Problem 75
Question
Find each product. $$ (a+b)(a+2 b) $$
Step-by-Step Solution
Verified Answer
The product is \(a^2 + 3ab + 2b^2\).
1Step 1: Apply the Distributive Property
To find the product of two binomials, we need to apply the distributive property. Distribute each term in the first binomial across the second binomial: \[(a+b)(a+2b) = a(a+2b) + b(a+2b)\]
2Step 2: Distribute Each Term Separately
Now distribute each term separately within the parentheses: * Distribute \(a\): \[a(a+2b) = a \cdot a + a \cdot 2b = a^2 + 2ab\]* Distribute \(b\): \[b(a+2b) = b \cdot a + b \cdot 2b = ab + 2b^2\]
3Step 3: Combine Like Terms
Next, combine the like terms from the expression obtained in the previous step:\[a^2 + 2ab + ab + 2b^2\] Add the like terms \(2ab\) and \(ab\): \[a^2 + 3ab + 2b^2\]
4Step 4: Write the Final Expression
After combining like terms, the final expression of the product is: \[a^2 + 3ab + 2b^2\]
Key Concepts
Distributive PropertyCombining Like TermsPolynomial ExpressionAlgebraic Manipulation
Distributive Property
The distributive property is a fundamental principle in algebra that lets us multiply a single term by two or more terms inside a set of parentheses. In the problem \((a+b)(a+2b)\), the distributive property allows us to tackle each part of the multiplication separately.
By distributing each term of the first binomial across the second binomial, we transform the expression into something more manageable.
By distributing each term of the first binomial across the second binomial, we transform the expression into something more manageable.
- First, multiply both terms inside the second binomial,\((a+2b)\), by the first term of the first binomial, \(a\).
- Then, do the same for the second term of the first binomial, \(b\).
Combining Like Terms
Combining like terms is an essential skill to simplify expressions by merging terms with the same variable and power.In our solution, after applying the distributive property, we arrive at the expanded expression: \[a^2 + 2ab + ab + 2b^2\].
"Like terms" are terms that have identical variable components. In the expression, \(2ab\) and \(ab\) are like terms because they both contain \(a\) and \(b\) to the first power.
"Like terms" are terms that have identical variable components. In the expression, \(2ab\) and \(ab\) are like terms because they both contain \(a\) and \(b\) to the first power.
- We add these coefficients to simplify the expression, resulting in \(3ab\).
- The operation simplifies our polynomial to \(a^2 + 3ab + 2b^2\).
Polynomial Expression
A polynomial expression consists of multiple terms combined by addition or subtraction, where each term contains variables raised to non-negative integer powers. In the example \[(a+b)(a+2b)\],when expanded using distributive property and combining like terms, we obtain \[a^2 + 3ab + 2b^2\].
It's vital to recognize different parts of a polynomial, such as:
It's vital to recognize different parts of a polynomial, such as:
- "Terms" like \(a^2\), \(3ab\), and \(2b^2\).
- "Coefficients," which are the numerical parts of the terms, like 1 in \(a^2\) and 3 in \(3ab\).
Algebraic Manipulation
Algebraic manipulation refers to methods used to rearrange and simplify expressions in algebra. In solving \((a+b)(a+2b)\), we applied various manipulation techniques:
Such manipulations are critical in solving algebraic equations, enabling the rounding down of long and convoluted expressions into simple, understandable equations.Whether it's balancing equations or factoring, these techniques underpin algebraic problem-solving.
- We used the distributive property to expand the product of two binomials.
- Combining like terms to further simplify the result.
Such manipulations are critical in solving algebraic equations, enabling the rounding down of long and convoluted expressions into simple, understandable equations.Whether it's balancing equations or factoring, these techniques underpin algebraic problem-solving.
Other exercises in this chapter
Problem 75
Find each power. $$ (2 \sqrt{x}-3)^{2} $$
View solution Problem 75
Evaluate each expression. \(\frac{1}{3}+\frac{3}{4}\)
View solution Problem 76
Evaluate each expression. \(\frac{1}{8}+\frac{5}{12}\)
View solution Problem 76
Find each product. $$ (x-3 y)(x+3 y) $$
View solution