Problem 76
Question
Find the area of each triangle. \(a=154\) centimeters, \(b=179\) centimeters. \(c=183\) centimeters
Step-by-Step Solution
Verified Answer
The area of the triangle is approximately 12,637.5 cm².
1Step 1: Calculate the Semiperimeter
To use Heron's formula to find the area of the triangle, first calculate the semiperimeter \( s \) of the triangle using the formula: \( s = \frac{a + b + c}{2} \). Here, \( a = 154 \), \( b = 179 \), and \( c = 183 \). So, \[ s = \frac{154 + 179 + 183}{2} = \frac{516}{2} = 258 \text{ cm} \].
2Step 2: Use Heron's Formula for Area
Heron's formula for the area \( A \) of a triangle is \( A = \sqrt{s(s-a)(s-b)(s-c)} \). Substitute the values of \( s \), \( a \), \( b \), and \( c \) into the formula: \( A = \sqrt{258(258-154)(258-179)(258-183)} \).
3Step 3: Calculate the Individual Terms
Calculate the terms inside the square root separately: \( s-a = 258 - 154 = 104 \), \( s-b = 258 - 179 = 79 \), and \( s-c = 258 - 183 = 75 \).
4Step 4: Compute the Product Under the Square Root
Now compute the product: \[ 258 \times 104 \times 79 \times 75 = 159785400 \].
5Step 5: Calculate the Square Root
Finally, take the square root of the product: \[ A = \sqrt{159785400} \approx 12637.5 \text{ cm}^2 \].
6Step 6: Verify the Units
Make sure the units for area are correct. Since the side lengths are in centimeters, the area should be in square centimeters.
Key Concepts
SemiperimeterTriangle Area CalculationSquare Root Calculation
Semiperimeter
Before calculating the area of a triangle using Heron's formula, you must find the semiperimeter. This is a crucial step that determines the starting point for further calculations. The semiperimeter, denoted as \( s \), of a triangle is essentially half of its perimeter. If you think about the perimeter as the total distance around the triangle, finding half of that gives you the semiperimeter.
To calculate it, you use the formula:
In our example, these side lengths are \( a = 154 \) cm, \( b = 179 \) cm, and \( c = 183 \) cm.
Plug them into the formula:
To calculate it, you use the formula:
- \( s = \frac{a+b+c}{2} \)
In our example, these side lengths are \( a = 154 \) cm, \( b = 179 \) cm, and \( c = 183 \) cm.
Plug them into the formula:
- \( s = \frac{154+179+183}{2} \)
- \( s = \frac{516}{2} \)
- \( s = 258 \) cm
Triangle Area Calculation
Calculating the area of a triangle becomes straightforward once you know the semiperimeter. Heron's formula is a powerful tool for this purpose. It provides a way to calculate the area when you have the lengths of all three sides. The formula is:
With the semiperimeter \( s = 258 \) cm already calculated, and sides \( a = 154 \) cm, \( b = 179 \) cm, and \( c = 183 \) cm, substitute these values into the formula:
- \( A = \sqrt{s(s-a)(s-b)(s-c)} \)
With the semiperimeter \( s = 258 \) cm already calculated, and sides \( a = 154 \) cm, \( b = 179 \) cm, and \( c = 183 \) cm, substitute these values into the formula:
- \( A = \sqrt{258(258-154)(258-179)(258-183)} \)
- \( 258-154 = 104 \)
- \( 258-179 = 79 \)
- \( 258-183 = 75 \)
- \( A = \sqrt{258 \times 104 \times 79 \times 75} \)
Square Root Calculation
After setting up Heron's formula for the area, the final challenge lies in executing the square root calculation. This involves calculating the product inside the square root, followed by finding the square root itself.
Let's start by computing the product of the terms previously found:
Remember, when dealing with units, if the side lengths are in centimeters, as in this problem, the area will naturally be in square centimeters.
This step completes the application of Heron's formula, giving you the triangle's area in squared units.
Let's start by computing the product of the terms previously found:
- \( 258 \times 104 \times 79 \times 75 = 159785400 \)
- \( A = \sqrt{159785400} \approx 12637.5 \text{ cm}^2 \)
Remember, when dealing with units, if the side lengths are in centimeters, as in this problem, the area will naturally be in square centimeters.
This step completes the application of Heron's formula, giving you the triangle's area in squared units.
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