Problem 76
Question
For the following problems, add or subtract the rational expressions. $$ \frac{x+2}{12 x^{3}}+\frac{x+1}{4 x^{2}+8 x-12}-\frac{x+3}{16 x^{2}-32 x+16} $$
Step-by-Step Solution
Verified Answer
Answer: $$\frac{6x^4 - 3x^3x^2 + 3x^3 + 4x^2 + 12x - 8}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}$$
1Step 1: Factor the denominators of rational expressions
First, we need to factor the denominators of each rational expression. This will help us find the least common denominator (LCD) for all the expressions.
For the first expression, the denominator is already factored: \(12x^3 = 2^2 \cdot 3 \cdot x^3\)
For the second expression, first factor the common factor and then factor the remaining quadratic expression:
$$
4x^2 + 8x - 12 = 4(x^2+2x-3) = 4(x+3)(x-1)
$$
For the third expression, first factor the common factor:
$$
16x^2 - 32x + 16 = 16(x^2-2x+1) = 16(x-1)^2
$$
2Step 2: Determine the Least Common Denominator (LCD)
Now we need to find the LCD for all the denominators. The LCD will be the product of the highest powers of each unique factor from the three denominators.
$$
\text{LCD} = 2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)
$$
3Step 3: Write each rational expression with the LCD as the denominator
Next, we need to rewrite each rational expression with the LCD as the denominator. To do this, we'll multiply each expression by the missing factors from the LCD.
$$
\frac{x+2}{12 x^{3}}\cdot \frac{2^2 \cdot (x+3)(x-1)}{2^2 \cdot (x+3)(x-1)} + \frac{x+1}{4 (x+3)(x-1)}\cdot \frac{2^3\cdot 3\cdot x^3}{2^3\cdot 3\cdot x^3} - \frac{x+3}{16(x-1)^2} \cdot \frac{3x^3(x+3)}{3x^3(x+3)}
$$
4Step 4: Simplify and add/subtract the rational expressions
After rewriting each expression with the same denominator, we can combine the numerators and simplify the expression.
$$
\frac{(x+2)(2^2)(x+3)(x-1) + (x+1)(2^3 \cdot 3 \cdot x^3) - (x+3)(3x^3)(x+3)}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}
$$
Now distribute and combine like terms:
$$
\frac{4(x^2+3x-2) + 24x^3(x+1) - 3x^3(x+3)^2}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}
$$
After expanding and simplifying:
$$
\frac{4x^2 + 12x - 8 + 24x^4 + 24x^3 - 3x^3(x^2+6x+9)}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}
$$
$$
\frac{4x^2 + 12x - 8 + 24x^4 + 24x^3 - 3x^3x^2 - 18x^4 - 27x^3}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}
$$
Combine like terms in the numerator:
$$
\frac{24x^4 - 18x^4 + 4x^2 - 3x^3x^2 - 24x^3 + 27x^3 + 12x - 8}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}
$$
$$
\frac{6x^4 - 3x^3x^2 + 3x^3 + 4x^2 + 12x - 8}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}
$$
The final simplified expression is:
$$
\frac{6x^4 - 3x^3x^2 + 3x^3 + 4x^2 + 12x - 8}{2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)}
$$
Key Concepts
Factoring PolynomialsLeast Common DenominatorSimplifying Expressions
Factoring Polynomials
Factoring polynomials is a key mathematical technique used to simplify complex expressions. In many cases, this process involves finding the simplest set of expressions that, when multiplied together, equal the original polynomial. This is vital in operations involving rational expressions which often necessitate simplification or finding a common denominator.
For example, consider the polynomial:
For example, consider the polynomial:
- \(16x^2 - 32x + 16\)
- The first step is to factor a common factor. Here, you can factor out 16, resulting in \(16(x^2 - 2x + 1)\).
- This expression is a perfect square trinomial and can be further factored to \(16(x-1)^2\).
Least Common Denominator
Finding the Least Common Denominator (LCD) is crucial when working with rational expressions that need to be added or subtracted. The LCD is the smallest expression or product that all denominators can divide into evenly. This process often involves:
To calculate the LCD:
- Identifying unique factors from each denominator, ensuring that each is represented at its highest power.
- Combining these factors to form a single denominator expression.
To calculate the LCD:
- Consider each factor's highest powers. You have \(2^4\), \(3\), \(x^3\), \((x+3)\), and \((x-1)^2\).
- Multiplying these together gives you: \(\text{LCD} = 2^4 \cdot 3 \cdot x^3 \cdot (x+3)(x-1)\).
Simplifying Expressions
Simplifying expressions ensures that they are in their most reduced form, which makes further mathematical operations more manageable. This includes rewriting expressions with common denominators and combining terms to reduce complexity.
In the example, after rewriting each rational expression with the LCD, you can merge numerators. This involves distributing any multipliers and combining like terms to minimize the expression.
For the numerators in:
You'll distribute and combine terms like \(x^4, x^3, x^2\), etc., into a single rational expression. Ultimately, this process yields a simplified fraction that represents the same value as the original complex expression.
This strategy not only resolves the exercise but is applicable widely in algebra, making seemingly arduous expressions manageable and concise.
In the example, after rewriting each rational expression with the LCD, you can merge numerators. This involves distributing any multipliers and combining like terms to minimize the expression.
For the numerators in:
- \(4(x^2+3x-2)\)
- \(24x^3(x+1)\)
- \(- 3x^3(x+3)^2\)
You'll distribute and combine terms like \(x^4, x^3, x^2\), etc., into a single rational expression. Ultimately, this process yields a simplified fraction that represents the same value as the original complex expression.
This strategy not only resolves the exercise but is applicable widely in algebra, making seemingly arduous expressions manageable and concise.
Other exercises in this chapter
Problem 76
For the following problems, convert the given rational expressions to rational expressions having the same denominators. $$ \frac{2}{x+5}, \frac{4}{x-5} $$
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For the following problems, perform the multiplications and divisions. $$ \frac{-a^{2}-2 a+15}{-6 a-12} \div \frac{a^{2}-2 a-8}{-2 a-10} $$
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For the following problems, solve the rational equations. $$ \frac{6 a}{7}+\frac{2 a-3}{21}=\frac{77}{21} $$
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When the same number is subtracted from both the numerator and denominator of \(\frac{3}{10},\) the result is \(\frac{1}{8}\). What is the number that is subtra
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