Problem 76
Question
The paramagnetism of \(\mathrm{O}_{2}{\underline{\phantom{xx}}}^{+}\)is due to the presence of an odd electron in the MO (a) \(\sigma^{*} 2 \mathrm{~s}\) (b) \(\pi 2 p y\) (c) \(\sigma^{*} 2 p x\) (d) \(\pi^{*} 2 \mathrm{py}\)
Step-by-Step Solution
Verified Answer
The paramagnetism is due to the presence of an odd electron in \( \pi^{*} 2 \mathrm{py} \).
1Step 1: Understanding Paramagnetism
Paramagnetism occurs in molecules due to the presence of unpaired electrons. Therefore, to determine the paramagnetism in \( \mathrm{O}_{2}^{+} \), we need to identify which molecular orbital has an unpaired electron.
2Step 2: Writing the Electron Configuration
\( \mathrm{O}_{2} \) has the molecular orbital configuration of: \( \sigma_{1s}^{2} \sigma^{*}_{1s}^{2} \sigma_{2s}^{2} \sigma^{*}_{2s}^{2} \sigma_{2p}^{2} \pi_{2p}^{4} \pi^{*}_{2p}^{2} \). \( \mathrm{O}_{2}^{+} \) means removing one electron from \( \pi^{*}_{2p} \) orbitals because they have the highest energy.
3Step 3: Identify the Orbital with the Odd Electron
After removing one electron from \( \pi^{*}_{2p} \) orbitals, \( \mathrm{O}_{2}^{+} \) will be left with one unpaired electron in \( \pi^{*}_{2p} \) orbitals. The unpaired electron in \( \pi^{*}_{2p} \) orbital is responsible for paramagnetism.
4Step 4: Conclusion
The odd electron in \( \mathrm{O}_{2}^{+} \) resides in the \( \pi^{*}_{2p} \) orbital, specifically in the \( \pi^{*} 2 \mathrm{py} \) or \( \pi^{*} 2 \mathrm{px} \) depending on notation.
Key Concepts
Molecular Orbital TheoryElectron ConfigurationUnpaired Electrons
Molecular Orbital Theory
Molecular Orbital Theory is a fundamental concept in chemistry that describes the behavior of electrons in a molecule. Unlike atomic orbital theory, which focuses on individual atoms, molecular orbital (MO) theory considers the molecule as a whole.
It assumes that atomic orbitals combine to form molecular orbitals when atoms bond together. This allows electrons to be more delocalized across the molecule rather than being confined to a particular atom.
Molecular orbitals are divided into bonding and antibonding orbitals:
It assumes that atomic orbitals combine to form molecular orbitals when atoms bond together. This allows electrons to be more delocalized across the molecule rather than being confined to a particular atom.
Molecular orbitals are divided into bonding and antibonding orbitals:
- Bonding orbitals result from the constructive combination of atomic orbitals. They have lower energy and contribute to the stability of a molecule.
- Antibonding orbitals occur when atomic orbitals combine destructively. They have higher energy and, if occupied by electrons, can destabilize a molecule.
Electron Configuration
Electron configuration is the arrangement of electrons in the orbitals of an atom or molecule. It's important because it affects how an element or compound behaves chemically.
To write the electron configuration for a molecule like \( \mathrm{O}_2 \), we follow the order of increasing energy of the molecular orbitals:
To write the electron configuration for a molecule like \( \mathrm{O}_2 \), we follow the order of increasing energy of the molecular orbitals:
- \(\sigma_{1s}^2\sigma^{*}_{1s}^2\) indicates the inner core electrons.
- \(\sigma_{2s}^2\sigma^{*}_{2s}^2\) represents the next level, including the non-bonding electrons.
- The \(\sigma_{2p}^2\pi_{2p}^4\pi^{*}_{2p}^2\) shows the configuration of electrons in the bonding and antibonding orbitals.
Unpaired Electrons
Unpaired electrons are essential when discussing the magnetic properties of a molecule. They occur when there's an electron in an orbital without a partner with opposite spin.
In the context of \(\mathrm{O}_2^{+}\), when one electron is removed from the \(\pi^{*}_{2p}\) molecular orbitals, it results in one unpaired electron.
These unpaired electrons cause the molecule to be paramagnetic. Paramagnetic materials have at least one unpaired electron and are attracted to magnetic fields.
In the context of \(\mathrm{O}_2^{+}\), when one electron is removed from the \(\pi^{*}_{2p}\) molecular orbitals, it results in one unpaired electron.
These unpaired electrons cause the molecule to be paramagnetic. Paramagnetic materials have at least one unpaired electron and are attracted to magnetic fields.
- In contrast, diamagnetic substances have no unpaired electrons and repel magnetic fields.
Other exercises in this chapter
Problem 74
Bond angle in \(\mathrm{XeO}_{3}\) is (a) \(107^{\circ}\) (b) \(119^{\circ}\) (c) \(92^{\circ}\) (d) \(103^{\circ}\)
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Which of the following molecule is planar? (a) \(\mathrm{CH}_{4}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{C}_{2} \mathrm{H}_{4}\) (d) \(\mathrm{SiCl}_{4}\)
View solution Problem 77
Among the following compound which one has maximum number of lone pairs of electrons on central atom (a) \(\left[\mathrm{ClO}_{3}\right]\) (b) \(\mathrm{XeF}_{4
View solution Problem 78
The acid having \(\mathrm{O}-\mathrm{O}\) bond is (a) \(\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) (b) \(\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{6}\) (c
View solution