Problem 77
Question
For each pair of numbers, find the values of \(a, b,\) and \(c\) for which the quadratic equation ax \(^{2}+b x+c=0\) has the given numbers as solutions. Answers may vary. (Hint: Use the zero-product property in reverses $$4,5$$
Step-by-Step Solution
Verified Answer
\(a = 1\), \(b = -9\), \(c = 20\).
1Step 1: Identify Roots and Use Reverse Zero-Product Property
The roots of the quadratic equation are 4 and 5. According to the zero-product property, the equation can be expressed as \((x - 4)(x - 5) = 0\).
2Step 2: Expand the Factored Form
Expand the product \((x - 4)(x - 5)\) to form the quadratic equation. Multiply: \((x - 4)(x - 5) = x^2 - 5x - 4x + 20 = x^2 - 9x + 20\).
3Step 3: Identify Coefficients
From the expanded form \(x^2 - 9x + 20\), we can identify the coefficients: \(a = 1\), \(b = -9\), \(c = 20\).
Key Concepts
Zero-Product PropertyRoots of EquationsFactoringCoefficients
Zero-Product Property
The Zero-Product Property is an essential concept in algebra. It tells us that if the product of two numbers is zero, then at least one of the numbers must be zero. This property is represented as: if \(ab = 0\), then \(a = 0\) or \(b = 0\).
When dealing with quadratic equations, this property helps in finding the solutions or "roots" of the equation. For instance, if we factorize a quadratic equation into two binomials like \((x - a)(x - b) = 0\), it means \(x\) must be equal to either \(a\) or \(b\) to satisfy the equation.
By applying the Zero-Product Property in reverse, as in the given problem, we know that if a quadratic equation has solutions, or roots, we can express it as a product of two binomials. This is an effective way to reconstruct the original equation once the roots are known.
When dealing with quadratic equations, this property helps in finding the solutions or "roots" of the equation. For instance, if we factorize a quadratic equation into two binomials like \((x - a)(x - b) = 0\), it means \(x\) must be equal to either \(a\) or \(b\) to satisfy the equation.
By applying the Zero-Product Property in reverse, as in the given problem, we know that if a quadratic equation has solutions, or roots, we can express it as a product of two binomials. This is an effective way to reconstruct the original equation once the roots are known.
Roots of Equations
Roots of an equation are the values that satisfy the equation when substituted for the variable. In a quadratic equation of the form \(ax^2 + bx + c = 0\), the roots are the values of \(x\) that make the equation true.
For a standard quadratic equation, you may find roots using several methods:
Finding the roots enables us to understand important properties of quadratic graphs, such as where they intersect the x-axis.
For a standard quadratic equation, you may find roots using several methods:
- Factoring the quadratic.
- Using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
- Completing the square.
Finding the roots enables us to understand important properties of quadratic graphs, such as where they intersect the x-axis.
Factoring
Factoring is a mathematical process used to express an equation as a product of its factors. For quadratic equations, factoring can simplify finding the roots.
Given a quadratic equation in standard form, \(ax^2 + bx + c\), the goal of factoring is to write it in the form \((x - p)(x - q)\) where \(p\) and \(q\) are the roots.
In the exercise, the equation \((x - 4)(x - 5) = 0\) has been expanded to form \(x^2 - 9x + 20\) through multiplication:
Given a quadratic equation in standard form, \(ax^2 + bx + c\), the goal of factoring is to write it in the form \((x - p)(x - q)\) where \(p\) and \(q\) are the roots.
In the exercise, the equation \((x - 4)(x - 5) = 0\) has been expanded to form \(x^2 - 9x + 20\) through multiplication:
- First, distribute: \(x \times x\), \(x \times -5\), \(-4 \times x\), and \(-4 \times -5\).
- Second, combine like terms to get the quadratic \(x^2 - 9x + 20\).
Coefficients
In a quadratic equation expressed as \(ax^2 + bx + c = 0\), the terms \(a\), \(b\), and \(c\) are known as coefficients. These coefficients determine the shape and position of the quadratic curve when plotted on a graph.
- The coefficient \(a\) is the leading coefficient.- The coefficient \(b\) is the linear coefficient.- The coefficient \(c\) is the constant term.
In the example from the exercise, the expanded equation \(x^2 - 9x + 20\) shows that:
- The coefficient \(a\) is the leading coefficient.- The coefficient \(b\) is the linear coefficient.- The coefficient \(c\) is the constant term.
In the example from the exercise, the expanded equation \(x^2 - 9x + 20\) shows that:
- \(a = 1\): indicating a standard "u" shaped parabola since it is positive,.
- \(b = -9\): affecting the horizontal positioning and symmetry of the graph.
- \(c = 20\): the y-intercept where the graph crosses the y-axis.
Other exercises in this chapter
Problem 76
Find the center-radius form of the equation of a circle with the given center and radius. Graph the circle. Center \((0,-3),\) radius \(\sqrt{7}\)
View solution Problem 76
Simplify each expression to \(i, 1,-i,\) or \(-1\) $$i^{19}$$
View solution Problem 77
Find the center-radius form of the circle with the given equation. Determine the coordinates of the center, find the radius, and graph the circle. $$x^{2}+y^{2}
View solution Problem 77
Simplify each expression to \(i, 1,-i,\) or \(-1\) $$i^{64}$$
View solution