Problem 75
Question
In Exercises \(61-86,\) use reference angles to find the exact value of each expression. Do not use a calculator. $$\tan \left(-\frac{\pi}{4}\right)$$
Step-by-Step Solution
Verified Answer
\(\tan \left(-\frac{\pi}{4}\right) = -1\).
1Step 1: Convert the negative angle into positive
Let's convert the negative angle into its positive equivalent first. Remember that negative angles are clockwise rotations, while positive angles are counterclockwise. The positive equivalent of a negative angle can be obtained by adding \(2\pi\). However, because \(-\frac{\pi}{4}\) is equivalent to its positive counterpart +\(\frac{7\pi}{4}\), there is no need to add \(2\pi\). The reference angle is then \(+\frac{\pi}{4}\).
2Step 2: Determine the value for the positive angle
The tangent of any angle in the unit circle is given by the ratio of the sine and cosine of that angle. For \(\frac{\pi}{4}\), both the sine and cosine values are \(+\frac{1}{\sqrt{2}}\) (or \(+\frac{\sqrt{2}}{2}\) when rationalized). Thus, \(\tan\left(\frac{\pi}{4}\right) = \frac{\sin\left(\frac{\pi}{4}\right)}{\cos\left(\frac{\pi}{4}\right)} = 1\).
3Step 3: Consider the sign of the original angle
The original angle was negative, indicating that the value occurs in a quadrant where tangent is negative. Given that \(\tan(-\theta) = -\tan(\theta)\) for any angle \(\theta\), the value of \(\tan\left(-\frac{\pi}{4}\right) = - \tan\left(+\frac{\pi}{4}\right) = -1\). Thus, the tangent of \(-\frac{\pi}{4}\) is \(-1\).
Other exercises in this chapter
Problem 75
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\tan ^{2} 15^{\circ}-\
View solution Problem 75
Express each angular speed in radians per second. 6 revolutions per second
View solution Problem 75
Let $$ \sin t=a, \cos t=b, \text { and } \tan t=c $$ Write each expression in terms of \(a, b,\) and \(c\). $$\sin (t+2 \pi)-\cos (t+4 \pi)+\tan (t+\pi)$$
View solution Problem 75
Determine whether each statement makes sense or does not make sense, and explain your reasoning. I analyzed simple harmonic motion in which the period was 10 se
View solution