Problem 77
Question
\(\mathrm{Cu}^{+}(\mathrm{aq})\) is unstable in solution and undergoes simultaneous oxidation and reduction according to the reaction, \(2 \mathrm{Cu}^{+}(\mathrm{aq}) \rightleftharpoons-\mathrm{Cu}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})\) choose correct \(E^{\circ}\) for above reaction if \(E^{\circ}\left(\mathrm{Cu}^{2+} / \mathrm{Cu}\right)=0.34 \mathrm{~V}\) and \(E^{\circ}\left(\mathrm{Cu}^{2+} / \mathrm{Cu}^{+}\right)=0.15 \mathrm{~V}\) (a) \(-0.38 \mathrm{~V}\) (b) \(+0.49 \mathrm{~V}\) (c) \(+0.38 \mathrm{~V}\) (d) \(-0.19 \mathrm{~V}\)
Step-by-Step Solution
Verified Answer
Option (d): \(-0.19 \mathrm{~V}\) is correct.
1Step 1: Understanding the Reaction
The given reaction is a redox reaction where simultaneously, copper(I) ions are oxidized to copper(II) ions and reduced to copper metal. This type of reaction is known as a disproportionation reaction, where an element in one oxidation state is simultaneously oxidized and reduced, resulting in different products.
2Step 2: Identify the Half-Reactions
For the disproportionation reaction \(2 \mathrm{Cu}^+(\mathrm{aq}) \rightarrow \mathrm{Cu}^{2+}(\mathrm{aq}) + \mathrm{Cu}(\mathrm{s})\), we need to split it into two half-reactions. The oxidation half-reaction is:\(\mathrm{Cu}^+ \rightarrow \mathrm{Cu}^{2+} + e^-\)and the reduction half-reaction is:\(\mathrm{Cu}^+ + e^- \rightarrow \mathrm{Cu}\).
Key Concepts
Redox ReactionElectrochemistryOxidation and Reduction Half-Reactions
Redox Reaction
Redox reactions are chemical processes where the oxidation states of elements change during the reaction. The term 'redox' stands for reduction-oxidation, as these reactions involve both reduction and oxidation processes. Reduction refers to the gain of electrons by an element, while oxidation involves the loss of electrons.
In a redox reaction, two half-reactions occur: one representing the oxidation process and the other for reduction. This balance between oxidation and reduction is crucial as electrons lost in the oxidation half must be gained in the reduction half. Such reactions occur frequently in nature and are fundamental to processes like respiration, combustion, and photosynthesis.
In a redox reaction, two half-reactions occur: one representing the oxidation process and the other for reduction. This balance between oxidation and reduction is crucial as electrons lost in the oxidation half must be gained in the reduction half. Such reactions occur frequently in nature and are fundamental to processes like respiration, combustion, and photosynthesis.
Electrochemistry
Electrochemistry is a branch of chemistry that studies the interaction between chemical reactions and electricity. It primarily focuses on redox reactions where electron transfer is fundamental. In electrochemical cells, these reactions allow for the conversion of chemical energy into electrical energy and vice versa.
- **Galvanic Cells**: These use spontaneous redox reactions to generate electricity. A classic example is a battery.
- **Electrolytic Cells**: Here, electricity is used to drive non-spontaneous chemical reactions, such as in electrolysis.
Oxidation and Reduction Half-Reactions
In any redox reaction, we split the reaction into oxidation and reduction half-reactions to understand the electron transfer process. Each half-reaction shows either the loss or gain of electrons.
- **Oxidation Half-Reaction**: Demonstrates how an element loses electrons. e.g., in the oxidation of copper, \[\text{Cu}^+ \rightarrow \text{Cu}^{2+} + e^- \]
- **Reduction Half-Reaction**: Shows how an element gains electrons. e.g., in the reduction of copper, \[\text{Cu}^+ + e^- \rightarrow \text{Cu(s)} \]
Other exercises in this chapter
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