Problem 76
Question
Evaluate each expression. \(_{7} \mathrm{P}_{3}\)
Step-by-Step Solution
Verified Answer
The number of permutations is 210
1Step 1: Identify the values of n and r
In \(_{7}P_{3}\), 7 is the total number of items (n) and 3 is the number of items to choose (r). So, n = 7 and r = 3.
2Step 2: Compute the factorials
Now, we will calculate factorials for both n and (n-r). In other words, we need to find the values of 7! and (7-3)!. \n 7! = 7*6*5*4*3*2*1 = 5040\n (7-3)! = 4! = 4*3*2*1 = 24
3Step 3: Substitute the values into the permutation formula
We substitute the values of n! and (n-r)! into the permutation formula \( P(n,r) = \frac{n!}{(n-r)!} \). Plugging in the values we get: \( P(7,3) = \frac{5040}{24}\)
4Step 4: Simplify the equation
Finally, simplify the fraction to find the total number of permutations. \( P(7,3) = \frac{5040}{24}\) = 210
Key Concepts
FactorialPermutation formulaAlgebra 2
Factorial
When exploring permutations, a core concept utilized is the factorial, typically represented by the symbol '!'. The factorial of a number is the product of all positive integers up to that number. For instance, for the number 7, the factorial (written as 7!) is calculated as follows:
- Begin with the number 7.
- Multiply 7 by 6, then continue multiplying sequentially by every integer below it: 5, 4, 3, 2, and 1.
- The result is 7! = 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040.
Permutation formula
The permutation formula is a standard tool in combinatorics used to find the number of possible arrangements of a subset of items from a larger set. It's written as \( P(n, r) = \frac{n!}{(n-r)!} \). Here:
- \(n\) is the total number of items.
- \(r\) is the number of items to arrange.
- \(n!\) refers to the factorial of \(n\).
- \((n-r)!\) represents the factorial of the difference between the total number of items and the number selected.
Algebra 2
In Algebra 2, the concept of permutations is further explored and applied to solve complex problems involving the arrangement of items. This subject often combines various mathematical concepts, such as factorials and permutation formulas, within larger algebraic systems.
Students might encounter permutation problems in topics like:
Students might encounter permutation problems in topics like:
- Combinatorics, where choosing order of items matters.
- Probability, determining likelihood of specific arrangements.
- Statistics, analyzing data permutations and their effects on results.
Other exercises in this chapter
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