Problem 76
Question
Verify that equation is an identity. \(\frac{\cos \theta+1}{\tan ^{2} \theta}=\frac{\cos \theta}{\sec \theta-1}\)
Step-by-Step Solution
Verified Answer
The equation is an identity as both sides simplify to the same expression \( \frac{\cos^2 \theta}{1 - \cos \theta} \).
1Step 1: Simplifying the Left Side
Start by rewriting \( \tan^2 \theta \) as \( \frac{\sin^2 \theta}{\cos^2 \theta} \). This gives us the left side of the equation as \( \frac{\cos \theta + 1}{\tan^2 \theta} = \frac{\cos \theta + 1}{\frac{\sin^2 \theta}{\cos^2 \theta}} = \frac{(\cos \theta + 1) \cos^2 \theta}{\sin^2 \theta} \).
2Step 2: Simplifying the Right Side
Now, simplify the right side of the equation. Rewrite \( \sec \theta \) as \( \frac{1}{\cos \theta} \) to get \( \frac{\cos \theta}{\sec \theta - 1} = \frac{\cos \theta}{\frac{1}{\cos \theta} - 1} = \frac{\cos^2 \theta}{1 - \cos \theta} \).
3Step 3: Finding a Common Expression
Both sides should simplify to the same expression. Return to the left side and attempt to manipulate it into the form on the right side. Multiply top and bottom by \( 1 + \cos \theta \), a form often used to rationalize expressions, to obtain \( \frac{(\cos \theta+1)^2 \cos^2 \theta}{\sin^2 \theta} \). Since \( \sin^2 \theta = 1 - \cos^2 \theta \), we rewrite the denominator using the identity \( 1 - \cos^2 \theta = (1 - \cos \theta)(1 + \cos \theta) \).
4Step 4: Verify the Simplification
The expression on the left after simplifying and using identities is \( \frac{(\cos \theta + 1) \cos^2 \theta}{(1 - \cos \theta)(1 + \cos \theta)} \), which further simplifies to \( \frac{\cos^2 \theta}{1 - \cos \theta} \). This is the same expression as obtained for the right side.
5Step 5: Conclusion
Since the expressions for both the left and the right sides of the equation simplify to the same form \( \frac{\cos^2 \theta}{1 - \cos \theta} \), we have verified that the equation is an identity.
Key Concepts
Simplifying Trigonometric ExpressionsVerify Trigonometric IdentitiesTrigonometric Functions
Simplifying Trigonometric Expressions
Simplifying trigonometric expressions involves rewriting them in a more manageable form. This often requires using basic trigonometric identities. These identities allow us to substitute one function for another, simplifying our work. Consider the original expression \( \frac{\cos \theta+1}{\tan ^{2} \theta} \). Here, \( \tan^2 \theta \) is rewritten as \( \frac{\sin^2 \theta}{\cos^2 \theta} \).
This substitution simplifies the expression to \( \frac{\cos \theta + 1}{\frac{\sin^2 \theta}{\cos^2 \theta}} \), further breaking it down to \( \frac{(\cos \theta + 1) \cos^2 \theta}{\sin^2 \theta} \).
It becomes crucial to have a clear understanding of these identities, as they form the cornerstone for simplifying complex trigonometric expressions effectively.
This substitution simplifies the expression to \( \frac{\cos \theta + 1}{\frac{\sin^2 \theta}{\cos^2 \theta}} \), further breaking it down to \( \frac{(\cos \theta + 1) \cos^2 \theta}{\sin^2 \theta} \).
It becomes crucial to have a clear understanding of these identities, as they form the cornerstone for simplifying complex trigonometric expressions effectively.
Verify Trigonometric Identities
Verifying trigonometric identities means proving that two different expressions are equivalent. In this exercise, we aim to show that both sides of the equation have the same value no matter what angle \( \theta \) is.
To verify, we simplify each side independently, using identities. On the right side, \( \sec \theta \) is replaced with \( \frac{1}{\cos \theta} \), transforming the expression to \( \frac{\cos \theta}{\frac{1}{\cos \theta} - 1} \).
Simplifying this results in \( \frac{\cos^2 \theta}{1 - \cos \theta} \).
After simplification, both sides equate to \( \frac{\cos^2 \theta}{1 - \cos \theta} \), verifying the identity. This process shows not only the equivalency but also deepens our understanding of trigonometric relationships.
To verify, we simplify each side independently, using identities. On the right side, \( \sec \theta \) is replaced with \( \frac{1}{\cos \theta} \), transforming the expression to \( \frac{\cos \theta}{\frac{1}{\cos \theta} - 1} \).
Simplifying this results in \( \frac{\cos^2 \theta}{1 - \cos \theta} \).
After simplification, both sides equate to \( \frac{\cos^2 \theta}{1 - \cos \theta} \), verifying the identity. This process shows not only the equivalency but also deepens our understanding of trigonometric relationships.
Trigonometric Functions
Trigonometric functions, such as \( \sin \theta \), \( \cos \theta \), \( \tan \theta \), and \( \sec \theta \), play vital roles in a variety of mathematical problems. They are functions of an angle and provide the foundation for working with trigonometric identities.
For example, the trigonometric function \( \tan \theta \) is defined as the ratio \( \frac{\sin \theta}{\cos \theta} \), while \( \sec \theta \) is \( \frac{1}{\cos \theta} \).
These simple relationships can be the key to solving more complex equations and understanding trigonometric identities.
For example, the trigonometric function \( \tan \theta \) is defined as the ratio \( \frac{\sin \theta}{\cos \theta} \), while \( \sec \theta \) is \( \frac{1}{\cos \theta} \).
These simple relationships can be the key to solving more complex equations and understanding trigonometric identities.
- \( \sin^2 \theta + \cos^2 \theta = 1 \) is one key identity often used to convert expressions.
- Understanding how to manipulate and apply these identities and functions can simplify problem solving significantly.
Other exercises in this chapter
Problem 76
Give the exact real number value of each expression. Do not use a calculator. $$\csc \left(\csc ^{-1} 3\right)$$
View solution Problem 76
Write each expression as a sum or difference of trigonometric functions or values. $$5 \cos 3 x \cos 2 x$$
View solution Problem 77
Give the exact real number value of each expression. Do not use a calculator. $$\tan ^{-1}\left(\tan \frac{5 \pi}{6}\right)$$
View solution Problem 77
Write each expression as a sum or difference of trigonometric functions or values. $$2 \cos 85^{\circ} \sin 140^{\circ}$$
View solution