Problem 76
Question
The letters \(x\) and \(y\) represent rectangular coordinates. Write each equation using polar coordinates \((r, \theta) .\) $$ 4 x^{2} y=1 $$
Step-by-Step Solution
Verified Answer
The polar form of the equation is \( r = \sqrt[3]{\frac{1}{4 \cos^2(\theta) \sin(\theta)}} \).
1Step 1: Identify rectangular coordinate equations
The given equation in rectangular coordinates is \( 4x^2 y = 1 \).
2Step 2: Recall the conversion formulas
Recall that the conversions from rectangular coordinates to polar coordinates are: \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \).
3Step 3: Substitute the polar coordinates
Substitute \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \) into the given equation. This results in: \( 4 (r \cos(\theta))^2 (r \sin(\theta)) = 1 \).
4Step 4: Simplify the equation
Simplify the substituted equation: \( 4 r^2 \cos^2(\theta) \cdot r \sin(\theta) = 1 \). Combine like terms to get \( 4 r^3 \cos^2(\theta) \sin(\theta) = 1 \).
5Step 5: Solve for \( r \)
Isolate \( r \) by dividing both sides by \( 4 \cos^2(\theta) \sin(\theta) \): \( r^3 = \frac{1}{4 \cos^2(\theta) \sin(\theta)} \). Take the cube root of both sides to solve for \( r \): \( r = \sqrt[3]{\frac{1}{4 \cos^2(\theta) \sin(\theta)}} \).
Key Concepts
rectangular coordinatescoordinate conversiontrigonometric identitiespolar equations
rectangular coordinates
Rectangular coordinates, also known as Cartesian coordinates, use two values, usually denoted as \(x\) and \(y\), to describe a point on a plane. The \(x\)-coordinate specifies the horizontal position, while the \(y\)-coordinate specifies the vertical position. Together, they form a pair \((x, y)\) that uniquely identifies a location on the plane.
Rectangular coordinates are familiar because they align with our daily experience of moving left-right and up-down. Cartesian systems are used in many fields for plotting points, graphing equations, and analyzing geometric shapes.
In mathematical expressions, functions can be written in terms of \(x\) and \(y\). For example, the given function \(4x^2 y = 1\) is expressed using rectangular coordinates.
Rectangular coordinates are familiar because they align with our daily experience of moving left-right and up-down. Cartesian systems are used in many fields for plotting points, graphing equations, and analyzing geometric shapes.
In mathematical expressions, functions can be written in terms of \(x\) and \(y\). For example, the given function \(4x^2 y = 1\) is expressed using rectangular coordinates.
coordinate conversion
When converting from rectangular coordinates to polar coordinates, we remodel the point \((x, y)\) into a form that uses the distance from the origin \((r)\) and the angle from the positive \(x\)-axis \((\theta)\). This transformation involves:
In the exercise, we started with an equation in rectangular coordinates, \( 4x^2 y = 1 \). In order to convert it, we substituted \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \), transforming the equation step-by-step.
The goal is to attain an equation purely in terms of \(r\) and \(\theta\) by applying these conversion formulas.
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
In the exercise, we started with an equation in rectangular coordinates, \( 4x^2 y = 1 \). In order to convert it, we substituted \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \), transforming the equation step-by-step.
The goal is to attain an equation purely in terms of \(r\) and \(\theta\) by applying these conversion formulas.
trigonometric identities
Trigonometric identities are mathematical equations that relate angles to side ratios in right triangles. These identities are very useful in transforming and simplifying expressions involving trigonometric functions. The most common trigonometric identities involve sine and cosine functions:
- \( \sin^2(\theta) + \cos^2(\theta) = 1 \)
- \( \cos(2\theta) = \cos^2(\theta) - \sin^2(\theta)\)
- \( \sin(2\theta) = 2 \sin(\theta) \cos(\theta)\)
polar equations
Polar equations use polar coordinates \((r, \theta)\) instead of rectangular coordinates \((x, y)\). In polar form, equations are often simpler to analyze due to the nature of the radial and angular components.
In the given exercise, the rectangular equation \(4x^2 y = 1\) was converted into a polar equation. By substituting \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \), the equation became \( 4 r^3 \cos^2(\theta) \sin(\theta) = 1 \).
Simplifying it further led us to \( r = \sqrt[3]{\frac{1}{4 \cos^2(\theta) \sin(\theta)}} \). This form directly relates the radius \(r\) to the angle \(\theta\), giving a clear and concise representation of the relationship between the variables.
In the given exercise, the rectangular equation \(4x^2 y = 1\) was converted into a polar equation. By substituting \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \), the equation became \( 4 r^3 \cos^2(\theta) \sin(\theta) = 1 \).
Simplifying it further led us to \( r = \sqrt[3]{\frac{1}{4 \cos^2(\theta) \sin(\theta)}} \). This form directly relates the radius \(r\) to the angle \(\theta\), giving a clear and concise representation of the relationship between the variables.
Other exercises in this chapter
Problem 75
A child pulls a wagon with a force of 40 pounds. The handle of the wagon makes an angle of \(30^{\circ}\) with the ground. Express the force vector \(\mathbf{F}
View solution Problem 75
Graph each polar equation. $$ r=\frac{1}{3-2 \cos \theta} \quad(\text {ellipse}) $$
View solution Problem 76
A man pushes a wheelbarrow up an incline of \(20^{\circ}\) with a force of 100 pounds. Express the force vector \(\mathbf{F}\) in terms of \(\mathbf{i}\) and \(
View solution Problem 76
Graph each polar equation. $$ r=\frac{1}{1-\cos \theta} \quad(\text {parabola}) $$
View solution