Problem 75
Question
Combine the types of equations we have discussed in this section. Solve each equation. Then state whether the equation is an identity, a conditional equation, or an inconsistent equation. \(\frac{2}{x}+\frac{1}{2}=\frac{3}{4}\)
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 8\) and it is a conditional equation.
1Step 1: Getting rid of Denominators
Multiplying each term by the least common denominator (LCD) of 4x will eliminate the denominators from the equation. As such, the equation becomes: \(4x*\frac{2}{x} + 4x*\frac{1}{2} = 4x*\frac{3}{4}\). This simplifies to \(8 + 2x = 3x\)
2Step 2: Solving for x
Use algebraic manipulation to solve for \(x\). First, subtract \(2x\) from both sides of the equation, resulting in \(8 = x\).
3Step 3: Identify the Type of Equation
Substitute \(8\) for \(x\) in the original equation and check if both sides are equal. If both sides equal, then the equation is a conditional equation, as it has exactly one solution. If they don't equal, then the equation is an inconsistent equation. However, as both sides are equal when \(x=8\), we classify it as a conditional equation.
Key Concepts
Conditional EquationsInconsistent EquationsIdentity Equations
Conditional Equations
A conditional equation is a type of equation that is true for certain values of the variable but not for others. In our exercise, we found that the equation \(\frac{2}{x} + \frac{1}{2} = \frac{3}{4}\) simplifies to \(8 + 2x = 3x\). Solving gives \(x = 8\) as the only solution.
When you solve a conditional equation, you find a specific value (or values) that make the equation true. If you substitute any other number in place of \(x\), the equation will not hold.
Here are some characteristics of conditional equations:
When you solve a conditional equation, you find a specific value (or values) that make the equation true. If you substitute any other number in place of \(x\), the equation will not hold.
Here are some characteristics of conditional equations:
- They have one or a few specific solutions.
- If the variable is substituted with a wrong value, the equation does not balance.
- They are common in algebraic problem-solving.
Inconsistent Equations
Inconsistent equations are those that have no solution. This means there are no values for which the equation is true. These typically occur when, through manipulation, you reach a contradiction—like 0 = 5—which is obviously false.
When dealing with algebra, identifying an inconsistent equation is crucial because it prevents futile attempts to find a solution.
Key features of inconsistent equations include:
When dealing with algebra, identifying an inconsistent equation is crucial because it prevents futile attempts to find a solution.
Key features of inconsistent equations include:
- They result in a false statement after simplifying.
- No value of the variable makes both sides of the equation equal.
Identity Equations
An identity equation is an equation that is true for all values of the variables involved. Unlike conditional equations, identity equations hold irrespective of what values are used in them.
A classic example is \(x + 0 = x\); it's always true, no matter what \(x\) represents.
Features of identity equations include:
A classic example is \(x + 0 = x\); it's always true, no matter what \(x\) represents.
Features of identity equations include:
- They simplify to a statement that is always true, such as 0 = 0.
- They have an infinite number of solutions.
- You can't pin down a specific solution like you would in a conditional equation because every number works.
Other exercises in this chapter
Problem 75
Solve each absolute value inequality. $$\left|\frac{2 x+2}{4}\right| \geq 2$$
View solution Problem 75
Solve each absolute value equation or indicate that the equation has no solution. $$ |2 x-1|+3=3 $$
View solution Problem 76
Write an original word problem that can be solved using a linear equation. Then solve the problem.
View solution Problem 76
Perform the indicated operations and write the result in standard form. $$ \frac{1+i}{1+2 i}+\frac{1-i}{1-2 i} $$
View solution