Problem 77
Question
In which of the following gaseous reaction, the value of \(K_{p}\) is less than \(K_{c}\) ? (a) \(\mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCI}_{3}+\mathrm{Cl}_{2}\) (b) \(2 \mathrm{SO}_{2}+\mathrm{O}_{2} \longrightarrow 2 \mathrm{SO}_{3}\) (c) \(2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}\) (d) \(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\)
Step-by-Step Solution
Verified Answer
Reactions (b) and (d) have \(K_{p} < K_{c}\).
1Step 1: Write the general formula relating Kp and Kc
The relationship between the equilibrium constants \(K_{p}\) and \(K_{c}\) for a gaseous reaction is given by \[ K_{p} = K_{c}(RT)^{\Delta n} \]where \(R\) is the ideal gas constant, \(T\) is the temperature in Kelvin, and \(\Delta n\) is the change in moles of gas, calculated as moles of gaseous products minus moles of gaseous reactants.
2Step 2: Calculate \(\Delta n\) for each reaction
(a) \(\mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{3}+\mathrm{Cl}_{2}\): \[ \Delta n = (1 + 1) - 1 = 1 \](b) \(2 \mathrm{SO}_{2}+\mathrm{O}_{2} \longrightarrow 2 \mathrm{SO}_{3}\): \[ \Delta n = 2 - (2 + 1) = -1 \](c) \(2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}\): \[ \Delta n = (1 + 1) - 2 = 0 \](d) \(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\): \[ \Delta n = 2 - (1 + 3) = -2 \]
3Step 3: Determine if \(K_{p} < K_{c}\)
For \(K_{p}\) to be less than \(K_{c}\), the term \((RT)^{\Delta n} < 1\).This means \(\Delta n\) must be negative. From Step 2:- Reaction (a) \(\Delta n = 1\), \(K_{p} > K_{c}\).- Reaction (b) \(\Delta n = -1\), \(K_{p} < K_{c}\).- Reaction (c) \(\Delta n = 0\), \(K_{p} = K_{c}\).- Reaction (d) \(\Delta n = -2\), \(K_{p} < K_{c}\).
4Step 4: Identify which choices have \(K_{p} < K_{c}\)
Based on the calculations, reactions (b) and (d) have \(K_{p} < K_{c}\) since their \(\Delta n\) values are negative.- Reaction (b) has \(\Delta n = -1\)- Reaction (d) has \(\Delta n = -2\)
Key Concepts
Equilibrium ConstantKp and Kc relationshipChange in Moles of Gas (Δn)Ideal Gas Constant (R)
Equilibrium Constant
The equilibrium constant is a crucial concept in chemistry that helps us understand chemical reactions in a state of balance. For a general reaction \\[ aA + bB \rightleftharpoons cC + dD \] \(K_c\) is the equilibrium constant expressed in terms of concentrations of products and reactants. It's calculated as follows:
- \(K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}\)
Kp and Kc relationship
In reactions involving gases, we often use the equilibrium constant in terms of partial pressures, denoted as \(K_p\). The relationship between \(K_p\) and \(K_c\) is important for understanding the dynamics of a reaction under different conditions:
- The relationship can be expressed as: \[ K_p = K_c (RT)^{\Delta n} \]
Change in Moles of Gas (Δn)
The term \(\Delta n\) is essential in linking \(K_p\) and \(K_c\). It measures the change in the number of moles of gas as a reaction proceeds from reactants to products:
- \(\Delta n = \text{moles of gaseous products} - \text{moles of gaseous reactants}\)
Ideal Gas Constant (R)
The ideal gas constant \(R\) is a vital part of the equation that connects \(K_p\) and \(K_c\). It's a universal constant in the equation \(K_p = K_c (RT)^{\Delta n}\) and provides the necessary link between energy and temperature across different gas laws.
- The value of \(R\) is approximately 8.314 J/mol⋅K when using SI units.
Other exercises in this chapter
Problem 74
For a gaseous reaction \(2 \mathrm{~A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D}\), the partial pressures of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) an
View solution Problem 75
For the reaction \(\mathrm{C}_{(\mathrm{s})}+\mathrm{CO}_{2}(\mathrm{~g})=2 \mathrm{CO}(\mathrm{g})\), the par- tial pressures of \(\mathrm{CO}_{2}\) and \(\mat
View solution Problem 80
The ratio of \(\mathrm{Kp} / \mathrm{Kc}\) for the reaction \(\mathrm{SO}_{2}(\mathrm{~g})+1 / 2 \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_{3}(
View solution Problem 81
If \(2 \mathrm{NO} \rightleftharpoons \mathrm{N}_{2}+\mathrm{O}_{2}\) \(\mathrm{K}_{\mathrm{c}}=2.5 \times 10^{30}\) \(\mathrm{NO}+\frac{1}{2} \mathrm{Br}_{2} \
View solution