Problem 76
Question
Use the distributive property to rewrite each expression. $$ -\frac{1}{3}(9 x+5) $$
Step-by-Step Solution
Verified Answer
-3x - \frac{5}{3}
1Step 1 - Identify the Distributive Property
The distributive property states that for any numbers a, b, and c: \[ a(b + c) = ab + ac \]In this case, the expression \[ -\frac{1}{3}(9x + 5) \] can be rewritten by distributing the \[ -\frac{1}{3} \] to both terms inside the parenthesis.
2Step 2 - Distribute to the First Term
Multiply \[ -\frac{1}{3} \] by \[ 9x \]:\[ -\frac{1}{3} \times 9x = -3x \]
3Step 3 - Distribute to the Second Term
Multiply \[ -\frac{1}{3} \] by \[ 5 \]:\[ -\frac{1}{3} \times 5 = -\frac{5}{3} \]
4Step 4 - Combine the Results
Put both parts together to get the final expression:\[ -3x - \frac{5}{3} \]
Key Concepts
distributive propertyalgebraic expressionsmultiplication of fractions
distributive property
Understanding the distributive property is key to solving many algebra problems. The distributive property helps us to simplify multiplication of a single term across a sum or difference inside parentheses. To put it simply, when you have an expression like \(a(b + c)\), you distribute \(a\) to both \(b\) and \(c\).
This results in the equation \(ab + ac\).
In our exercise, we applied the distributive property to the expression \(-\frac{1}{3}(9x + 5)\).
We multiplied \(-\frac{1}{3}\) by each term inside the parentheses separately:
This results in the equation \(ab + ac\).
In our exercise, we applied the distributive property to the expression \(-\frac{1}{3}(9x + 5)\).
We multiplied \(-\frac{1}{3}\) by each term inside the parentheses separately:
- First, \( -\frac{1}{3} \times 9x = -3x\)
- Then, \( -\frac{1}{3} \times 5 = -\frac{5}{3} \)
algebraic expressions
An algebraic expression is a mix of numbers, variables, and arithmetic operations. In the given problem, we started with the algebraic expression \(-\frac{1}{3}(9x + 5)\).
This expression includes:
This expression includes:
- A numerical fraction: \(-\frac{1}{3}\)
- A variable term: \(9x\)
- A constant term: 5
- The variable term became \(-3x\)
- The constant term turned into \(-\frac{5}{3}\)
multiplication of fractions
Multiplying fractions might seem tricky, but it's very straightforward once you get the hang of it. When you multiply fractions, you multiply the numerators together and the denominators together. For example, in our exercise, one of the steps involved multiplying the fraction \(-\frac{1}{3}\) by 9.
To do this, consider 9 as \(\frac{9}{1}\), so the multiplication looks like:
\ \ $$ -\frac{1}{3} \times \frac{9}{1} = -\frac{1 \times 9}{3 \times 1} = -\frac{9}{3} = -3 $$
We also multiplied \(-\frac{1}{3}\) by 5:
Consider 5 as \(\frac{5}{1}\), so the multiplication goes like this:
Breaking down the multiplication of fractions into these simple steps makes it easier to understand and apply in algebraic problems.
To do this, consider 9 as \(\frac{9}{1}\), so the multiplication looks like:
\ \ $$ -\frac{1}{3} \times \frac{9}{1} = -\frac{1 \times 9}{3 \times 1} = -\frac{9}{3} = -3 $$
We also multiplied \(-\frac{1}{3}\) by 5:
Consider 5 as \(\frac{5}{1}\), so the multiplication goes like this:
- \(-\frac{1}{3} \times \frac{5}{1} = -\frac{1 \times 5}{3 \times 1} = -\frac{5}{3}\)
Breaking down the multiplication of fractions into these simple steps makes it easier to understand and apply in algebraic problems.
Other exercises in this chapter
Problem 75
Simplify each expression. \(100[0.05(x+3)]\)
View solution Problem 75
Perform each indicated operation. \(\frac{-5(-6)}{9-(-1)}\)
View solution Problem 76
Find each difference. $$ -4.4-8.6 $$
View solution Problem 76
Simplify each expression. \(100[0.06(x+5)]\)
View solution