Problem 76
Question
ENERGY A circular cell must deliver 18 watts of energy. If each square centimeter of the cell that is in sunlight produces 0.01 watt of energy, how long must the radius of the cell be?
Step-by-Step Solution
Verified Answer
The radius of the cell must be approximately 23.93 cm.
1Step 1: Understanding the Problem
We are given that a circular solar cell needs to deliver 18 watts of energy. Each square centimeter of the cell in sunlight generates 0.01 watt. We need to find out the radius that will achieve this output.
2Step 2: Calculate Required Area
Since each square centimeter produces 0.01 watt and we need 18 watts, we calculate the total area required by dividing the total energy needed by the energy produced per square centimeter: \[ \text{Required Area} = \frac{18 \text{ watts}}{0.01 \text{ watts/cm}^2} = 1800 \text{ cm}^2. \]
3Step 3: Area Formula for Circle
The area of a circle is given by the formula: \[ A = \pi r^2. \] Here, we have the area as 1800 cm², and need to find the radius \( r \).
4Step 4: Solve for Radius
Set the area formula equal to the required area and solve for \( r \): \[ \pi r^2 = 1800. \] Divide both sides by \( \pi \): \[ r^2 = \frac{1800}{\pi}. \] Then, take the square root of both sides to find \( r \): \[ r = \sqrt{\frac{1800}{\pi}}. \]
5Step 5: Numerical Calculation
Calculate the numerical value: \[ r = \sqrt{\frac{1800}{3.14159}} \approx \sqrt{573.026} \approx 23.93 \text{ cm}. \]
Key Concepts
Energy calculationCircle area formulaRadius determination
Energy calculation
In the world of solar cells, energy calculation plays a crucial role in determining the performance and requirements of the cells. Solar cells convert sunlight into electricity, measured in watts. But how exactly do you calculate the energy required for a solar cell to function efficiently? Let's break it down.
In this problem, we have a circular solar cell that must produce 18 watts. Each part of the solar cell, specifically each square centimeter, generates only 0.01 watt when exposed to sunlight. To find how many square centimeters are necessary to reach the 18 watts target, you simply divide the total desired energy by the energy production per unit area.
This results in the formula:
In this problem, we have a circular solar cell that must produce 18 watts. Each part of the solar cell, specifically each square centimeter, generates only 0.01 watt when exposed to sunlight. To find how many square centimeters are necessary to reach the 18 watts target, you simply divide the total desired energy by the energy production per unit area.
This results in the formula:
- \[ \text{Required Area} = \frac{\text{Total Energy Required}}{\text{Energy Produced per Unit Area}} \]
- \[ \text{Required Area} = \frac{18\, \text{watts}}{0.01\, \text{watts/cm}^2} = 1800\, \text{cm}^2 \]
Circle area formula
Once you know the required area of a solar cell, it's essential to relate this area to the shape of the cell. In our exercise, we are dealing with a circular solar cell. Thus, understanding the circle area formula is key.
The formula for the area of a circle is denoted as:
The next step is to use this formula to determine the radius, which leads us to the following calculation:
The formula for the area of a circle is denoted as:
- \[ A = \pi r^2 \]
- \( A \) is the area
- \( r \) is the radius
- \( \pi \) is a constant approximately equal to 3.14159
The next step is to use this formula to determine the radius, which leads us to the following calculation:
- \[ \pi r^2 = 1800 \]
Radius determination
Finding the radius of the solar cell involves solving the circle's area formula for \( r \). When you rearrange the equation \( \pi r^2 = 1800 \), you first need to isolate \( r^2 \):
- \[ r^2 = \frac{1800}{\pi} \]
- \[ r = \sqrt{\frac{1800}{\pi}} \]
- \[ r = \sqrt{\frac{1800}{3.14159}} \approx \sqrt{573.026} \approx 23.93 \text{ cm} \]
Other exercises in this chapter
Problem 76
Solve each equation. Round to the nearest hundredth. \(2^{x}=10\)
View solution Problem 76
What is the solution to the equation \(3^{x}=11 ?\) F. \(x=2\) G. \(x=\log _{10} 2\) H. \(x=\log _{10} 11+\log _{10} 3\) J. \(x=\frac{\log _{10} 11}{\log _{10}
View solution Problem 77
Solve each equation. Round to the nearest hundredth. \(5^{x}=12\)
View solution Problem 77
Simplify each expression. \(x^{\sqrt{6}} \cdot x^{\sqrt{6}}\)
View solution