Problem 74
Question
Use an algebraic approach to solve each problem. Verify that for any three consecutive integers, the sum of the smallest and largest is equal to twice the middle integer. [Hint: Use \(n, n+1\), and \(n+2\) to represent the three consecutive integers.]
Step-by-Step Solution
Verified Answer
Sum of smallest and largest = 2 * middle integer; verified by algebra.
1Step 1: Define Consecutive Integers
Let the three consecutive integers be represented as: \(n, n+1, n+2\). Here, \(n\) is the smallest integer, \(n+1\) is the middle integer, and \(n+2\) is the largest integer.
2Step 2: Find the Sum of the Smallest and Largest
The sum of the smallest integer \(n\) and the largest integer \(n+2\) is given by: \(n + (n+2) = 2n + 2\).
3Step 3: Calculate Twice the Middle Integer
The middle integer is \(n+1\), so twice this integer is calculated as: \(2(n+1) = 2n + 2\).
4Step 4: Compare Both Sides
Both expressions from Step 2 and Step 3 are identical, i.e., \(2n + 2 = 2n + 2\). This confirms that the sum of the smallest and largest integer is indeed equal to twice the middle integer.
Key Concepts
Algebraic ApproachInteger VerificationSum of Integers
Algebraic Approach
To tackle a problem using an algebraic approach, we leverage algebraic expressions to represent unknown quantities. In the case of consecutive integers, this method simplifies the problem by expressing each integer as a term related to a common variable. For example:
- The smallest integer is denoted as \( n \).
- The next consecutive integer is \( n + 1 \).
- The largest consecutive integer is \( n + 2 \).
Integer Verification
Integer verification involves checking if a proposed relationship holds true for integers. In our exercise, we need to verify that the sum of the smallest and largest of three consecutive numbers equals twice the middle one. By applying algebra, we find:
- Sum of smallest and largest: \( n + (n + 2) = 2n + 2 \)
- Twice the middle integer: \( 2(n + 1) = 2n + 2 \)
Sum of Integers
When exploring the sum of integers, we focus on understanding how different operations affect the overall sum. This exercise sheds light on how the choice of consecutive integers impacts their sums and relationships. For three consecutive integers \( n, n + 1, n + 2 \), important observations include:
- The sum of the smallest and largest integers is \( 2n + 2 \).
- Doubling the middle integer \( n + 1 \) results in \( 2n + 2 \) too.
Other exercises in this chapter
Problem 73
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View solution Problem 75
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View solution