Problem 75
Question
75\. Show that if \(g(x)=|f(x)|\) is continuous it is not necessarily true that \(f(x)\) is continuous.
Step-by-Step Solution
Verified Answer
If \(g(x) = |f(x)|\) is continuous, \(f(x)\) may still be discontinuous; see \(f(x) = -1\) for \(x=0\), \(1\) for \(x\neq 0\).
1Step 1: Understanding the Problem
To solve this problem, we need to provide an example where the function \(g(x) = |f(x)|\) is continuous, but the function \(f(x)\) itself is not continuous.
2Step 2: Choose a Function with Discontinuity
Let's consider the function \(f(x)\) defined as follows: \[ f(x) = \begin{cases} -1, & \text{if } x = 0 \ 1, & \text{if } x eq 0 \end{cases} \] This function is discontinuous at \(x = 0\) because the limit as \(x\) approaches 0 does not equal the value of \(f(0)\).
3Step 3: Construct \(g(x)\) using Absolute Value
We define \(g(x) = |f(x)|\). For our chosen \(f(x)\), we have: \[ g(x) = |f(x)| = \begin{cases} 1, & \text{if } x = 0 \ 1, & \text{if } x eq 0 \end{cases} \] Simplifying gives \(g(x) = 1\) for all \(x\), which is a constant function.
4Step 4: Prove Continuity of \(g(x)\)
The function \(g(x)\) is constant, and constant functions are continuous everywhere. Therefore, \(g(x)\) is continuous for all \(x\).
5Step 5: Conclude the Example
We have shown that \(g(x) = |f(x)|\) is continuous but \(f(x)\) is discontinuous at \(x = 0\). This example demonstrates that \(g(x) = |f(x)|\) being continuous does not imply that \(f(x)\) is continuous.
Key Concepts
Absolute ValueDiscontinuous FunctionConstant FunctionLimits
Absolute Value
Absolute value is a fundamental concept in mathematics that helps understand how far a number is from zero on the number line, regardless of direction. When we talk about the absolute value of a function, we are essentially transforming any negative outputs to positive ones, while leaving positive outputs unchanged.
For a function like \(f(x)\), its absolute value is represented as \(|f(x)|\). This transformation ensures that the output of \(|f(x)|\) is never negative, since the absolute value strips away any negative sign.
For a function like \(f(x)\), its absolute value is represented as \(|f(x)|\). This transformation ensures that the output of \(|f(x)|\) is never negative, since the absolute value strips away any negative sign.
- If \(f(x)\) is positive or zero, then \(|f(x)| = f(x)\).
- If \(f(x)\) is negative, then \(|f(x)| = -f(x)\), which results in a positive value.
Discontinuous Function
A function is said to be discontinuous at a point if there is a break, jump, or hole in its graph at that particular point. Specifically, for a function \(f(x)\), it is discontinuous at a point if the following conditions are not met:
This discrepancy at \(x = 0\) prevents \(f(x)\) from having a continuous path without breaks on the graph.
- The limit of \(f(x)\) as \(x\) approaches a point exists.
- The value of the function at that point exists.
- The limit value at that point equals the function value.
This discrepancy at \(x = 0\) prevents \(f(x)\) from having a continuous path without breaks on the graph.
Constant Function
A constant function is one of the simplest types of functions, where the output value remains the same regardless of the input. Mathematically, it is expressed as \(g(x) = c\), where \(c\) is a constant.
In our example, after applying the absolute value, the function \(g(x) = |f(x)|\) simplifies to \(g(x) = 1\). Here, for every value of \(x\), the result is consistently \(1\), showcasing the property of a constant function.
In our example, after applying the absolute value, the function \(g(x) = |f(x)|\) simplifies to \(g(x) = 1\). Here, for every value of \(x\), the result is consistently \(1\), showcasing the property of a constant function.
- Constant functions represent horizontal lines on a graph.
- They have no fluctuations, making them smooth and uniform across their domain.
Limits
Limits are a fundamental concept in calculus that describe the behavior of a function as it approaches a certain point. Understanding limits is crucial to discussing the continuity of a function.
For a limit to exist, the values of \(f(x)\) as \(x\) approaches a particular point from both the left and right must converge to the same value. This value is what we call the limit of the function as \(x\) approaches that point.
In the provided exercise, we saw that \(f(x)\) fails to meet this criterion at \(x = 0\), making it discontinuous. However, the absolute value transformation \(g(x) = |f(x)|\) effectively sidesteps this discontinuity by ensuring the left and right approach result in the same constant value.
For a limit to exist, the values of \(f(x)\) as \(x\) approaches a particular point from both the left and right must converge to the same value. This value is what we call the limit of the function as \(x\) approaches that point.
In the provided exercise, we saw that \(f(x)\) fails to meet this criterion at \(x = 0\), making it discontinuous. However, the absolute value transformation \(g(x) = |f(x)|\) effectively sidesteps this discontinuity by ensuring the left and right approach result in the same constant value.
- Limits help determine the continuity of a function at a specific point.
- They are key in defining derivatives and integrals in calculus.
Other exercises in this chapter
Problem 73
Let \(f(x+y)=f(x)+f(y)\) for all \(x\) and \(y\) and suppose that \(f\) is continuous at \(x=0\). (a) Prove that \(f\) is continuous everywhere. (b) Prove that
View solution Problem 74
Prove that if \(f(x)\) is a continuous function on an interval then so is the function \(|f(x)|=\sqrt{(f(x))^{2}}\).
View solution Problem 76
Let \(f(x)=0\) if \(x\) is irrational and let \(f(x)=1 / q\) if \(x\) is the rational number \(p / q\) in reduced form \((q>0)\). (a) Sketch (as best you can) t
View solution Problem 72
Suppose that \(f\) is continuous on \([a, b]\) and it is never zero there. Is it possible that \(f\) changes sign on \([a, b] ?\) Explain.
View solution