Problem 77
Question
Name the compound that has the formula \(\operatorname{Sr} \mathrm{Cl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\)
Step-by-Step Solution
Verified Answer
The compound with the given chemical formula \(\operatorname{Sr} \mathrm{Cl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) is called strontium dichloride hexahydrate.
1Step 1: Identify the Cation
The cation in the given chemical formula \(\operatorname{Sr} \mathrm{Cl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) is Sr, which is the metal strontium.
2Step 2: Identify the Anion
The anion in the given chemical formula \(\operatorname{Sr} \mathrm{Cl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) is \(\mathrm{Cl}_{2}\), which is formed by two chloride ions (Cl⁻). We denote it as dichloride since there are two chloride ions in the compound.
3Step 3: Identify the Hydrate
The hydrate in the given chemical formula \(\operatorname{Sr} \mathrm{Cl}_{2} \cdot 6\mathrm{H}_{2} \mathrm{O}\) is \(6 \mathrm{H}_{2} \mathrm{O}\). We refer to this as hexahydrate since there are six water molecules in the compound.
4Step 4: Combine the Cation, Anion, and Hydrate
Now we combine the cation, anion, and hydrate to name the compound. We have: strontium dichloride hexahydrate.
So, the compound with the given chemical formula \(\operatorname{Sr} \mathrm{Cl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) is called strontium dichloride hexahydrate.
Key Concepts
Strontium CompoundsHydrate ChemistryChemical Formula Identification
Strontium Compounds
Strontium compounds are chemicals composed of the element strontium, a silvery metal that belongs to the alkaline earth metals in group 2 of the periodic table. Strontium is often used in fireworks to produce a bright red color and can form various chemical compounds, primarily with chlorine, sulfur, and oxygen.
In the realm of chemistry, strontium's reactive nature is notable, as it often forms ionic compounds. It typically loses two electrons to form a stable strontium ion, \( ext{Sr}^{2+}\). This means that when forming compounds, strontium usually bonds with non-metals that accept these electrons, creating substances such as strontium chloride (SrCl2).
In the realm of chemistry, strontium's reactive nature is notable, as it often forms ionic compounds. It typically loses two electrons to form a stable strontium ion, \( ext{Sr}^{2+}\). This means that when forming compounds, strontium usually bonds with non-metals that accept these electrons, creating substances such as strontium chloride (SrCl2).
- These compounds often have applications in electronics, pyrotechnics, and sometimes even pharmaceuticals.
- Understanding the properties of strontium is crucial for predicting the behavior of strontium compounds in chemical reactions.
Hydrate Chemistry
Hydrate chemistry involves compounds that contain water molecules within their crystalline structure. These are known as hydrates, and they play a significant role in various chemical processes, including synthesis and crystallization.
Hydrates are characterized by their ability to retain water molecules in a fixed ratio, which is vital in determining their physical properties. For example, in the compound \( ext{SrCl}_{2} \cdot 6 ext{H}_{2}O\), the presence of water is indicated by the dot followed by the water formula (H2O), and the prefix "hexa-" represents six water molecules bound within the compound.
Hydrates are characterized by their ability to retain water molecules in a fixed ratio, which is vital in determining their physical properties. For example, in the compound \( ext{SrCl}_{2} \cdot 6 ext{H}_{2}O\), the presence of water is indicated by the dot followed by the water formula (H2O), and the prefix "hexa-" represents six water molecules bound within the compound.
- The number of water molecules is essential for the proper nomenclature and understanding of hydrates. Hence, it's referred to as "hexahydrate" in this case.
- Hydrates like these can undergo transformations when heated, often losing their water content to become anhydrous (water-free) substances.
Chemical Formula Identification
Chemical formula identification is a fundamental skill in chemistry, enabling scientists and students to decipher and name compounds accurately. It involves reading chemical formulas to discern the elements present, the number of each type of atom, and any structural details such as water molecules or ionic compositions.
In the case of \( ext{SrCl}_{2} \cdot 6 ext{H}_{2}O\), the identification process starts by recognizing individual elements and compounds. The \( ext{Sr}\) represents the strontium cation, while \( ext{Cl}_{2}\) points to two chloride anions, indicating an ionic bond between these elements.
In the case of \( ext{SrCl}_{2} \cdot 6 ext{H}_{2}O\), the identification process starts by recognizing individual elements and compounds. The \( ext{Sr}\) represents the strontium cation, while \( ext{Cl}_{2}\) points to two chloride anions, indicating an ionic bond between these elements.
- Next, the \( ext{H}_{2}O\) denotes the water of crystallization, crucial for forming a hydrated compound.
- By analyzing these components, the compound's full name can be constructed as "strontium dichloride hexahydrate."
Other exercises in this chapter
Problem 73
Analyze Hematite (Fe \(\mathrm{O}_{3}\) ) and magnetite \(\left(\mathrm{Fe}_{3} \mathrm{O}_{4}\right)\) are two ores used as sources of iron. Which ore provides
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Challenge An 11.75-g sample of a common hydrate of cobalt(II) chloride is heated. After heating, 0.0712 mol of anhydrous cobalt chloride remains. What is the fo
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Describe the experimental procedure for determining the formula of a hydrate. Explain the reason for each step.
View solution Problem 79
Apply A hydrate contains 0.050 mol of \(\mathrm{H}_{2} \mathrm{O}\) to every 0.00998 mol of ionic compound. Write a generalized formula of the hydrate.
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