Problem 75
Question
If you have a ring that contains \(1.94 \mathrm{~g}\) gold, calculate how many gold atoms are in the ring.
Step-by-Step Solution
Verified Answer
The ring contains approximately \(5.93 \times 10^{21}\) gold atoms.
1Step 1: Identify the known values
To solve the problem, we first need to list the known values:- The mass of gold: 1.94 g- Molar mass of gold (Au): 197 g/mol. This is the standard atomic weight of gold.- Avogadro's number: \(6.022 \times 10^{23}\) atoms/mol.
2Step 2: Calculate moles of gold
Use the molar mass of gold to convert the given mass into moles. The formula to calculate moles from mass is: \[\text{moles} = \frac{\text{mass in grams}}{\text{molar mass in g/mol}}\]Substitute the known values:\[\text{moles of gold} = \frac{1.94 \, \text{g}}{197 \, \text{g/mol}} \approx 0.00985 \, \text{mol}\]
3Step 3: Calculate the number of gold atoms
To find the number of atoms, multiply the moles of gold by Avogadro's number. The formula is:\[\text{Number of atoms} = \text{moles} \times \text{Avogadro's number}\]Substitute the values we have:\[\text{Number of gold atoms} = 0.00985 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 5.93 \times 10^{21} \, \text{atoms}\]
Key Concepts
Molar MassAvogadro's NumberMole Concept
Molar Mass
Understanding molar mass helps us relate mass and moles. The molar mass of an element or compound is the mass of one mole of its particles. For atoms like gold (Au), the molar mass matches its standard atomic weight measured in grams per mole (g/mol).
For gold, the molar mass is approximately 197 g/mol, reflecting the average mass of a mole of gold atoms.
For gold, the molar mass is approximately 197 g/mol, reflecting the average mass of a mole of gold atoms.
- This value accounts for isotopic distribution of gold but is often rounded when used in calculations.
- \( \text{moles} = \frac{\text{mass in grams}}{\text{molar mass in g/mol}} \)
Avogadro's Number
Avogadro's number, a fundamental constant in chemistry, allows us to scale atomic scale quantities to macroscopic levels. It is the number of particles, usually atoms or molecules, in one mole of a substance.
- Numerically, Avogadro's number is \( 6.022 \times 10^{23} \) particles per mole.
- For ease of calculation, consider that one mole of gold atoms equals \( 6.022 \times 10^{23} \) gold atoms.
Mole Concept
The mole is a central concept in chemistry, serving as a bridge between the atomic and macroscopic worlds. It lets us understand how the tiny particles that make up matter translate into quantities we can see and measure.
Key aspects of the mole concept include:
Key aspects of the mole concept include:
- One mole is defined as \( 6.022 \times 10^{23} \) particles, also known as Avogadro’s number.
- It represents a definite number of atoms, molecules, or ions present in a substance.
- You can calculate moles from mass using the formula \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \).
- The number of molecules or atoms can be found by multiplying the number of moles by Avogadro’s number.
Other exercises in this chapter
Problem 73
Calculate the amount of substance for each sample: (a) \(16.0 \mathrm{~g} \mathrm{Na}\) (b) \(0.0034 \mathrm{~g}\) platinum (c) \(1.54 \mathrm{~g} \mathrm{P}\)
View solution Problem 74
If you have a \(35.67-\mathrm{g}\) piece of chromium metal on your car, calculate how many chromium atoms you have.
View solution Problem 76
You have a pure sample of the antiseptic aminacrine, \(\mathrm{C}_{13} \mathrm{H}_{10} \mathrm{~N}_{2}\) (a) Calculate the mass in grams of 0.06500 mol aminacri
View solution Problem 77
You have a pure sample of apholate, \(\mathrm{C}_{12} \mathrm{H}_{24} \mathrm{~N}_{9} \mathrm{P}_{3},\) a highly effective commercial insecticide. (a) Calculate
View solution