Problem 76
Question
Do you expect cesium, a group 1 element used in infrared lamps, or bromine, a halogen used in firefighting compounds to have the greatest electronegativity? Why?
Step-by-Step Solution
Verified Answer
Bromine has the greater electronegativity compared to cesium, as it is further to the right and higher up within the periodic table. Electronegativity increases across a period (left to right) and decreases down a group (top to bottom). Bromine's position, being closer to the top-right corner of the table, indicates higher electronegativity.
1Step 1: Define electronegativity
Electronegativity is the ability of an atom in a molecule to attract electrons towards itself. It depends on factors like atomic number and atomic radius. In general, electronegativity increases across a period from left to right and decreases down a group in the periodic table.
2Step 2: Locate cesium and bromine on the periodic table
Cesium belongs to group 1 (alkali metals) and is in the 6th period, while bromine belongs to group 17 (halogens) and is in the 4th period.
3Step 3: Compare electronegativities based on their positions
Since electronegativity increases across a period (left to right) and decreases down a group (top to bottom), we can make the following comparisons:
- Cesium is further to the left than bromine, so bromine is expected to have a higher electronegativity.
- Cesium is further down than bromine, so cesium is expected to have a lower electronegativity.
4Step 4: Determine the element with the greatest electronegativity
Based on the comparisons made in Step 3, we can conclude that bromine has a greater electronegativity when compared to cesium. This greater electronegativity is due to bromine's position in the periodic table, being closer to the top-right corner where elements generally have higher electronegativities.
Key Concepts
Periodic TableGroup 1 ElementsHalogensAtomic Radius
Periodic Table
The Periodic Table is a tabular arrangement of all known chemical elements organized based on their atomic number, electron configuration, and recurring chemical properties. Elements are ordered from left to right and top to bottom by increasing atomic number. This design helps predict the properties of elements, including electronegativity. As you move across a period from left to right, electronegativity tends to increase. This means elements on the right side of the table are generally more electronegative. Conversely, moving down a group (from top to bottom), electronegativity decreases as atoms gain more electron shells, which reduces their ability to attract additional electrons due to the increased distance from the nucleus.
Group 1 Elements
Group 1 elements, also known as alkali metals, include lithium, sodium, potassium, rubidium, cesium, and francium. These elements are located in the far-left column of the periodic table. They are characterized by having one electron in their outermost shell, making them highly reactive, especially with water.
- Alkali metals have low electronegativities because they tend to lose their single valence electron easily to form positive ions.
- Their reactivity increases as you move down the group due to the increasing atomic radius and decreasing ionization energy.
Halogens
Halogens are the elements in Group 17 of the periodic table, which include fluorine, chlorine, bromine, iodine, and astatine. These elements are highly electronegative and tend to gain electrons during chemical reactions.
- They have high electronegativities because of their smaller atomic radii and greater nuclear charge, allowing them to attract electrons strongly.
- Electronegativity decreases as you move down this group from fluorine to astatine because the atomic radius increases, reducing the attractive force exerted by the nucleus on the valence electrons.
Atomic Radius
Atomic radius is the distance from the nucleus of an atom to the outermost electron shell. It plays a significant role in determining the chemical properties and reactivity of an element. Generally, the atomic radius:
- Increases as you move down a group due to the addition of extra electron shells.
- Decreases as you move across a period from left to right because additional protons pull the electron cloud closer.
Other exercises in this chapter
Problem 74
Explain why the radius of an atom cannot be measured directly.
View solution Problem 75
What is the metalloid in period 2 of the periodic table that is part of compounds used as water softeners?
View solution Problem 78
Which element in each pair is more electronegative? a. \(K,\) As \(\quad\) b. N, Sb \(\quad\) c. Sr, Be
View solution Problem 79
Explain why the s-block of the periodic table is two-groups wide, the p-block is six-groups wide, and the d-block is ten-groups wide.
View solution