Problem 75
Question
Assign the IUPAC name for the following compound. (a) 3,4 -dichloroazobenzene (b) (4-chlorophenyl) (3-chlorophenyl) diazene (c) 3,4 -bis(chlorophenyl) diazene (d) (3-chlorophenyl) (4-chlorophenyl) diazene
Step-by-Step Solution
Verified Answer
Option (d) (3-chlorophenyl) (4-chlorophenyl) diazene is the correct IUPAC name.
1Step 1: Analyze the Structure
Examine the name given in the option. Option (b) is stated as (4-chlorophenyl) (3-chlorophenyl) diazene, indicating two phenyl groups, each containing a single chlorine atom at different positions, joined by a diazene linkage (-N=N-). The first phenyl ring has the chlorine at position 4, and the second phenyl ring has the chlorine at position 3.
2Step 2: Understand Substituent Positions
The IUPAC naming convention assigns substituents' positions based on attachment to the parent hydrocarbon. In option (b), (4-chlorophenyl) indicates that the chlorine is on the 4th position of the first benzene ring, while (3-chlorophenyl) indicates that the chlorine is on the 3rd position of the second benzene ring.
3Step 3: Determine Main Functional Group
The diazene group (-N=N-) is the main linking functional group between the two phenyl rings. In diazenes, the naming typically focuses on the substituents on the phenyl rings.
4Step 4: Assign Correct IUPAC Name
By IUPAC rules, we list out the substituents with their respective position numbers, and then name the compound according to alphabetical order of substituents and symmetry. Here, option (d) is correctly ordered: (3-chlorophenyl) (4-chlorophenyl) diazene indicates correct positions and respects IUPAC naming conventions by prioritizing the chlorophenyl groups.
Key Concepts
Substituent PositionsPhenyl RingsDiazene Linkage
Substituent Positions
The placement of substituents is crucial when naming chemical compounds using the IUPAC system. In our example, substituents refer to the chlorine atoms attached to the phenyl rings. Position numbers are assigned to these substituents based on their location relative to a reference point in the ring, often the position of a specified group or a point of attachment to a chain.
For a mono-substituted benzene ring, the substituent receives the lowest possible position number, typically starting from one of the carbons adjacent to any functional group present.
In the compound (4-chlorophenyl) (3-chlorophenyl) diazene, the numbers 3 and 4 specify where each chlorine atom is attached on its respective phenyl ring. This approach permits chemists to accurately describe where on the molecule each substituent is located, a critical requirement for communication and understanding in chemistry.
For a mono-substituted benzene ring, the substituent receives the lowest possible position number, typically starting from one of the carbons adjacent to any functional group present.
In the compound (4-chlorophenyl) (3-chlorophenyl) diazene, the numbers 3 and 4 specify where each chlorine atom is attached on its respective phenyl ring. This approach permits chemists to accurately describe where on the molecule each substituent is located, a critical requirement for communication and understanding in chemistry.
Phenyl Rings
Phenyl rings are a fundamental component in organic chemistry, representing the benzene ring minus one hydrogen atom, usually denoted as -C₆H₅. Phenyl groups are quite common due to their planar structure and unique electronic properties, which contribute to stability through resonance.
When phenyl groups appear in a compound, they can be either substituted or unsubstituted by various other groups. This can greatly affect the chemical and physical properties of the overall compound.
In the context of the given problem, each phenyl ring has a chlorine substituent, creating a substituted phenyl group. These substitutions are key to naming the compound as they impact both the structure and its corresponding IUPAC name.
When phenyl groups appear in a compound, they can be either substituted or unsubstituted by various other groups. This can greatly affect the chemical and physical properties of the overall compound.
In the context of the given problem, each phenyl ring has a chlorine substituent, creating a substituted phenyl group. These substitutions are key to naming the compound as they impact both the structure and its corresponding IUPAC name.
Diazene Linkage
The diazene linkage, expressed as (-N=N-), is a functional group that connects two phenyl rings in the compound. Known as an azo linkage as well, this connection involves two nitrogen atoms double-bonded to each other.
Diazene linkages are prominent in azo compounds, often manifesting in vivid colors and widely used in dyes and pigments. The presence of this linkage between the phenyl groups is the principal feature for determining the compound's name.
In IUPAC naming, the linkage's presence does not alter the substituent positions on the phenyl rings but significantly contributes to the compound's functionality and categorization. It's vital to ensure correct positioning of substituents relative to the diazene linkage for accurate chemical identification.
Diazene linkages are prominent in azo compounds, often manifesting in vivid colors and widely used in dyes and pigments. The presence of this linkage between the phenyl groups is the principal feature for determining the compound's name.
In IUPAC naming, the linkage's presence does not alter the substituent positions on the phenyl rings but significantly contributes to the compound's functionality and categorization. It's vital to ensure correct positioning of substituents relative to the diazene linkage for accurate chemical identification.
Other exercises in this chapter
Problem 70
On monochlorination of \(n\)-pentane, the number of isomers formed is are (a) 4 (b) 3 (c) 2 (d) 1
View solution Problem 71
The number of possible open chain (acyclic) isomeric compounds for molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10}\) would be (a) 5 (b) 6 (c) 7 (d) 4
View solution Problem 80
A compound with molecular formula \(\mathrm{C}_{7} \mathrm{H}_{16}\) shows optical isomerism. The compound will be (a) 2 -methylhexane (b) 2,2 -dimethylpentane
View solution Problem 82
Which of the following represents the given mode of hybridization \(s p^{2}-s p^{2}-s p-\) sp from left to right? (a) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{C} \
View solution