Problem 76
Question
A new car worth 24,000 dollars is depreciating in value by 3000 dollars per year. The mathematical model $$y=-3000 x+24,000$$ describes the car's value, \(y,\) in dollars, after \(x\) years. a. Find the \(x\) -intercept. Describe what this means in terms of the car's value. b. Find the \(y\) -intercept. Describe what this means in terms of the car's value. c. Use the intercepts to graph the linear equation. Because \(x\) and \(y\) must be nonnegative (why?), limit your graph to quadrant I and its boundaries. d. Use your graph to estimate the car's value after five years.
Step-by-Step Solution
Verified Answer
From the equation, the x-intercept is 8 years, meaning the car will have no value after 8 years. The y-intercept is $24,000, showing the initial price of the car. Plotting these in a graph, it shows the depreciation of the car's value over time, from which it is estimated the car's value will be $9000 after five years.
1Step 1: Find x-intercept
To find the x-intercept, set \(y=0\) in the equation and solve for \(x\). The x-intercept represents the time in years when the car will not have any monetary value.
2Step 2: Find y-intercept
To find the y-intercept, set \(x=0\) in the equation and solve for \(y\). The y-intercept represents the initial value of the car before any depreciation, which in this case is when \(x=0\), i.e., in the beginning.
3Step 3: Plot Linear Equation
Plot the equation, representing time(in years) on the x-axis and car's value (in dollars) on the y-axis. Assume positive values for both x and y, because they represent time and money respectively, which cannot be negative.
4Step 4: Estimate Car's Value After Five Years
With the car's depreciation modeled in the graph, find the point on the graph that corresponds to \(x=5\) (five years from now). This value will be the car's estimate value after five years.
5Step 5: Interpret the intercepts
Interpret the x and y intercepts in terms of the car's value which will help in understanding the depreciation of the car over the years
Key Concepts
DepreciationX-InterceptY-InterceptGraphing Linear Equations
Depreciation
Depreciation is the gradual decrease in the value of an asset, like a car, over time. This decline in value occurs due to factors such as wear and tear, or obsolescence. In the context of our exercise, depreciation is modeled using the linear equation \( y = -3000x + 24000 \).
In our case, the car will eventually be worthless as its depreciated value reaches zero. This situation is calculated at the x-intercept, which occurs when the entire initial value is lost over the years.
- The negative sign in front of 3000 indicates that the value of the car decreases by 3000 dollars each year.
- The initial price of the car is 24,000 dollars, representing its value when purchased new.
In our case, the car will eventually be worthless as its depreciated value reaches zero. This situation is calculated at the x-intercept, which occurs when the entire initial value is lost over the years.
X-Intercept
The x-intercept is where the graph of an equation crosses the x-axis. In our depreciation problem, this value tells us when the car's worth will completely depreciate to zero. To find the x-intercept:
- Set \( y = 0 \) in the equation \( y = -3000x + 24000 \).
- Solve for \( x \) to get \( x = \frac{24000}{3000} = 8 \).
Y-Intercept
The y-intercept is where the line crosses the y-axis. It represents the starting value when the time is zero. In our scenario, the y-intercept is found by setting \( x = 0 \) in the equation \( y = -3000x + 24000 \):
- This simplifies to \( y = 24000 \).
Graphing Linear Equations
Graphing the linear equation is a visual way to understand how depreciation affects car value over time. Use a graph with:
- The x-axis representing time in years.
- The y-axis showing the car's value in dollars.
Other exercises in this chapter
Problem 75
Graph each linear equation in two variables. Find at least five solutions in your table of values for each equation. $$y=-\frac{5}{2} x-1$$
View solution Problem 76
Will help you prepare for the material covered in the next section. From \((0,1),\) move 2 units down and 3 units to the right. What point do you obtain?
View solution Problem 76
Graph each linear equation in two variables. Find at least five solutions in your table of values for each equation. $$y=-\frac{5}{2} x+1$$
View solution Problem 77
A new car worth 45,000 dollars is depreciating in value by 5000 dollars per year. The mathematical model $$y=-5000 x+45,000$$ describes the car's value, \(y,\)
View solution