Problem 76
Question
$$ \begin{array}{|l|c|c|c|c|} \hline \text { Monomials } & \text { Add } & \text { Subtract } & \text { Multiply } & \text { Divide } \\ \hline 6 x, 3 x & 6 x+3 x=9 x & 6 x-3 x=3 x & 6 x \cdot 3 x=18 x^{2} & \frac{6 x}{3 x}=2 \\ \hline-12 x^{2}, 2 x & -12 x^{2}+2 x ; \text { can't be simplified } & -12 x^{2}-2 x ; \text { can't be simplified } & -12 x^{2} \cdot 2 x=-24 x^{3} & \frac{-12 x^{2}}{2 x}=-6 x \\ \hline 4 y^{3}, 4 y^{7} & & & \\ \hline \end{array} $$
Step-by-Step Solution
Verified Answer
The results are: addition - no simplification, subtraction - no simplification, multiplication - \(16y^{10}\), division - \(\frac{1}{y^4}\).
1Step 1: Addition of Monomials
The monomials given are \(4y^3\) and \(4y^7\), which do not have like terms (since their exponents differ). Thus, they cannot be added to result in a simplified expression. The expression remains \(4y^3 + 4y^7\).
2Step 2: Subtraction of Monomials
Subtracting the monomials \(4y^3\) and \(4y^7\) again involves unlike terms because their exponents are different. Hence, the expression is not simplified further and remains \(4y^3 - 4y^7\).
3Step 3: Multiplication of Monomials
To multiply the monomials \(4y^3\) and \(4y^7\), multiply the coefficients and add the exponents. This gives: \[4y^3 \cdot 4y^7 = (4 \cdot 4)y^{3+7} = 16y^{10}.\]
4Step 4: Division of Monomials
To divide the monomials \(4y^3\) and \(4y^7\), divide the coefficients and subtract the exponents: \[\frac{4y^3}{4y^7} = \frac{4}{4}y^{3-7} = y^{-4}.\] Write this as \(\frac{1}{y^4}\) for standard form.
Key Concepts
Addition of MonomialsSubtraction of MonomialsMultiplication of MonomialsDivision of Monomials
Addition of Monomials
When it comes to adding monomials, the key is to focus on like terms. Like terms in algebra are those terms that have identical variable parts, meaning both the variable and its exponent must match. This is crucial for addition because only like terms can be combined to form a single monomial.
For instance, if you have monomials like \(6x\) and \(3x\), the variable part \(x\) is the same, allowing us to add their coefficients: \(6x + 3x = 9x\).
However, if the terms are not like, such as \(4y^3\) and \(4y^7\), addition is not possible without simplifying, as their exponents differ. Thus, their sum is simply expressed as \(4y^3 + 4y^7\).
Here's a quick checklist for adding monomials:
For instance, if you have monomials like \(6x\) and \(3x\), the variable part \(x\) is the same, allowing us to add their coefficients: \(6x + 3x = 9x\).
However, if the terms are not like, such as \(4y^3\) and \(4y^7\), addition is not possible without simplifying, as their exponents differ. Thus, their sum is simply expressed as \(4y^3 + 4y^7\).
Here's a quick checklist for adding monomials:
- Check if the terms are like (same variable and exponent).
- If they are like terms, add the coefficients.
- If not, rewrite the expression without combining them.
Subtraction of Monomials
Subtraction of monomials follows the same concept as addition; identifying like terms is essential. You must ensure that both the variable and its exponent are identical in the monomials being subtracted.
For example, with \(6x\) and \(3x\), subtract the coefficients: \(6x - 3x = 3x\).
On the other hand, attempting to subtract unlike terms such as \(4y^3 - 4y^7\) results in no simplification. The expression remains as \(4y^3 - 4y^7\) because the exponents of \(y\) are different.
Here's a simple process for subtracting monomials:
For example, with \(6x\) and \(3x\), subtract the coefficients: \(6x - 3x = 3x\).
On the other hand, attempting to subtract unlike terms such as \(4y^3 - 4y^7\) results in no simplification. The expression remains as \(4y^3 - 4y^7\) because the exponents of \(y\) are different.
Here's a simple process for subtracting monomials:
- Check for like terms (same variable and same exponent).
- Subtract their coefficients if they are like terms.
- If not, keep the expression as is without any subtraction.
Multiplication of Monomials
Unlike addition and subtraction, when multiplying monomials, you multiply both the coefficients and the variables, while adding the exponents of the variables.
For example, multiplying \(4y^3\) and \(4y^7\) involves:
The steps are straightforward:
For example, multiplying \(4y^3\) and \(4y^7\) involves:
- Multiplying the coefficients: \(4 \times 4 = 16\).
- Adding the exponents of \(y\): \(3 + 7 = 10\); hence, the result is \(16y^{10}\).
The steps are straightforward:
- Multiply the coefficients.
- Add the exponents of the like bases.
- Simplify the resulting monomial fully.
Division of Monomials
Dividing monomials involves dividing their coefficients and subtracting the exponents of the common variable. It's important to understand the application of the law of exponents which states subtract the exponents of like bases during division.
For instance, to divide \(4y^3\) by \(4y^7\):
To divide monomials effectively:
For instance, to divide \(4y^3\) by \(4y^7\):
- First, divide the coefficients: \(\frac{4}{4} = 1\).
- Then, subtract the exponents of \(y\): \(3 - 7 = -4\).
To divide monomials effectively:
- Divide their coefficients.
- Subtract the exponents of like terms.
- Simplify and, if needed, express using positive exponents by flipping the base.
Other exercises in this chapter
Problem 76
Explain why the degree of the term \(5 y^{3}\) is 3 and the degree of the polynomial \(2 y+y+2 y\) is 1 .
View solution Problem 76
Write each number in scientific notation. $$ 0.00000017 $$
View solution Problem 76
Simplify each expression. $$ y^{4} y $$
View solution Problem 76
Mixed Practice Multiply. $$ (3 x+5)(3 x-5) $$
View solution