Problem 76
Question
Use both the addition and multiplication properties of inequality to solve each inequality and graph the solution set on a number line. $$7-2(x-4)<5(1-2 x)$$
Step-by-Step Solution
Verified Answer
In short, the solution for given inequality is \( x<-5/6 \), and its solution set can be represented on the number line with a ray starting from \( -5/6 \) and extending to the left excluding \( -5/6 \).
1Step 1: Expand the inequality
Begin by expanding the inequality by distributing \( -2 \) to \( (x-4) \) and \( 5 \) to \( (1-2x) \). It gives us the inequality, \( 7-2x+8<5-10x \).
2Step 2: Simplify the inequality
Combine like terms on each side of the inequality which leads to \( 15+2x<5-10x \).
3Step 3: Isolate the term with x on one side of the inequality
To do this, add \( 10x \) to both sides of the equation giving us \( 15+12x<5 \).
4Step 4: Further Isolate x
Subtract \( 15 \) from both side leads to \( 12x<-10 \).
5Step 5: Solve for x
Finally, divide both sides by \( 12 \) to find the value of \( x \). This gives \( x<-10/12 \) or \( x<-5/6 \).
6Step 6: Graph the solution set
On a number line, we represent all the numbers less than \( -5/6 \). The solution will be a ray that starts at point \( -5/6 \) and extends to the left. The point \( -5/6 \) is not included in the solution set, so we use an open circle.
Key Concepts
Addition Property of InequalityMultiplication Property of InequalityGraphing InequalitiesNumber Line Representation
Addition Property of Inequality
Inequalities are quite similar to equations, and you often manipulate them using rules that closely resemble arithmetic operations. The addition property of inequality is one such rule. This principle states that if you add or subtract the same number from both sides of an inequality, the inequality's direction does not change. For example, if you have an inequality: - \( a < b \) Then by adding \( c \) to both sides, the inequality remains: - \( a + c < b + c \) This property is particularly useful when you want to isolate a variable on one side of an inequality. You can move a term from one side to the other by adding or subtracting it, just as you would in an equation.
- Important: When shifting terms, be sure to perform the same operation on both sides of the inequality.
Multiplication Property of Inequality
Multiplication is another crucial operation when dealing with inequalities. The multiplication property of inequality states that the inequality's direction remains unchanged when you multiply or divide both sides by a positive number. However, when you multiply or divide both sides by a negative number, you must reverse the inequality's direction to maintain its logic. Here's a basic breakdown:
- If \( a < b \) and you multiply by a positive \( c \) (where \( c > 0 \)), then \( ac < bc \).
- But if you multiply by a negative \( c \) (where \( c < 0 \)), the inequality reverses, so \( ac > bc \).
Graphing Inequalities
Visualizing inequalities can greatly aid understanding, and graphing them is a common method for this. Graphing begins by solving the inequality algebraically, finding values that satisfy it. Once you've isolated the variable (like \( x \) in our exercise), you can represent this solution using a graph on a number line.
- For instance, if \( x < -\frac{5}{6} \): this means \( x \) can take any value smaller than \( -\frac{5}{6} \).
- If the inequality were \( \leq \) or \( \geq \), the point would include a filled circle, indicating the endpoint is part of the solution.
Number Line Representation
A number line is a simple yet powerful visual tool for representing solutions of inequalities. Using a number line, you can precisely show ranges of numbers that satisfy an inequality. Here's the step-by-step of how we represent our exercise's solution:
- Identify the key point, which is \( -\frac{5}{6} \).
- Use an open circle at \( -\frac{5}{6} \) since numbers strictly less than this point are included in the solution.
- Draw a ray extending leftwards from the open circle to indicate that every number less than \( -\frac{5}{6} \) meets the inequality's requirement.
Other exercises in this chapter
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