Problem 76
Question
Use the Derivative Quotient Rule to prove the Power Rule for negative integers, that is, $$\frac{d}{d x}\left(x^{-m}\right)=-m x^{m-1}$$ where \(m\) is a positive integer.
Step-by-Step Solution
Verified Answer
The Power Rule for negative integers is proven by applying the Quotient Rule.
1Step 1: Recall the Quotient Rule
The derivative quotient rule states: \( \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2} \) where \( u \) and \( v \) are differentiable functions of \( x \).
2Step 2: Express \( x^{-m} \) as a Quotient
We write \( x^{-m} = \frac{1}{x^m} \). Here, let \( u = 1 \) and \( v = x^m \).
3Step 3: Compute Derivatives of \( u \) and \( v \)
For \( u = 1 \), the derivative \( \frac{du}{dx} = 0 \). For \( v = x^m \), the derivative \( \frac{dv}{dx} = m x^{m-1} \) using the power rule for positive integers.
4Step 4: Apply the Quotient Rule
Substitute into the quotient rule: \[\frac{d}{dx} \left( \frac{1}{x^m} \right) = \frac{x^m \cdot 0 - 1 \cdot mx^{m-1}}{(x^m)^2} = \frac{-mx^{m-1}}{x^{2m}}.\]
5Step 5: Simplify the Expression
Simplify the expression obtained:\[\frac{-mx^{m-1}}{x^{2m}} = -m \cdot x^{m-1 - 2m} = -m \cdot x^{-m-1}.\]
6Step 6: Confirm the Power Rule for Negative Exponents
Thus, we have shown that \( \frac{d}{dx}(x^{-m}) = -mx^{-m-1} \), confirming the Power Rule for negative integers.
Key Concepts
Derivative Quotient RulePower RuleNegative IntegersPower Rule for Differentiation
Derivative Quotient Rule
The Derivative Quotient Rule is a fundamental tool in calculus, especially when tackling the differentiation of quotient forms. This rule allows us to find the derivative of a function presented as a ratio of two other functions. Using this rule, if you have a function of the form \( \frac{u}{v} \), where both \( u \) and \( v \) are differentiable, the derivative is expressed as:
- Find the derivative of the numerator \( \frac{du}{dx} \).
- Find the derivative of the denominator \( \frac{dv}{dx} \).
- Apply the formula: \( \frac{d}{dx}\left( \frac{u}{v} \right) = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2} \).
Power Rule
The Power Rule is one of the most commonly used differentiation techniques in calculus. It provides a quick method to find the derivative of polynomial functions. Usually, the Power Rule applies to functions of the form \( x^n \), where \( n \) is any real number, and states that:
- To differentiate \( x^n \), multiply by the exponent \( n \).
- Subtract one from the exponent.
- Thus, the derivative is \( nx^{n-1} \).
Negative Integers
Negative integers often create confusion during differentiation, especially when using the Power Rule. However, understanding that they are nothing more than exponents that signify division helps simplify the process. When dealing with a function like \( x^{-m} \), think of it as \( \frac{1}{x^m} \).
This amounts to:
This amounts to:
- First, rewrite the negative exponent term as a fraction.
- Then differentiate using techniques like the Quotient Rule, if necessary.
Power Rule for Differentiation
The Power Rule for Differentiation extends beyond simple positive integers and applies to negative integers and other real numbers as well. This comprehensive rule helps calculate derivatives across a wide range of functions, ensuring consistency in solutions.
- Multiplier the exponent by the base to get the first part of the derivative.
- Subtract one from the exponent.
- Thus, derivatives such as \( x^{-m} \) follow the rule and simplify to \(-mx^{-m-1} \).
Other exercises in this chapter
Problem 76
Find the derivative of \(y\) with respect to the given independent variable. $$y=\log _{25} e^{x}-\log _{5} \sqrt{x}$$
View solution Problem 76
Find \(y^{\prime \prime}\) in Exercises \(71-78\). $$y=x^{2}\left(x^{3}-1\right)^{5}$$
View solution Problem 77
Find the derivative of \(y\) with respect to the given independent variable. $$y=\log _{2} r \cdot \log _{4} r$$
View solution Problem 78
Find the derivative of \(y\) with respect to the given independent variable. $$y=\log _{3} r \cdot \log _{9} r$$
View solution