Problem 76
Question
Simplify. $$ \log _{11}(11)^{-1} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-1\).
1Step 1: Understanding the Problem
The expression to simplify is \( \log_{11}(11)^{-1} \). Here, we have a logarithm with base 11 and the argument \((11)^{-1}\). The goal is to simplify this expression.
2Step 2: Using Logarithm Property
Apply the logarithm power rule: \( \log_b (a^c) = c \cdot \log_b a \). In our case, \(a = 11\), \(c = -1\), and \(b = 11\). Therefore, \( \log_{11}(11)^{-1} = -1 \cdot \log_{11} 11\).
3Step 3: Simplifying Further
Recognize that \( \log_b b = 1 \) for any positive \(b\). Hence, \( \log_{11} 11 = 1 \). Substitute back to get: \(-1 \cdot 1 = -1\).
4Step 4: Conclusion
Thus, the simplified form of the expression \( \log_{11}(11)^{-1} \) is \(-1\).
Key Concepts
Logarithm PropertiesBase of a LogarithmSimplifying Expressions
Logarithm Properties
Logarithms have several useful properties that help in simplifying expressions, such as the power rule, product rule, and quotient rule.
In our exercise, we use the power rule, which states:
By applying this to the expression \( \log_{11}(11)^{-1} \), we recognize \( a = 11 \), \( c = -1 \), and \( b = 11 \). Therefore, using the power rule, the expression becomes \(-1 \cdot \log_{11} 11\).
This brings us to another basic property:
In our exercise, we use the power rule, which states:
- \( \log_b (a^c) = c \cdot \log_b a \)
By applying this to the expression \( \log_{11}(11)^{-1} \), we recognize \( a = 11 \), \( c = -1 \), and \( b = 11 \). Therefore, using the power rule, the expression becomes \(-1 \cdot \log_{11} 11\).
This brings us to another basic property:
- The identity \( \log_b b = 1 \).
Base of a Logarithm
The base of a logarithm is a critical component because it tells us the number in terms of which we are expressing the power. For example, in \( \log_{11}(11)^{-1} \), 11 is the base.
The base is always a positive number, except the special case where the logarithm base \(e\) leads to natural logarithms. In many logarithmic expressions, recognizing the base can make simplification much easier.
The base is always a positive number, except the special case where the logarithm base \(e\) leads to natural logarithms. In many logarithmic expressions, recognizing the base can make simplification much easier.
- For instance, if the base and the argument (the number next to the base) are the same, then by property \( \log_b b^c = c \), it simplifies the process greatly.
- Another example is \( \log_b b \), which equals to 1. This identity is exactly what's used when simplifying \( \log_{11} 11 \).
Simplifying Expressions
Simplifying logarithmic expressions is an important skill that allows you to work with and transform logarithmic identities and equations into simpler forms.
To simplify \( \log_{11}(11)^{-1} \): start with identifying properties of logarithms, such as the power rule and base-argument relationships. Use these properties:
To simplify \( \log_{11}(11)^{-1} \): start with identifying properties of logarithms, such as the power rule and base-argument relationships. Use these properties:
- Apply the power rule: \( \log_b (a^c) = c \cdot \log_b a \). In this case, our expression becomes \(-1 \cdot \log_{11} 11\).
- Use the identity \( \log_{11} 11 = 1 \), derived from \( \log_b b = 1 \). Now your expression simplifies further to \(-1 \cdot 1\), which results in \(-1\).
Other exercises in this chapter
Problem 75
The Richter scale measures the intensity, or magnitude, of an earthquake. The formula for the magnitude \(R\) of an earthquake is \(R=\log \left(\frac{a}{T}\rig
View solution Problem 75
Determine whether each statement is true or false. $$ \frac{\log _{7} 10}{\log _{7} 5}=\log _{7} 2 $$
View solution Problem 76
The Richter scale measures the intensity, or magnitude, of an earthquake. The formula for the magnitude \(R\) of an earthquake is \(R=\log \left(\frac{a}{T}\rig
View solution Problem 76
Determine whether each statement is true or false. $$ \log _{7} \frac{14}{8}=\log _{7} 14-\log _{7} 8 $$
View solution