Problem 77
Question
A spaceship at rest in a certain reference frame \(S\) is given a speed increment of \(0.50 \mathrm{c}\). Relative to its new rest frame, it is then given a further \(0.50 \mathrm{c}\) increment. This process is continued until its speed with respect to its original frame \(S\) exceeds \(0.999 \mathrm{c}\). How many increments does this process require?
Step-by-Step Solution
Verified Answer
Five increments are required for the spaceship's speed to exceed \(0.999c\).
1Step 1: Understand the Problem
We need to find out how many speed increments of \(0.50\, c\) are required until the spaceship's speed in the original reference frame exceeds \(0.999\, c\). Importantly, we must account for relativistic velocity addition since speeds are high relative to the speed of light \(c\).
2Step 2: Use Relativistic Velocity Addition Formula
In the relativistic context, when a body at velocity \(u\) is given a velocity increment \(v\), the new velocity \(u'\) is given by the formula:\[u = \frac{u + v}{1 + \frac{uv}{c^2}}\]Here, \(v = 0.50\, c\) is the increment, and initially \(u = 0\).
3Step 3: Calculate First Speed Increment
After the first increment:\[u_1 = \frac{0 + 0.50c}{1 + 0} = 0.50c\]The speed in the frame \(S\) after the first increment is \(0.50c\).
4Step 4: Compute Second Increment
For the second increment, using the velocity from Step 3:\[u_2 = \frac{0.50c + 0.50c}{1 + (0.50 \, c)(0.50 \, c)/c^2} = \frac{1.00c}{1.25} = 0.80c\]
5Step 5: Calculate Third Increment
For the third increment:\[u_3 = \frac{0.80c + 0.50c}{1 + (0.80 \, c)(0.50 \, c)/c^2} = \frac{1.30c}{1.40} = 0.9286c\]
6Step 6: Determine Fourth Increment
For the fourth increment:\[u_4 = \frac{0.9286c + 0.50c}{1 + (0.9286 \, c)(0.50 \, c)/c^2} = \frac{1.4286c}{1.4643} \approx 0.9756c\]
7Step 7: Calculate Fifth Increment
Compute for the fifth increment:\[u_5 = \frac{0.9756c + 0.50c}{1 + (0.9756 \, c)(0.50 \, c)/c^2} = \frac{1.4756c}{1.4878} \approx 0.9932c\]Now the speed has exceeded \(0.999c\).
Key Concepts
Reference FrameSpeed of LightVelocity Increment
Reference Frame
A reference frame is an essential concept in physics, especially in the study of motion. It serves as the backdrop against which the position and velocity of objects are measured. Imagine you're observing a spaceship from a stationary point on Earth; your observation point constitutes your reference frame.
Why does this matter? Because velocities aren't absolute; they depend on the observer's frame. Understanding this helps grasp how the spaceship's speed surpasses a certain threshold relative to its starting point.
- In our exercise, reference frame "S" is the initial frame where the spaceship is at rest initially.
- Each time an increment is applied, the speed of the spaceship is measured from this original frame "S".
Why does this matter? Because velocities aren't absolute; they depend on the observer's frame. Understanding this helps grasp how the spaceship's speed surpasses a certain threshold relative to its starting point.
Speed of Light
The speed of light, denoted as "c", is one of the constants of nature, approximately equal to 299,792,458 meters per second. In physics, especially in relativistic contexts, it’s considered the ultimate speed limit for any object or signal.
Importantly, the speed of light being a constant governs how velocities combine. This is why even with continuous increments, the ship never quite reaches "c" but can approach it closely, such as exceeding 0.999c in our problem.
- In our context, the speed of the spaceship increments towards this limit.
- As speeds approach "c", Newtonian physics can no longer be applied, necessitating the use of Einstein's theory of relativity.
Importantly, the speed of light being a constant governs how velocities combine. This is why even with continuous increments, the ship never quite reaches "c" but can approach it closely, such as exceeding 0.999c in our problem.
Velocity Increment
Velocity increment is a key factor in our exercise. It refers to the additional speed given to a moving object. In traditional, everyday scenarios, increments simply sum up — but not when close to the speed of light.
Understanding velocity increment through the lens of relativity guides us to the solution of how many increments it takes for the spaceship to exceed 0.999c, drawing from step-by-step increases and applying the relativistic formula iteratively.
- In this exercise, each increment is a significant portion of "c", specifically 0.50c.
- The relativistic velocity addition formula is key to calculating the new velocity after each increment.
Understanding velocity increment through the lens of relativity guides us to the solution of how many increments it takes for the spaceship to exceed 0.999c, drawing from step-by-step increases and applying the relativistic formula iteratively.
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