Problem 76
Question
Simplify each expression. Write answers using positive exponents. a. \(\left(2^{\sqrt{3}}\right)^{\sqrt{3}}\) b. \(7^{\sqrt{3}} 7^{\sqrt{12}}\) c. \(\frac{5^{6 \sqrt{2}}}{5^{4 \sqrt{2}}}\) d. \(5^{-\sqrt{5}}\)
Step-by-Step Solution
Verified Answer
a. 8, b. \(7^{3\sqrt{3}}\), c. \(5^{2\sqrt{2}}\), d. \(\frac{1}{5^{\sqrt{5}}}\)
1Step 1: Simplify the first expression
The expression is \( (2^{\sqrt{3}})^{\sqrt{3}} \). To simplify, use the power of a power property: \((a^m)^n = a^{m \cdot n}\). So, \((2^{\sqrt{3}})^{\sqrt{3}} = 2^{\sqrt{3} \cdot \sqrt{3}} = 2^3 = 8\).
2Step 2: Simplify the second expression
The expression is \( 7^{\sqrt{3}} \times 7^{\sqrt{12}} \). Use the product of powers property: \(a^m \cdot a^n = a^{m+n}\). Combine the exponents: \(\sqrt{3} + \sqrt{12}\). Recognize \(\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3}\). This gives \(7^{\sqrt{3} + 2\sqrt{3}} = 7^{3\sqrt{3}}\).
3Step 3: Simplify the third expression
The expression is \( \frac{5^{6 \sqrt{2}}}{5^{4 \sqrt{2}}} \). Use the quotient of powers property: \(\frac{a^m}{a^n} = a^{m-n}\). Subtract the exponents: \(6\sqrt{2} - 4\sqrt{2} = 2\sqrt{2}\). The simplified form is \(5^{2\sqrt{2}}\).
4Step 4: Simplify the fourth expression
The expression is \(5^{-\sqrt{5}}\). To express it with a positive exponent, use the property \(a^{-n} = \frac{1}{a^n}\). Thus, \(5^{-\sqrt{5}} = \frac{1}{5^{\sqrt{5}}}\).
Key Concepts
Power of a Power PropertyProduct of Powers PropertyQuotient of Powers PropertyNegative Exponents
Power of a Power Property
When you see an expression raised to another power, like \((a^m)^n\), you use the power of a power property to simplify. This rule tells us that you multiply the exponents: \((a^m)^n = a^{m \cdot n}\). This works because you're essentially considering \(a^m\) repeated \(n\) times.
This concept is useful to simplify expressions like \((2^{\sqrt{3}})^{\sqrt{3}}\). Here, you multiply \(\sqrt{3} \times \sqrt{3}\), which gives \(\sqrt{3}^2\), and since \(\sqrt{3}^2 = 3\), the expression becomes \(2^3 = 8\). It’s a straightforward process once you recognize how to multiply the exponents.
This concept is useful to simplify expressions like \((2^{\sqrt{3}})^{\sqrt{3}}\). Here, you multiply \(\sqrt{3} \times \sqrt{3}\), which gives \(\sqrt{3}^2\), and since \(\sqrt{3}^2 = 3\), the expression becomes \(2^3 = 8\). It’s a straightforward process once you recognize how to multiply the exponents.
Product of Powers Property
You often encounter expressions where the same base is multiplied, such as \(a^m \cdot a^n\). In these situations, use the product of powers property: simply add the exponents: \(a^m \cdot a^n = a^{m+n}\).
For example, simplifying \(7^{\sqrt{3}} \times 7^{\sqrt{12}}\) requires adding the exponents. Recognizing \(\sqrt{12} = 2\sqrt{3}\) helps. Then, \(\sqrt{3} + 2\sqrt{3} = 3\sqrt{3}\), so you get \(7^{3\sqrt{3}}\). It’s all about identifying parts and adding the exponents properly.
For example, simplifying \(7^{\sqrt{3}} \times 7^{\sqrt{12}}\) requires adding the exponents. Recognizing \(\sqrt{12} = 2\sqrt{3}\) helps. Then, \(\sqrt{3} + 2\sqrt{3} = 3\sqrt{3}\), so you get \(7^{3\sqrt{3}}\). It’s all about identifying parts and adding the exponents properly.
Quotient of Powers Property
When you divide expressions with the same base, like \(\frac{a^m}{a^n}\), apply the quotient of powers property: subtract the exponents: \(a^{m-n}\). This subtraction works because dividing is the reverse of multiplying, which corresponds to exponents subtraction.
Consider \(\frac{5^{6 \sqrt{2}}}{5^{4 \sqrt{2}}}\). By subtracting the exponents, \(6\sqrt{2} - 4\sqrt{2}\), we find \(2\sqrt{2}\). Thus, the expression simplifies to \(5^{2\sqrt{2}}\). Keep the same base and rely on subtraction for simplification.
Consider \(\frac{5^{6 \sqrt{2}}}{5^{4 \sqrt{2}}}\). By subtracting the exponents, \(6\sqrt{2} - 4\sqrt{2}\), we find \(2\sqrt{2}\). Thus, the expression simplifies to \(5^{2\sqrt{2}}\). Keep the same base and rely on subtraction for simplification.
Negative Exponents
Expressions with negative exponents represent the inverse, or reciprocal. For any base \(a\), the rule \(a^{-n} = \frac{1}{a^n}\) applies. This turns the expression into its reciprocal form, making the exponent positive.
Look at \(5^{-\sqrt{5}}\). By using the property, it becomes \(\frac{1}{5^{\sqrt{5}}}\). Transform any negative exponent using this reciprocal approach, which makes equations easier to handle without negative powers.
Look at \(5^{-\sqrt{5}}\). By using the property, it becomes \(\frac{1}{5^{\sqrt{5}}}\). Transform any negative exponent using this reciprocal approach, which makes equations easier to handle without negative powers.
Other exercises in this chapter
Problem 76
Solve each equation. Give the exact solution and, when appropriate, an approximation to four decimal places. $$ \log x^{3}=3 $$
View solution Problem 76
Let \(f(x)=x^{2}-1\) and \(g(x)=x^{2}-4 .\) Find each function and give its domain. $$ g \cdot f $$
View solution Problem 76
Write in words how to read the notation. a. \(f^{-1}(x)=\frac{1}{2} x-3\) b. \(\left(f \circ f^{-1}\right)(x)=x\)
View solution Problem 76
Write logarithmic expression as one logarithm. \(2 \log x+\frac{1}{2} \log y\)
View solution