Problem 75
Question
Use the \(a c\) method to factor \(x^{2}+0 x-36\).
Step-by-Step Solution
Verified Answer
The factored form is \((x + 6)(x - 6)\).
1Step 1 - Identify coefficients
Identify the coefficients of the quadratic equation in standard form. For the equation \(x^{2} + 0x - 36\), the coefficients are: \(a = 1\), \(b = 0\), and \(c = -36\).
2Step 2 - Find the product of \(a\) and \(c\)
Multiply the coefficients \(a\) and \(c\) to find their product. In this case: \(a \cdot c = 1 \cdot (-36) = -36\).
3Step 3 - Find factors of the product
Find two numbers that multiply to \(-36\) and add to \(0\) (the coefficient of \(x\)). These numbers are \(-6\) and \(6\) as \((-6) \cdot 6 = -36\) and \((-6) + 6 = 0\).
4Step 4 - Rewrite the middle term
Rewrite the middle term using the factors found in Step 3. So, \(x^{2} + 0x - 36\) becomes \(x^{2} - 6x + 6x - 36\).
5Step 5 - Group and factor
Group the terms in pairs and factor out the common factors. For \(x^2 - 6x + 6x - 36\): \(x(x - 6) + 6(x - 6)\).
6Step 6 - Factor by grouping
Notice that \(x - 6\) is a common factor. Factor it out: \((x + 6)(x - 6)\).
Key Concepts
ac methodquadratic equation coefficientsfactor by groupingrewriting middle term
ac method
The 'ac method' is a technique used for factoring quadratic equations. It is especially helpful when the quadratic trinomial cannot be factored easily by inspection. The method involves four primary steps: multiplying the coefficients of the first and last terms (in the form of ax^2 + bx + c), finding two numbers that multiply to this product and add to the middle coefficient, rewriting the middle term using these numbers, and finally grouping and factoring the rewritten equation. This method simplifies solving otherwise tricky quadratic equations.
quadratic equation coefficients
Quadratic equations can typically be written in the standard form: ax^2 + bx + c. The coefficients 'a', 'b', and 'c' are the numerical factors that multiply with the variable terms. Identifying these coefficients correctly is crucial in methods like the 'ac method'.
- In the quadratic equation x^2 + 0x - 36:
- a = 1 (the coefficient of x^2)
- b = 0 (the coefficient of x)
- c = -36 (the constant term)
factor by grouping
Factoring by grouping is a valuable skill in algebra. After rewriting the middle term using the two numbers from the 'ac method', the quadratic equation can be expressed in four terms. These terms can be grouped in pairs and factored separately. For instance:
For x^2 - 6x + 6x - 36:
For x^2 - 6x + 6x - 36:
- Group terms into pairs: (x^2 - 6x) and (6x - 36)
- Factor out the greatest common factor in each pair: x(x - 6) + 6(x - 6)
- Observe the common binomial factor: (x - 6)
- Factor out the common binomial to get the fully factored form: (x + 6)(x - 6)
rewriting middle term
One critical step in the 'ac method' is rewriting the middle term. This is necessary to simplify the quadratic expression into a form that can be factored by grouping. For x^2 + 0x - 36, we find two numbers that multiply to 'ac' (= -36) and add to 'b' (= 0), which are -6 and 6.
- Replace the middle term with two terms using these factors: x^2 - 6x + 6x - 36
- This step transforms the equation, making it possible to factor by grouping
Other exercises in this chapter
Problem 75
Factor completely. Identify any prime polynomials. $$ 6 a^{2} c+3 a^{2}-2 a b c-a b $$
View solution Problem 75
Use any of the factoring methods to factor. Identify any prime polynomials. $$ 9 w^{2}-18 w+5 $$
View solution Problem 75
Factor by grouping. Do not combine like terms before factoring. $$ 36 x^{2}-9 x-20 x+5 $$
View solution Problem 76
Factor completely. Identify any prime polynomials. $$ 12 x^{2} z+4 x^{2}-3 x y z-x y $$
View solution