Problem 75
Question
(a) Determine the number of calcium ions in the chemical formula of the mineral hardystonite, \(\mathrm{Ca}_{x} \mathrm{Zn}\left(\mathrm{Si}_{2} \mathrm{O}_{7}\right)\). (b) Determine the number of hydroxide ions in the chemical formula of the mineral pyrophyllite, \(\mathrm{Al}_{2}\left(\mathrm{Si}_{2} \mathrm{O}_{5}\right)_{2}(\mathrm{OH})_{x}\).
Step-by-Step Solution
Verified Answer
(a) The number of calcium ions in hardystonite, \(\mathrm{Ca}_{x} \mathrm{Zn}\left(\mathrm{Si}_{2} \mathrm{O}_{7}\right)\), is 2.
(b) There appears to be an error in the given formula for pyrophyllite, as a negative number of hydroxide ions was calculated. Please double-check the chemical formula and follow a similar process to find the number of hydroxide ions once the correct formula is provided.
1Step 1: (Finding the number of calcium ions in hardystonite)
To determine the number of calcium ions in hardystonite, we need to consider the overall charge of the compound. Hardystonite is a neutral compound, meaning that the total positive charge from the cations must balance the total negative charge from the anions.
The charges for each ion are as follows:
- Calcium ion \(\mathrm{(Ca)}\): +2
- Zinc ion \(\mathrm{(Zn)}\): +2
- Silicate group \(\mathrm{(Si}_{2} \mathrm{O}_{7})\): -6
Let's write an equation to represent the total charge of the compound:
$$+2x + 2 = 6$$
Solving for x, we get the number of calcium ions in hardystonite.
2Step 2: (Step 1: Solving Hardystonite Charge Equation)
Our equation for the total charge of hardystonite is:
$$2x + 2 = 6$$
Subtract 2 from both sides of the equation:
$$2x = 4$$
Now, divide by 2 to isolate x:
$$x = 2$$
So, there are 2 calcium ions in the chemical formula of hardystonite: \(\mathrm{Ca}_{2} \mathrm{Zn}\left(\mathrm{Si}_{2} \mathrm{O}_{7}\right)\).
Next, let's determine the number of hydroxide ions in pyrophyllite.
3Step 3: (Finding the number of hydroxide ions in pyrophyllite)
First, we need to find the charge of the pyrophyllite compound. This compound is also neutral, so the total positive charge from the cations must balance the total negative charge from the anions.
The charges for each ion are as follows:
- Aluminum ion \(\mathrm{(Al)}\): +3
- Silicate group \(\mathrm{(Si}_{2} \mathrm{O}_{5})\): -10
- Hydroxide ion \(\mathrm{(OH)}\): -1
Since there are two aluminum ions and two silicate groups, we can write an equation to represent the total charge of the compound:
$$2(3) + 2(-10) + (-1)x = 0$$
Solving for x, we find the number of hydroxide ions in pyrophyllite.
4Step 4: (Step 2: Solving Pyrophyllite Charge Equation)
Our equation for the total charge of pyrophyllite is:
$$6 - 20 + (-1)x = 0$$
Add 20 to both sides of the equation:
$$-1x = 14$$
Now, multiply by -1 to isolate x:
$$x = -14$$
We cannot have a negative number of hydroxide ions, so there must be an error in the given formula. Please double-check the chemical formula of pyrophyllite and ensure that it is correct before proceeding. Once the correct formula is provided, you can follow a similar process to find the number of hydroxide ions.
Key Concepts
Calcium IonsHydroxide IonsCharge Balancing
Calcium Ions
Calcium ions are represented by the symbol \( \text{Ca}^{2+} \) and play an essential role in many chemical compounds. They are a type of cation, which means they have a positive charge. In the case of the mineral hardystonite, calcium ions contribute a \(+2\) charge each. To determine how many calcium ions are in a compound like hardystonite, we balance the total positive and negative charges to keep the compound neutral.
In our original exercise, we learned there are two calcium ions in hardystonite, represented chemically as \( \text{Ca}_{2}\text{Zn(Si}_2\text{O}_7) \). Here are some steps you typically follow to find the number of calcium ions:
In our original exercise, we learned there are two calcium ions in hardystonite, represented chemically as \( \text{Ca}_{2}\text{Zn(Si}_2\text{O}_7) \). Here are some steps you typically follow to find the number of calcium ions:
- Identify the charge of each ion and group in the compound.
- Form an equation that combines these charges to add up to zero, ensuring a neutral compound.
- Solve the equation for the number of calcium ions.
Hydroxide Ions
Hydroxide ions, denoted as \( \text{OH}^{-} \), consist of one oxygen and one hydrogen atom. They are anions, carrying a negative charge of \(-1\). These ions are vital in compounds, particularly in bases, and affect how these compounds interact in chemical reactions.
The exercise involving pyrophyllite posed a challenge when attempting to balance the number of hydroxide ions. This usually involves figuring out how these ions balance with the positive charges in the compound to maintain neutrality. For pyrophyllite, errors in the chemical formula might yield confusing results, such as a negative number of hydroxide ions. These outcomes suggest the need to revisit and correct any formula mistakes before accurately calculating the number of ions.
The exercise involving pyrophyllite posed a challenge when attempting to balance the number of hydroxide ions. This usually involves figuring out how these ions balance with the positive charges in the compound to maintain neutrality. For pyrophyllite, errors in the chemical formula might yield confusing results, such as a negative number of hydroxide ions. These outcomes suggest the need to revisit and correct any formula mistakes before accurately calculating the number of ions.
- Check the validity of the chemical formula provided.
- Understand the typical charges for each section of the formula.
- Remain cautious of calculation steps to ensure no arithmetic errors occur.
Charge Balancing
Charge balancing is a fundamental aspect of chemistry. It ensures that a compound's total positive charges from the cations equal the total negative charges from the anions, resulting in a neutrally charged compound.
This process involves writing out an equation where the sum of the positive and negative charges equals zero. This method helps determine unknown quantities in a compound, like the number of certain ions. In our exercises:
This process involves writing out an equation where the sum of the positive and negative charges equals zero. This method helps determine unknown quantities in a compound, like the number of certain ions. In our exercises:
- For hardystonite, the charge-balancing equation was \( +2x + 2 = 6 \), solving for \( x \) gave us two calcium ions.
- For pyrophyllite, the equation was \( 6 - 20 + (-1)x = 0 \), leading to a problematic result, highlighting the importance of having accurate formulas before solving.
Other exercises in this chapter
Problem 70
Write the formulas for the following compounds, and indicate the oxidation state of the group 14 element or of boron in each: (a) stannous fluoride, (b) germane
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Select the member of group 14 that best fits each description: \((\mathbf{a})\) has the greatest tendency to form multiple bonds with itself, (b) forms polymeri
View solution Problem 76
(a) Determine the number of sodium ions in the chemical formula of albite, \(\mathrm{Na}_{x} \mathrm{AlSi}_{3} \mathrm{O}_{8} .(\mathbf{b})\) Determine the numb
View solution Problem 77
(a) How does the structure of diborane \(\left(\mathrm{B}_{2} \mathrm{H}_{6}\right)\) differ from that of ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right) ?\
View solution