Problem 75
Question
Explain how to verify an identity.
Step-by-Step Solution
Verified Answer
To verify an identity, choose either the more complex side or any side if both are equally complex, simplify the side using known identities and basic operations, and then compare with the other side to confirm if the identity is verified.
1Step 1: Understand the Problem
An identity is an equation that is true for all values of the variable in its domain. Verify means to prove or check whether it is true. However, remember that you can perform operations on both sides independently to make them look identical.
2Step 2: Start On One Side
Choose the more complicated side of the equation. If both sides are equally complex, choose either side. Make this side, your 'working-side' from now on.
3Step 3: Use Known Identities
Use the appropriate identities in order to simplify the working side of the equation. You may replace sin^2 x with 1 - cos^2 x or cos^2 x with 1 - sin^2 x. Similarly if you have a tan x = sin x/cos x, sin^2 x + cos^2 x = 1 and many more.
4Step 4: Simplify The Equation
Simplify the working side as much as possible using responses from elementary operations such as addition, subtraction, multiplication and division. Break up fractions or combine fractions as needed.
5Step 5: Compare With Other Side
After simplification, the working side should be the same as the non-working side. If both the sides are not identical, check the work. If they look identical, the identity is verified.
Other exercises in this chapter
Problem 74
Rewrite each expression in terms of the given function or functions. \(\frac{1-\sin x}{1+\sin x}-\frac{1+\sin x}{1-\sin x} ; \sec x\) and \(\tan x\)
View solution Problem 75
Use an identity to solve each equation on the interval \([0,2 \pi)\) $$ \sin x \cos x=\frac{\sqrt{2}}{4} $$
View solution Problem 76
Use an identity to solve each equation on the interval \([0,2 \pi)\) $$ \sin x \cos x=\frac{\sqrt{3}}{4} $$
View solution Problem 76
Describe two strategies that can be used to verify identities.
View solution