Problem 75
Question
Combine: \(\frac{x}{3}-\frac{x-1}{4}+\frac{x+1}{2}\)
Step-by-Step Solution
Verified Answer
\(\frac{7x + 9}{12}\)
1Step 1 - Find the Common Denominator
Identify the denominators in the expression: 3, 4, and 2. The least common multiple (LCM) of these numbers is 12. Therefore, the common denominator is 12.
2Step 2 - Rewrite Each Fraction with the Common Denominator
Convert each fraction to have the common denominator of 12. \(\frac{x}{3} = \frac{4x}{12}\), \(\frac{x-1}{4} = \frac{3(x-1)}{12} = \frac{3x-3}{12}\), \(\frac{x+1}{2} = \frac{6(x+1)}{12} = \frac{6x+6}{12}\)
3Step 3 - Combine the Numerators
Since all fractions now have the same denominator, we can add the numerators: \(\frac{4x}{12} - \frac{3x-3}{12} + \frac{6x+6}{12}\). Combine the numerators: \(4x - (3x-3) + (6x+6)\)
4Step 4 - Simplify the Numerator
Distribute and combine like terms in the numerator: \(4x - 3x + 3 + 6x + 6 = 7x + 9\)
5Step 5 - Write the Final Fraction
Put the simplified numerator over the common denominator: \(\frac{7x + 9}{12}\)
Key Concepts
Common DenominatorsLeast Common MultipleFraction Addition in AlgebraCombining Like Terms
Common Denominators
In algebra, when working with fractions, especially when adding or subtracting, we need a common denominator. A common denominator is a shared multiple of the denominators of two or more fractions. This allows us to combine the fractions smoothly.
To find a common denominator, follow these steps:
To find a common denominator, follow these steps:
- Identify the denominators of each fraction. In our exercise, these are 3, 4, and 2.
- Determine the least common multiple (LCM) of these denominators. The LCM of 3, 4, and 2 is 12.
- Rewrite each fraction with this common denominator.
Least Common Multiple
The Least Common Multiple (LCM) is the smallest number that is a multiple of two or more numbers. It's a key concept when finding common denominators.
To find the LCM of a set of numbers:
To find the LCM of a set of numbers:
- List the multiples of each number.
- Identify the smallest multiple that appears in all lists.
- Multiples of 3: 3, 6, 9, 12, 15, ...
- Multiples of 4: 4, 8, 12, 16, 20, ...
- Multiples of 2: 2, 4, 6, 8, 10, 12, ...
Fraction Addition in Algebra
Adding fractions in algebra involves more steps than simple arithmetic addition. Here's the process:
- Find a common denominator for all fractions, typically the LCM.
- Rewrite each fraction so they have this common denominator.
- Combine the numerators, keeping the common denominator the same.
- Simplify the resulting fraction, if possible.
- Convert each fraction to have the denominator of 12, resulting in \(\frac{4x}{12}, \frac{3(x-1)}{12}, \frac{6(x+1)}{12}\).
- Combine the numerators: \(\frac{4x}{12} - \frac{3(x-1)}{12} + \frac{6(x+1)}{12}\), which simplifies to \(\frac{4x - 3x + 3 + 6x + 6}{12}\).
Combining Like Terms
Combining like terms is a crucial step in simplifying algebraic expressions, including those involving fractions. Like terms are terms that have the same variables raised to the same power. When combining them, just add or subtract their coefficients.
For example, in the expression 4x - (3x - 3) + (6x + 6), we follow these steps:
Combining like terms helps make the expression easier to work with, especially when dealing with algebraic fractions.
For example, in the expression 4x - (3x - 3) + (6x + 6), we follow these steps:
- Distribute any negative signs: 4x - 3x + 3 + 6x + 6
- Identify and group like terms: 4x, -3x, and 6x are like terms.
- Combine these terms: 4x - 3x + 6x = 7x.
- Add constant terms separately: 3 + 6 = 9.
Combining like terms helps make the expression easier to work with, especially when dealing with algebraic fractions.
Other exercises in this chapter
Problem 73
Solve the following problem algebraically. Be sure to label what the variable represents. Lamont has invested \(\$ 1,300\) in a savings account that pays \(4 \%
View solution Problem 74
Solve for \(x: \frac{x}{3}-\frac{x-1}{4}=\frac{x+1}{2}\)
View solution Problem 76
Solve the following problem algebraically. Be sure to label what the variable represents. Tamika leaves point \(A\) at 10: 00 A.M. traveling due east at 60 kph.
View solution Problem 73
How could you use the idea of slope to show that the three points \((-1,-2)\) \((2,0),\) and \((5,2)\) all lie on a straight line?
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