Problem 76
Question
Half-life of radioactive \({ }^{14} \mathrm{C}\) is 5760 years. In how many years, \(200 \mathrm{mg}\) of \({ }^{14} \mathrm{C}\) will be reduced to \(25 \mathrm{mg}\) ? (a) 5760 years (b) 11520 years (c) 17280 years (d) 23040 years
Step-by-Step Solution
Verified Answer
It will take 17280 years for 200 mg of \(^{14}C\) to reduce to 25 mg.
1Step 1: Understanding the Half-Life Formula
The half-life formula is essential for calculating the time required for a radioactive substance to decay to a certain amount. The formula is \( N = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}} \), where \( N \) is the remaining quantity, \( N_0 \) is the initial quantity, \( T_{1/2} \) is the half-life period, and \( t \) is the time elapsed.
2Step 2: Identifying Given and Required Values
We are given the initial quantity \( N_0 = 200 \) mg, the remaining quantity \( N = 25 \) mg, and the half-life \( T_{1/2} = 5760 \) years. We need to find the time \( t \) it takes for the substance to reduce to 25 mg.
3Step 3: Setting Up the Equation
Using the half-life formula: \( 25 = 200 \left( \frac{1}{2} \right)^{\frac{t}{5760}} \). We need to solve for \( t \).
4Step 4: Solving for the Power of 1/2
Rearranging the equation gives us: \( \left( \frac{1}{2} \right)^{\frac{t}{5760}} = \frac{25}{200} = \frac{1}{8} \). This implies\( \left( \frac{1}{2} \right)^3 = \frac{1}{8} \).
5Step 5: Equating the Exponents
Since the powers of \( \frac{1}{2} \) are equal, we can equate the exponents: \( \frac{t}{5760} = 3 \).
6Step 6: Calculating the Time
Solving for \( t \) gives \( t = 5760 \times 3 = 17280 \) years.
7Step 7: Final Answer
The time it takes for the substance to decay from 200 mg to 25 mg is \( 17280 \) years.
Key Concepts
Half-Life CalculationCarbon-14 DecayHalf-Life Formula
Half-Life Calculation
Calculating the half-life of a radioactive substance is crucial in understanding how long it takes for it to decay to a certain amount. Half-life is the time period required for half of the radioactive atoms in a sample to decay. To calculate the time for a quantity to decay to a specific amount, you need the initial amount, the remaining amount, and the half-life of the substance.
Here's how you approach it:
Here's how you approach it:
- Identify the initial amount (0) and the remaining amount (1).
- Use the half-life formula: \[ N = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}} \] where \(N\) is the remaining amount, \(N_0\) is the initial amount, \(T_{1/2}\) is the half-life, and \(t\) is the elapsed time.
- Rearrange the formula to solve for time \(t\) when \(N\) and \(N_0\) are known. This involves equating the exponents and solving for \(t\).
Carbon-14 Decay
Carbon-14 is a naturally occurring radioactive isotope of carbon, which is used extensively in radiocarbon dating. This method is commonly used to date historical artifacts and archaeological findings.
Carbon-14 decays at a consistent rate, with a half-life of approximately 5760 years. This means every 5760 years, half of the carbon-14 in a sample will have decayed. The stable decay rate allows scientists to determine the age of objects by measuring the remaining carbon-14 content.
Some key points about carbon-14 decay include:
Carbon-14 decays at a consistent rate, with a half-life of approximately 5760 years. This means every 5760 years, half of the carbon-14 in a sample will have decayed. The stable decay rate allows scientists to determine the age of objects by measuring the remaining carbon-14 content.
Some key points about carbon-14 decay include:
- It is produced in the atmosphere and is absorbed by living organisms.
- When the organism dies, it stops absorbing carbon-14, and the existing carbon-14 starts to decay.
- The decay follows the same exponential decay pattern as other radioactive isotopes.
Half-Life Formula
The half-life formula is a powerful tool in the study of radioactive decay as it describes how quantities diminish over time.
This formula is given by:\[ N = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}} \]Here, the formula components are:
This formula is given by:\[ N = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}} \]Here, the formula components are:
- \(N\) = remaining quantity after time \(t\)
- \(N_0\) = initial quantity
- \(T_{1/2}\) = half-life period, the time taken for the quantity to reduce to half
- \(t\) = total time elapsed
Other exercises in this chapter
Problem 74
The disintegration constant of a radioactive isotope whose half-life is 3 hours is (a) \(1.57\) per hour (b) \(1.92\) per hour (c) \(1.04\) per hour (d) \(0.231
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The half-life of a radioactive element is 40 days. Calculate the average life. (a) \(5.76\) days (b) \(57.6\) days (c) 646 days (d) \(4.56\) days
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One microgram of radioactive sodium \({ }_{11} \mathrm{Na}^{24}\) with a half- life of 15 hours was injected into a living system for a bio assay. How long will
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The half-life of a radioactive nuclide is \(0.693\) minutes. The time (in minutes) required for the disintegration of this nuclide from 10 grams to one gram is
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