Problem 76
Question
In Exercises 73 - 78, find a quadratic model for the sequence with the indicated terms. \( a_0 = 3, a_2 = 0, a_6 = 36 \)
Step-by-Step Solution
Verified Answer
The quadratic model for the given sequence is \(y = x^2 - 3x + 3\)
1Step 1: Set up the system of equations
The three equations derived from the sequences and the model form \(ax^2+bx+c\) are: \\ For \(a_0 = 3\), substitute \(x=0\) in model equation, we have equation (1) as \(a(0)^2+b(0)+c=3\) or \(c=3\) \\ For \(a_2 = 0\), substitute \(x=2\) in model equation, we have equation (2) as \(a(2)^2+b(2)+c=0\) or \(4a+2b+c=0\) \\ For \(a_6 = 36\), substitute \(x=6\) in model equation, we have equation (3) as \(a(6)^2+b(6)+c=36\) or \(36a+6b+c=36\)
2Step 2: Solve the system of equations
We have \(c=3\) from the first equation, we can substitute this into second equation (2) and equation (3) to solve for \(a\) and \(b\). After substitution, equation (2) now reads \(4a+2b+3=0\), simplified to \(2a+b=-1\). Substituting into equation (3) gives \(36a+6b+3=36\), simplified to \(6a+b=5\). Solving these two equations simultaneously gives\[a=1, b=-3\]
3Step 3: Write the quadratic model equation
The coefficients \(a\), \(b\), and \(c\) in the quadratic model are now known. So the quadratic model is \(y=ax^2+bx+c\), by substituting the values of \(a\), \(b\), and \(c\), the equation becomes \(y=x^2-3x+3\)
Key Concepts
Quadratic ModelSystem of EquationsSolving Quadratic Equations
Quadratic Model
A quadratic model is an equation that offers a way to represent a particular set of data or sequence using a quadratic function. It's particularly useful when the data exhibits a parabolic trend. Each quadratic model is expressed in the standard form:\[ y = ax^2 + bx + c \]Here, \(a\), \(b\), and \(c\) are coefficients that determine the shape and position of the parabola. The quadratic model is essential in various fields like physics, economics, and engineering to predict and analyze data patterns.
To find a quadratic model for a given sequence, we typically need at least three points. For the exercise, the points given were \( a_0 = 3, a_2 = 0, a_6 = 36 \). By substituting these points into the quadratic equation model, you can generate a system of equations to solve for \(a\), \(b\), and \(c\). This model captures the trend or pattern in the sequence data.
To find a quadratic model for a given sequence, we typically need at least three points. For the exercise, the points given were \( a_0 = 3, a_2 = 0, a_6 = 36 \). By substituting these points into the quadratic equation model, you can generate a system of equations to solve for \(a\), \(b\), and \(c\). This model captures the trend or pattern in the sequence data.
System of Equations
A system of equations involves multiple equations that are solved together since they share common variables. In the context of finding a quadratic model, we derive these equations by inserting known values of \(x\) and their corresponding outputs (like \(a_0 = 3\)) into our quadratic model:- For \(a_0 = 3\), substituting in gives: \(c=3\)- For \(a_2 = 0\), substituting in gives: \(4a + 2b + c = 0\)- For \(a_6 = 36\), substituting in gives: \(36a + 6b + c = 36\)These equations are simultaneously solved to find the values of \(a\), \(b\), and \(c\). Solving a system of equations typically requires either substitution or elimination methods. The system helps find a unique set of values that satisfy all the given equations, allowing us to construct our quadratic model.
Solving Quadratic Equations
Solving quadratic equations is a fundamental part of mathematics that involves finding the values of the variable that make the equation true. Once we've substituted point values into the quadratic model, we're left with a system of linear equations. The steps involved in solving these equations include:
- Substitution of known values: e.g., since \(c = 3\), we replace \(c\) in other equations.
- Elimination or substitution: reduce the system to isolate one variable.
- Solve for the unknowns: Solve the simplified equations, yielding values for \(a\), \(b\), and \(c\).
Other exercises in this chapter
Problem 76
In Exercises 73 - 76, find the number of diagonals of the polygon. (A line segment connecting any two non adjacent vertices is called a diagonal of the polygon.
View solution Problem 76
In Exercises 73 - 78, use the Binomial Theorem to expand the complex number. Simplify your result. \( \left(5 + \sqrt{-9}\right)^3 \)
View solution Problem 76
In Exercises 67 - 86, find the sum of the finite geometric sequence. \( \sum_{n=0}^{40}5\left(\dfrac{3}{5}\right)^n \)
View solution Problem 76
In Exercises 71-76, write the first five terms of the sequence. (Assume that \( n \) begins with 0.) \( a_n = \dfrac{(-1)^{2n + 1}}{(2n + 1)!} \)
View solution