Problem 75
Question
Find the distance between the centers of the circles with equations \((x-5)^{2}+(y-1)^{2}=16\) and \((x+1)^{2}+(y-9)^{2}=49\)
Step-by-Step Solution
Verified Answer
The distance between the centers of the circles is 10 units.
1Step 1: Identify the Centers of the Circles
The centers of the circles can be determined by looking at the coefficients in the circle equations. If \((x-a)^2 + (y-b)^2 = r^2\) is the equation of a circle, \((a, b)\) is the center of the circle. Thus, for the circle with equation \((x-5)^{2}+(y-1)^{2}=16\), the center is \((5, 1)\), and for the circle with equation \((x+1)^{2}+(y-9)^{2}=49\), the center is \((-1,9)\).
2Step 2: Apply the Distance Formula
You can now calculate the distance between the two centers using the distance formula. This formula is \(\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}\). In this case, \((x_{1}, y_{1})\) are the coordinates of the center of the first circle, \((5, 1)\) and \((x_{2}, y_{2})\) are the coordinates of the center of the second circle, \((-1, 9)\).
3Step 3: Calculate the Distance
Substituting these values into the distance formula, we have \(\sqrt{((-1)-5)^2 + (9-1)^2} = \sqrt{(-6)^2 + 8^2 = 36 + 64} = \sqrt{100}\).
Key Concepts
Center of a CircleDistance FormulaCircle Equations
Center of a Circle
Understanding the center of a circle is vital when dealing with circle equations. In any standard circle equation of the form \[ (x-a)^2 + (y-b)^2 = r^2 \] the point \((a, b)\) denotes the center. Here, \(a\) and \(b\) are the values subtracted from the \(x\) and \(y\) terms, respectively. This equation implies that the circle is plotted around the center at \((a, b)\) with a radius of \(r\). Furthermore, this center serves as a reference for various circle properties like the diameter, circumference, and position in the Cartesian plane.
Using the given exercise as an example, let's identify the centers for the circles involved:
Using the given exercise as an example, let's identify the centers for the circles involved:
- The equation \((x-5)^2 + (y-1)^2 = 16\) reveals that the center is at \((5, 1)\).
- Similarly, for \((x+1)^2 + (y-9)^2 = 49\), the center is \((-1, 9)\).
Distance Formula
The distance formula is a handy tool to calculate the straight-line distance between two points in a coordinate plane. If given two points, \((x_1, y_1)\) and \((x_2, y_2)\), the formula is expressed as:\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] This formula is derived from the Pythagorean theorem and is crucial in geometry and algebra. It allows for the measurement of how far apart two locations are, which is particularly useful in various applications, such as navigation, physics, and engineering.
Applying this formula to the centers we found:
Applying this formula to the centers we found:
- The center of the first circle is \((5, 1)\)
- The center of the second is \((-1, 9)\)
Circle Equations
An equation of a circle describes all the points that make up a circle in a coordinate plane. The general form of this equation is:\[ (x-a)^2 + (y-b)^2 = r^2 \] In this format:
In the example provided, each equation gives insight into the respective circle’s shape:
- \((a, b)\) represents the center of the circle.
- \(r\) is the radius, which is the distance from the center to any point on the circle.
In the example provided, each equation gives insight into the respective circle’s shape:
- The equation \((x-5)^2 + (y-1)^2 = 16\) shows a circle with a radius 4, centered at \((5, 1)\).
- Similarly, \((x+1)^2 + (y-9)^2 = 49\) indicates a circle with a radius 7, centered at \((-1, 9)\).
Other exercises in this chapter
Problem 75
Find the asymptotes of the graph of each equation. $$ y=\frac{5}{x+5}+2 $$
View solution Problem 75
Simplify each expression. 4 \(\ln e^{2}\)
View solution Problem 76
Simplify each expression. What are the restrictions on the variable? $$ \frac{x^{2}-36}{x^{2}+5 x-6} $$
View solution Problem 76
Find the asymptotes of the graph of each equation. $$ y=\frac{2}{x-3}-1 $$
View solution