Problem 75
Question
Simplify each expression by performing the indicated operation. $$ \frac{2}{3-\sqrt{7}} $$
Step-by-Step Solution
Verified Answer
Answer: The simplified form of the expression $$\frac{2}{3-\sqrt{7}}$$ is $$3+\sqrt{7}$$.
1Step 1: Identify the conjugate
First, we will identify the conjugate of the given binomial expression. The conjugate of $$3-\sqrt{7}$$ is $$3+\sqrt{7}$$.
2Step 2: Multiply by conjugate
Next, we will multiply both the numerator and denominator of the given fraction by the conjugate we found in the previous step.
$$
\frac{2}{3-\sqrt{7}} \cdot \frac{3+\sqrt{7}}{3+\sqrt{7}}
$$
3Step 3: Apply FOIL method
Now, we will use the FOIL (First, Outer, Inner, Last) method to multiply the terms in the numerator and denominator of the resulting fraction.
$$
\frac{2(3+\sqrt{7})}{(3-\sqrt{7})(3+\sqrt{7})}
$$
4Step 4: Simplify numerator and denominator
Next, we will simplify the numerator and denominator of the resulting fraction as follows:
Numerator:
$$
2(3+\sqrt{7}) = 6+2\sqrt{7}
$$
Denominator:
$$
(3-\sqrt{7})(3+\sqrt{7}) = 3^2 - (\sqrt{7})^2 = 9-7
$$
5Step 5: Write final simplified expression
Finally, we substitute the simplified numerator and denominator, and simplify the resulting fraction:
$$
\frac{6+2\sqrt{7}}{9-7} = \frac{6+2\sqrt{7}}{2}
$$
Since the numerator and denominator have a common factor of 2, we can simplify further:
$$
\frac{6+2\sqrt{7}}{2}=\frac{2(3+\sqrt{7})}{2} = 3+\sqrt{7}
$$
The final simplified expression is $$3+\sqrt{7}$$.
Key Concepts
ConjugatesFOIL MethodSimplifying ExpressionsBinomials
Conjugates
In mathematics, the conjugate of a binomial expression is a specific way to manipulate radicals that appear in fractions. A conjugate involves changing the sign between two terms. For instance, if you have a binomial expression like \( a - b \), its conjugate would be \( a + b \). The special property of conjugates is that when multiplied by each other, the middle term cancels out due to differences of squares. This technique is crucial in rationalizing denominators when you want to eliminate radicals, making expressions simpler to work with.
- The given binomial: \( 3 - \sqrt{7} \)
- Its conjugate: \( 3 + \sqrt{7} \)
FOIL Method
The FOIL Method, which stands for First, Outer, Inner, Last, is a popular technique for multiplying two binomials. It's a systematic approach that ensures all components are correctly accounted for during multiplication, which can be especially helpful for students to visualize all parts of the expression.
- First: Multiply the first terms of each binomial.
- Outer: Multiply the outer terms of the binomials.
- Inner: Multiply the inner terms.
- Last: Multiply the last terms of each binomial.
Simplifying Expressions
Simplifying an expression means reducing it to its simplest form where all possible arithmetic operations have been performed. This process often involves combining like terms, factoring, or employing techniques like rationalizing.
- After multiplying by the conjugate, we simplify the numerator to \(6 + 2\sqrt{7}\).
- The denominator is simplified using differences of squares, becoming \(2\).
Binomials
Binomials are simple mathematical expressions with two terms, usually joined by a plus or a minus sign. Understanding the structure of binomials is crucial for operations like multiplication or finding conjugates.
- Consider the binomial: \(3 - \sqrt{7}\)
- Its conjugate: \(3 + \sqrt{7}\)
Other exercises in this chapter
Problem 74
Find each of the following products. $$ \sqrt{x}\left(\sqrt{x^{3}}-\sqrt{2 x^{4}}\right) $$
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For the following problems, solve the equations. $$ \sqrt{2 x+3}+8=11 $$
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For the following problems, simplify each of the radical expressions. $$ \sqrt{(b+2)^{4}} $$
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Simplify \(x^{8} y^{7}\left(\frac{x^{4} y^{8}}{x^{3} y^{4}}\right)\).
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