Problem 77
Question
Let \(n \geq 1\) be constant, and consider the region bounded by \(f(x)=x^{n},\) the \(x\) -axis, and \(x=1\). Find the centroid of this region. As \(n \rightarrow \infty\), what does the region look like, and where is its centroid?
Step-by-Step Solution
Verified Answer
The centroid of the region bounded by the curve \(f(x) = x^n\), the x-axis, and \(x = 1\) is \((\frac{n+1}{n+2},\frac{n+1}{2n+2})\). As \(n \rightarrow \infty\), the centroid is \((1,0.5)\), resembling a vertical line at \(x = 1\).
1Step 1: Calculating the Area under f(x)
The area 'A' under the curve \( f(x) = x^n \) from 0 to 1 is given by: \( A = \int_{0}^{1} x^n dx \), computing this we get \( A = \frac{1}{n+1} \).
2Step 2: Calculating the centroid coordinates
Next, calculate the x-coordinate of the centroid \(\bar{x}\) using the formula: \(\bar{x}= \frac{1}{A} \int_{0}^{1} x. f(x) dx \) which calculates to \(\bar{x}= \frac{1}{\frac{1}{n+1}} \int_{0}^{1} x^{n+1} dx = \frac{n+1}{n+2} \). Similarly, calculate the y-coordinate of the centroid \(\bar{y}\) using the formula: \( \bar{y}= \frac{1}{2A} \int_{0}^{1} (f(x))^2 dx \) which calculates to \(\bar{y} = \frac{1}{2\frac{1}{n+1}} \int_{0}^{1} x^{2n} dx = \frac{n+1}{2n+2} \).
3Step 3: Describing the region and its centroid as \( n \rightarrow \infty \)
As \( n \rightarrow \infty \), the graph of the function \( x^n \) approaches the x-axis for \(0
Key Concepts
Definite IntegralsCentroid CoordinatesLimit Behavior
Definite Integrals
A definite integral helps us find the area under a curve between two points. It is a fundamental concept in calculus essential for various applications. In this problem, we need to calculate the area under the function \( f(x) = x^n \) from \( x = 0 \) to \( x = 1 \). Here's how it works:
- The integral \( \int_{0}^{1} x^n \, dx \) is computed, resulting in \( \frac{1}{n+1} \). This value represents the total area under the curve, which is crucial for further calculations.
- Definite integrals give you exact numerical values rather than a function, thus allowing you to determine quantities like area with precise bounds.
Centroid Coordinates
The centroid of a region acts similarly to a center of mass, balancing the shape perfectly. To find it, we need coordinates \( \bar{x} \) and \( \bar{y} \). Here’s how each is determined:
- X-coordinate \( \bar{x} \): We use the formula \( \bar{x} = \frac{1}{A} \int_{0}^{1} x \cdot f(x) \, dx \). With the previously found area, \( A = \frac{1}{n+1} \), it evaluates to \( \bar{x} = \frac{n+1}{n+2} \). This coordinate leans towards the higher \( x \) values due to the curve's stretching nature.
- Y-coordinate \( \bar{y} \): For the y-coordinate, the formula \( \bar{y}= \frac{1}{2A} \int_{0}^{1} (f(x))^{2} \, dx \) is used. With calculations, it results in \( \bar{y} = \frac{n+1}{2n+2} \). This coordinate is generally located below the midline of the shape's height, illustrating the region's mass distribution.
Limit Behavior
Exploring the behavior as \( n \rightarrow \infty \) provides insights into how the region evolves. When \( n \) increases indefinitely, the polynomial \( x^n \) transforms significantly:
- The graph flatten towards the \( x \)-axis between \( 0 < x < 1 \), turning into a more exaggerated exponential drop, only touching 1 at \( x = 1 \). Essentially, it becomes a steep wall at \( x = 1 \) as \( n \) grows.
- Geometrically, this shift results in the region appearing to shrink on the \( y \)-axis yet subtly stretches along the \( x \)-axis.
- The x-coordinate \( \bar{x} \) naturally drifts towards 1, indicating that the center of mass is pulling closer to the far-right boundary as the region becomes more right-leaning.
- The y-coordinate \( \bar{y} \) approaches 0.5, suggesting the vertical balance less reliant on height, aligning with the region's form of a slender line extending upward from the x-axis.
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