Problem 77
Question
\(\begin{array}{ll} & (\mathbf{a}) \text { How does the structure of diborane }\left(\mathrm{B}_{2} \mathrm{H}_{6}\right) \text { differ from }\end{array}\) that of ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right) ?(\mathbf{b})\) Explain why diborane adopts the geometry that it does. (c) What is the significance of the statement that the hydrogen atoms in diborane are described as "hydridic"?
Step-by-Step Solution
Verified Answer
Diborane has 3c-2e bonds, unlike ethane's sigma bonds. Diborane's geometry is electron-deficient driven, while hydridic hydrogen atoms have a partial negative charge.
1Step 1: Understanding the structure of Diborane (B2H6)
Diborane has a unique structure characterized by two boron atoms and six hydrogen atoms. Unlike ethane, diborane forms two three-center two-electron (3c-2e) bonds. Each boron atom is bonded with two terminal hydrogen atoms and shares two bridging hydrogen atoms with the other boron.
2Step 2: Comparing B2H6 with Ethane (C2H6) Structure
In ethane, each carbon forms four single covalent bonds with hydrogen atoms or another carbon atom, resulting in a tetrahedral geometry around each carbon. In contrast, diborane utilizes 3c-2e bonds for the bridging hydrogen atoms, leading to a different bonding and structural arrangement without the classical direct H—B—B—H single bond network found in ethane.
3Step 3: Geometry of Diborane
Diborane's geometry is driven by electron deficiency. Each boron atom needs three bonds, but instead of forming typical covalent bonds, it creates a unique 3c-2e bond. This results in a bridge-like structure where hydrogen atoms bridge between boron atoms, possessing banana-shaped bonds because standard Lewis structures cannot fully describe diborane.
4Step 4: Significance of "hydridic" Hydrogen Atoms in Diborane
Describing the hydrogen atoms in diborane as "hydridic" refers to their partial negative charge. In diborane, these hydrogen atoms participate in 3c-2e bonds, leading to a shift in electron density that makes them more negatively charged than typical hydrogen atoms, resembling more of a hydride ion (H⁻) than a proton (H⁺).
Key Concepts
Three-center two-electron bondsElectron deficiencyHydridic hydrogen atoms
Three-center two-electron bonds
Three-center two-electron bonds, often abbreviated as 3c-2e bonds, are a fascinating feature of the diborane molecule,
formed between boron and hydrogen atoms. Unlike typical two-center covalent bonds, which involve two electrons shared by two atoms,
3c-2e bonds involve two electrons being shared by three atoms. This unconventional bonding occurs in diborane due to its unique structural requirements.
This bond formation reflects the electron deficiency inherent in certain molecules, creating a scenario where traditional Lewis structures are inadequate. The concept of 3c-2e bonds provides insight into why some molecules adopt non-conventional bonding schemes to achieve stability.
- Diborane comprises two boron atoms and six hydrogen atoms.
- Each boron atom bonds to two terminal hydrogen atoms.
- Two hydrogen atoms act as bridges between the boron atoms, forming 3c-2e bonds.
This bond formation reflects the electron deficiency inherent in certain molecules, creating a scenario where traditional Lewis structures are inadequate. The concept of 3c-2e bonds provides insight into why some molecules adopt non-conventional bonding schemes to achieve stability.
Electron deficiency
Electron deficiency is a core reason why diborane adopts its unusual structure. Unlike carbon in ethane, which achieves a stable electron structure
through typical covalent bonding, boron in diborane doesn't have enough electrons to complete its octet through conventional means.
Diborane compensates for this deficiency through its 3c-2e bonds, allowing each boron molecule to effectively share electrons with the neighboring hydrogen and boron atoms. By forming these bonds, each boron atom achieves a state that satisfies its bonding requirements in the face of electron scarcity.
Diborane compensates for this deficiency through its 3c-2e bonds, allowing each boron molecule to effectively share electrons with the neighboring hydrogen and boron atoms. By forming these bonds, each boron atom achieves a state that satisfies its bonding requirements in the face of electron scarcity.
- In ethane, each carbon can form four single bonds to satisfy the octet rule.
- Boron, with only three valence electrons, cannot form enough single bonds to fill its valence.
- The 3c-2e bonds allow diborane to stabilize its structure despite having fewer electrons than needed for simple bonding models.
Hydridic hydrogen atoms
In the context of diborane, the term "hydridic" describes hydrogen atoms with characteristics more similar to hydride ions
(H⁻) rather than typical protons (H⁺). This is due to the electron density distribution within the molecule.
Ordinarily, hydrogen atoms in covalent compounds like ethane share electron density equally, but in diborane, the situation differs:
Ordinarily, hydrogen atoms in covalent compounds like ethane share electron density equally, but in diborane, the situation differs:
- The hydrogen atoms involved in 3c-2e bonds possess higher electron density compared to standard covalent bonds.
- This electron density shift confers a partial negative charge on these hydrogen atoms.
- As a result, they resemble a hydride ion, acting as if they carry an extra electron, giving rise to the term "hydridic."
Other exercises in this chapter
Problem 72
Select the member of group 14 that best fits each description: (a) has the greatest tendency to form multiple bonds with itself, (b) forms polymeric structures
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Write a balanced equation for each of the following reactions: (a) Diborane reacts with water to form boric acid and molecular hydrogen. (b) Upon heating, boric
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Although the \(\mathrm{ClO}_{4}^{-}\) and \(\mathrm{IO}_{4}^{-}\) ions have been known for a long time, \(\mathrm{BrO}_{4}^{-}\) was not synthesized until 1965
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