Problem 76
Question
Factor completely by first taking out a negative common factor. $$-r^{2}+11 r-28$$
Step-by-Step Solution
Verified Answer
The short answer to factoring the expression completely by first taking out a negative common factor is: \(-1(r - 4)(r - 7)\).
1Step 1: Identify negative common factors
In the given expression \(-r^2 + 11r - 28\), the negative common factor is -1. So, we first need to multiply the entire expression by -1.
2Step 2: Multiply the expression by -1
Multiplying the expression by -1, we get:
\((-1) * (-r^2 + 11r - 28)\)
\(r^2 - 11r + 28\)
3Step 3: Factor the quadratic expression
Now, we need to factor the quadratic expression \(r^2 - 11r + 28\).
We are looking for two numbers that multiply to 28 and, when added, give us -11. These numbers are -4 and -7. So, we can rewrite the expression as:
\((r - 4)(r - 7)\)
4Step 4: Write down the final factored expression
The original expression, \(-r^2 + 11r - 28\), can now be written in factored form as:
\(-1(r - 4)(r - 7)\)
The final factored expression is \(-1(r - 4)(r - 7)\).
Key Concepts
Negative Common FactorQuadratic ExpressionPolynomial Factoring
Negative Common Factor
Finding a negative common factor is often the first step in factoring certain polynomial expressions, especially when you start with a negative leading term. The negative leading term can make factoring more complex, so isolating that negative can simplify the process. In our example, we looked at the expression
- -r² + 11r - 28
- -1(r² - 11r + 28)
Quadratic Expression
Quadratic expressions are polynomials of the form \(ax^2 + bx + c\). These are equations where the highest degree of the variable is 2. They have significant meaning in algebra because they represent parabolas when plotted on a graph. In our exercise, we're dealing with
The primary goal is to break down this quadratic expression into products of simpler binomials. This means we're looking for two binomials that multiply to form the original quadratic.
Identifying the right pair of numbers involves checking factors of the constant term (28, in this case) that also add up to the linear coefficient (-11). The solution was determined as (-4 and -7), and this gave:
- r² - 11r + 28
The primary goal is to break down this quadratic expression into products of simpler binomials. This means we're looking for two binomials that multiply to form the original quadratic.
Identifying the right pair of numbers involves checking factors of the constant term (28, in this case) that also add up to the linear coefficient (-11). The solution was determined as (-4 and -7), and this gave:
- (r - 4)(r - 7)
Polynomial Factoring
Factoring polynomials involves finding simpler expressions that multiply together to recreate the original polynomial. This process is crucial in solving polynomial equations, simplifying expressions, and performing algebraic operations. The expression
- -r² + 11r - 28
- First, extracting the negative common factor resulted in: -1 (r² - 11r + 28).
- Second, factoring the quadratic \(r² - 11r + 28\) into: (r - 4)(r - 7).
- -1(r - 4)(r - 7)
Other exercises in this chapter
Problem 76
If \(x^{n}\) is a perfect square and a perfect cube, then \(n\) is divisible by what number?
View solution Problem 76
Factor by grouping. What should be the first step in factoring \(3 x y+6 x+15 y+30 ?\)
View solution Problem 76
Factor completely, if possible. Begin by asking yourself, "Can I factor out a GCF?" $$(p-q) z^{2}-21(p-q) z+110(p-q)$$
View solution Problem 77
Factor completely. $$d^{3}+1$$
View solution