Problem 77
Question
Let \(h(t)=\sqrt{t+3}\) and \(k(t)=t-5 .\) Find each of the following. $$ (h \circ k)(18) $$
Step-by-Step Solution
Verified Answer
(h \circ k)(18) = 4.
1Step 1: Understand the Composition
The composition of functions \((h \circ k)(t)\) means we first apply the function \(k(t)\) and then apply the function \(h(t)\) to the result of \(k(t)\). Therefore, \((h \circ k)(t) = h(k(t))\).
2Step 2: Evaluate \(k(18)\)
Substitute \(t = 18\) into the function \(k(t) = t - 5\). This gives: \[ k(18) = 18 - 5 = 13 \]
3Step 3: Evaluate \(h(k(18))\)
Now substitute the result from the previous step into the function \(h(t) = \sqrt{t+3}\). This means substituting \(13\) into \(h(t)\).\[ h(13) = \sqrt{13 + 3} = \sqrt{16} \]
4Step 4: Calculate \(\sqrt{16}\)
Since \(\sqrt{16} = 4\), this is the value for \(h(13)\).
Key Concepts
Understanding the Square Root FunctionMastering Function EvaluationMath Problem Solving with Function Composition
Understanding the Square Root Function
The square root function is a special type of mathematical operation that reverses the process of squaring a number. When you see the square root sign, it means you are looking for a number that, when multiplied by itself, gives the original number beneath the square root symbol.For example,
- the square root of 16 is 4 because when you multiply 4 by 4, you get 16.
- Similarly, the square root of 9 is 3, as 3 times 3 equals 9.
- Did you know that the square root of 1 is just 1? That's because 1 multiplied by itself is still 1.
Mastering Function Evaluation
Function evaluation is the process of finding the output of a function for a given input. Imagine it as feeding a number into a machine that follows a set of instructions to produce a result.Let's take the function \(k(t) = t - 5\). To evaluate this function for \(t = 18\):
- You simply substitute 18 for \(t\) in the function.
- So you calculate \(18 - 5\), which equals 13.
Math Problem Solving with Function Composition
Function composition is like chaining together two or more functions, where the output of one function becomes the input of another. This comes in handy when you need to perform complex calculations in a sequence.In the exercise,
- the function \((h \circ k)(t)\) symbolizes: first apply \(k(t)\), then apply \(h(t)\) to that result.
- This is done step by step to maintain accuracy and logic in your calculations.
- First, you evaluate \(k(t)\), then you use the result to evaluate \(h(t)\). This stepwise approach simplifies how you manage multiple functions and the transformations between them.
Other exercises in this chapter
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