Problem 77
Question
In Exercises \(64-77, T_{n}\) denotes the nth Fibonacci tree. Prove each. $$e_{n}=2 F_{n}-2$$
Step-by-Step Solution
Verified Answer
In summary, by using induction, we have proven that the formula \(e_n = 2F_n - 2\) holds true for all Fibonacci trees T_n. The base cases hold true for n = 1 and n = 2. Assuming the formula is true for n = k and n = k - 1, we have shown that it holds for n = k + 1, which completes the induction proof.
1Step 1: Define the nth Fibonacci tree and Fibonacci numbers
The nth Fibonacci tree, T_n, is a tree with recursively constructed nodes that follow the Fibonacci sequence. The first two Fibonacci trees, T_1 and T_2, consist of a single node. The kth Fibonacci tree, T_k, is formed by joining the (k-1)th and (k-2)th Fibonacci trees as subtrees.
Fibonacci numbers, denoted as F_n, form a sequence {0, 1, 1, 2, 3, 5, 8, ...} such that every number after the first two is the sum of the two preceding ones. Mathematically, F_n = F_{n-1} + F_{n-2} for n > 1, and F_0 = 0, F_1 = 1.
2Step 2: Base case
For the base cases, we consider the first and second Fibonacci trees and check if the formula holds true.
For n = 1: \(e_1 = 2 F_{1} - 2 = 2(1) - 2 = 0\), and T_1 has 0 edges.
For n = 2: \(e_2 = 2 F_{2} - 2 = 2(1) - 2 = 0\), and T_2 has 0 edges.
Since the formula holds true for the base cases, we proceed with the induction step.
3Step 3: Induction hypothesis
Assume the formula holds true for n = k and n = k - 1:
\(e_k = 2 F_{k} - 2\) and \(e_{k-1} = 2 F_{k-1} - 2\)
4Step 4: Induction step
We want to show that the formula holds true for n = k + 1:
\(e_{k+1} = 2 F_{k+1} - 2\)
We know that T_{k+1} is formed by joining T_k and T_{k-1} as subtrees. The number of edges in T_{k+1} can be represented as the sum of the number of edges in T_k and T_{k-1} plus one new edge connecting the roots of T_k and T_{k-1}:
\(e_{k+1} = e_k + e_{k-1} + 1\)
Now, substitute the induction hypothesis:
\(e_{k+1} = (2 F_{k} - 2) + (2 F_{k-1} - 2) + 1\)
Since F_n = F_{n-1} + F_{n-2}, we can replace F_{k+1} with F_k + F_{k-1}:
\(e_{k+1} = 2 (F_{k} + F_{k-1}) - 3\)
\(e_{k+1} = 2 F_{k+1} - 3 + 1\)
\(e_{k+1} = 2 F_{k+1} - 2\)
This proves our induction step, and the formula holds for n = k + 1.
5Step 5: Conclusion
By induction, the formula \(e_n = 2F_n - 2\) holds true for all Fibonacci trees T_n. Thus, the number of edges in the nth Fibonacci tree can be determined using this formula.
Key Concepts
Fibonacci SequenceInductive ProofRecursionMathematical Induction
Fibonacci Sequence
The Fibonacci sequence is a series of numbers where each number is the sum of the two preceding ones, starting with 0 and 1. It begins like this: 0, 1, 1, 2, 3, 5, 8, and continues on infinitely.
Mathematically, it can be defined as:
Mathematically, it can be defined as:
- \( F_0 = 0 \)
- \( F_1 = 1 \)
- \( F_n = F_{n-1} + F_{n-2} \) for \( n > 1 \)
Inductive Proof
Inductive proof is a mathematical technique used to prove statements about all natural numbers. It involves two primary steps:
- Base Case: Verify the statement is true for the initial value, often n=1 or n=0.
- Induction Step: Show that if the statement is true for an arbitrary number \( n = k \), then it must also be true for \( n = k + 1 \).
Recursion
Recursion is a powerful and elegant method for solving problems, where a problem is divided into smaller, similar subproblems. A recursive function calls itself with different arguments to break down the tasks.
In the context of Fibonacci numbers and Fibonacci trees, recursion provides an ideal approach as it resembles the natural structure of these mathematical constructs. For instance, calculating the nth Fibonacci number recursively involves breaking down the calculation into finding the \( (n-1) \)th and \( (n-2) \)th Fibonacci numbers using the formula \( F_n = F_{n-1} + F_{n-2} \).
This recursive nature makes it easier to translate problems into a series of steps that match the inherent properties of what we are trying to solve. Hence, recursion is a key concept when dealing with structures like Fibonacci trees.
In the context of Fibonacci numbers and Fibonacci trees, recursion provides an ideal approach as it resembles the natural structure of these mathematical constructs. For instance, calculating the nth Fibonacci number recursively involves breaking down the calculation into finding the \( (n-1) \)th and \( (n-2) \)th Fibonacci numbers using the formula \( F_n = F_{n-1} + F_{n-2} \).
This recursive nature makes it easier to translate problems into a series of steps that match the inherent properties of what we are trying to solve. Hence, recursion is a key concept when dealing with structures like Fibonacci trees.
Mathematical Induction
Mathematical induction is a proof technique similar to a domino effect. By showing a statement is true for the first few steps, and proving each step implies the next one, we ensure the statement holds in general. It involves:
- Base Case: Establishing the truth of the statement for a starting value, say n=0 or n=1.
- Inductive Hypothesis: Assuming the statement is valid for some arbitrary step n=k.
- Inductive Step: Proving that if the statement holds for n=k, it necessarily holds for n=k+1.
Other exercises in this chapter
Problem 72
In Exercises \(64-77, T_{n}\) denotes the nth Fibonacci tree. Using \(T_{n},\) define each recursively. The height \(h_{n}\)
View solution Problem 73
In Exercises \(64-77, T_{n}\) denotes the nth Fibonacci tree. Using \(T_{n},\) define each recursively. The number of edges \(e_{n}\)
View solution Problem 77
Prove each. $$e_{n}=2 F_{n}-2$$
View solution Problem 78
Write an algorithm to traverse a binary tree in: Preorder.
View solution