the numerator and the denominator, so you can cancel it out.
5Step 5: Simplify further by canceling terms
After canceling \( (k+3) \), the expression simplifies to \( \frac{10k\ell}{5k\ell} \). Then, \( k\ell \) is also a common factor and can be canceled out.
6Step 6: Final simplification
After all cancellations, the expression simplifies to \( \frac{10}{5} \), which simplifies to 2.
Key Concepts
Understanding Algebraic ExpressionsMultiplying Fractions in AlgebraFinding Common FactorsCancelling Terms for Simplification
Understanding Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operations. In general, they can include:
Understanding how to manipulate and simplify algebraic expressions is essential for solving many algebra problems, including this exercise.
- Numeric constants, like 5 or 10
- Variables, such as \( k \) or \( \ell \)
- Operations, like addition, subtraction, multiplication, or division
Understanding how to manipulate and simplify algebraic expressions is essential for solving many algebra problems, including this exercise.
Multiplying Fractions in Algebra
When multiplying fractions, the process is straightforward. Multiply the numerators together to form a new numerator and multiply the denominators together to form a new denominator.
In the given exercise, we have two fractions: \(\frac{k+3}{5k\ell}\) and \(\frac{10k\ell}{k+3}\). To multiply them, we follow these steps:
It is crucial to handle each multiplication carefully to ensure that the expressions are correct before simplifying the fraction.
In the given exercise, we have two fractions: \(\frac{k+3}{5k\ell}\) and \(\frac{10k\ell}{k+3}\). To multiply them, we follow these steps:
- Multiply the numerators: \((k+3) \times 10k\ell = 10k\ell(k+3)\)
- Multiply the denominators: \(5k\ell \times (k+3) = 5k\ell(k+3)\)
It is crucial to handle each multiplication carefully to ensure that the expressions are correct before simplifying the fraction.
Finding Common Factors
Common factors in fractions are terms that appear in both the numerator and the denominator and can be "cancelled" to simplify the fraction. Identifying these factors is essential because it greatly simplifies the process of fraction simplification.
In our exercise, after multiplying the fractions, we obtain: \(\frac{10k\ell(k+3)}{5k\ell(k+3)}\).
Here, the term \((k+3)\) is common to both the numerator and the denominator. By cancelling out \((k+3)\), we simplify the fraction. It’s also important to note that sometimes multiple terms can be factors, like \(k\ell\), which can also be cancelled in this case.
This process of finding and cancelling common factors is a critical step in reducing fractions.
In our exercise, after multiplying the fractions, we obtain: \(\frac{10k\ell(k+3)}{5k\ell(k+3)}\).
Here, the term \((k+3)\) is common to both the numerator and the denominator. By cancelling out \((k+3)\), we simplify the fraction. It’s also important to note that sometimes multiple terms can be factors, like \(k\ell\), which can also be cancelled in this case.
This process of finding and cancelling common factors is a critical step in reducing fractions.
Cancelling Terms for Simplification
Cancelling terms is the process of removing common factors from the numerator and the denominator to simplify an algebraic fraction.
In the step-by-step solution, we canceled the term \((k+3)\) because it appears both in the numerator and the denominator. After this cancellation, we are left with \( \frac{10k\ell}{5k\ell} \).
Further simplification involves cancelling \(k\ell\), leaving us with \(\frac{10}{5}\). Simplifying further results in the final answer of 2.
Cancelling terms is a powerful technique in algebra that helps to make complex expressions manageable and reveals the simplest form of a fraction.
In the step-by-step solution, we canceled the term \((k+3)\) because it appears both in the numerator and the denominator. After this cancellation, we are left with \( \frac{10k\ell}{5k\ell} \).
Further simplification involves cancelling \(k\ell\), leaving us with \(\frac{10}{5}\). Simplifying further results in the final answer of 2.
Cancelling terms is a powerful technique in algebra that helps to make complex expressions manageable and reveals the simplest form of a fraction.
Other exercises in this chapter
Problem 76
Simplify each expression. \(\frac{39 a^{3} b^{4}}{13 a^{4} b^{3}}\)
View solution Problem 76
Simplify. $$ (\sqrt{10}-\sqrt{6})(\sqrt{5}+\sqrt{3}) $$
View solution Problem 77
Solve each equation by completing the square. $$ x^{2}+9 x+20.25=0 $$
View solution Problem 78
Simplify each expression. \(\frac{5 y-15 z}{42 x^{2}} \div \frac{y-3 z}{14 x}\)
View solution