Problem 75
Question
Relativity According to the Theory of Relativity, the length \(L\) of an object is a function of its velocity \(v\) with respect to an observer. For an object whose length at rest is \(10 \mathrm{m},\) the function is given by $$L(v)=10 \sqrt{1-\frac{v^{2}}{c^{2}}}$$ $$L(v)=10 \sqrt{1-\frac{v^{2}}{c^{2}}}$$ where \(c\) is the speed of light \((300,000 \mathrm{km} / \mathrm{s}) .\)(b) How does the length of an object change as its velocity increases?
Step-by-Step Solution
Verified Answer
The length of the object contracts as its velocity increases, approaching zero as velocity approaches the speed of light.
1Step 1: Understand the Function
The function given is \( L(v) = 10 \sqrt{1 - \frac{v^2}{c^2}} \), where \( L(v) \) is the length at velocity \( v \) and \( L(0) = 10 \) m when the object is at rest. This represents the relativistic effect of length contraction.
2Step 2: Concept of Length Contraction
According to the theory, the length of an object contracts (appears shorter) when observed at velocities closer to the speed of light \( c \). As \( v \) increases, \( 1 - \frac{v^2}{c^2} \) decreases, resulting in a smaller value under the square root.
3Step 3: Analyze the Denominator
The term \( \frac{v^2}{c^2} \) increases as velocity \( v \) increases, meaning \( \sqrt{1 - \frac{v^2}{c^2}} \) decreases because the fraction becomes larger, thus decreasing \( L(v) \).
4Step 4: Limit Analysis
Consider \( v \) approaching \( c \): \( \frac{v^2}{c^2} \rightarrow 1 \), making \( \sqrt{1 - \frac{v^2}{c^2}} \rightarrow 0 \). Thus, \( L(v) \) approaches 0. When \( v \) is much less than \( c \), \( \frac{v^2}{c^2} \approx 0 \), and \( L(v) \) approximately equals 10 m.
Key Concepts
Length ContractionRelativistic EffectsVelocity and Speed of Light
Length Contraction
One fascinating aspect of Einstein's Theory of Relativity is the concept of length contraction. Imagine observing a spaceship zooming through space at a speed close to the speed of light. To you, as a stationary observer, the spaceship would appear shorter along its direction of motion than it would if it were at rest.
This phenomenon occurs because as the spaceship's velocity \( v \) increases, the factor \( 1 - \frac{v^2}{c^2} \) decreases. Therefore, the length \( L(v) = 10 \sqrt{1 - \frac{v^2}{c^2}} \) becomes smaller.
This phenomenon occurs because as the spaceship's velocity \( v \) increases, the factor \( 1 - \frac{v^2}{c^2} \) decreases. Therefore, the length \( L(v) = 10 \sqrt{1 - \frac{v^2}{c^2}} \) becomes smaller.
- When \( v = 0 \), the spaceship remains its original length of 10 meters.
- As \( v \) increases, the observed length \( L(v) \) shrinks.
- When \( v \) approaches the speed of light \( c \), \( L(v) \) approaches zero.
Relativistic Effects
Relativistic effects are phenomena that occur when objects travel at speeds close to that of light. These effects fundamentally change how we perceive time and space, significantly differing from classical Newtonian mechanics.
One of the key ideas involves not just length contraction, but also time dilation and mass increase. These all arise because the laws of physics and the speed of light remain invariant, no matter the observer's frame of reference.
One of the key ideas involves not just length contraction, but also time dilation and mass increase. These all arise because the laws of physics and the speed of light remain invariant, no matter the observer's frame of reference.
- As speed increases, time for the moving object slows down relative to a stationary observer (time dilation).
- The mass of the moving object increases, requiring more energy to continue accelerating.
- Length contraction, as previously mentioned, causes the object to appear shorter in the direction of motion.
Velocity and Speed of Light
A core principle of the Theory of Relativity is that no object with mass can travel at or faster than the speed of light, \( c = 300,000 \text{ km/s} \). This speed limit is fundamental and dictates many relativistic effects.
Consider the spaceship from our earlier example. As its velocity \( v \) approaches the speed of light, its relativistic mass increases dramatically, requiring more and more energy to continue accelerating.
Consider the spaceship from our earlier example. As its velocity \( v \) approaches the speed of light, its relativistic mass increases dramatically, requiring more and more energy to continue accelerating.
- The equation \( L(v) = 10 \sqrt{1 - \frac{v^2}{c^2}} \) illustrates that as \( v \rightarrow c \), \( \frac{v^2}{c^2} \rightarrow 1 \), thus making the multiplier 0 and shrinking the object’s length to nearly zero.
- Any effort to reach the speed of light is met with resistance due to increasing relativistic mass, making \( c \) unreachable for objects with mass.
Other exercises in this chapter
Problem 75
Find a function whose graph is the given curve. The line segment joining the points \((-2,1)\) and \((4,-6)\)
View solution Problem 75
\(75-82\) a Determine whether the function \(f\) is even, odd, or neither. If \(f\) is even or odd, use symmetry to sketch its graph. $$ f(x)=x^{4} $$
View solution Problem 76
The given function is not one-to-one. Restrict its domain so that the resulting function \(i s\) one-to-one. Find the inverse of the function with the restricte
View solution Problem 76
Find a function whose graph is the given curve. The line segment joining the points \((-3,-2)\) and \((6,3)\)
View solution